Answer:
The magnitude of charge on each sphere is [tex]q=2.50\times 10^{-8}\ C[/tex].
Explanation:
Given that,
Force of repulsion between the charges, F = 22 mN
The distance between spheres, r = 16 mm = 0.016 m
It is mentioned that both the spheres carry equal charges. The force between charges is given by :
[tex]F=\dfrac{kq^2}{r^2}[/tex]
[tex]q=\sqrt{\dfrac{Fr^2}{k}}[/tex]
[tex]q=\sqrt{\dfrac{22\times 10^{-3}\times (0.016)^2}{9\times 10^9}}[/tex]
[tex]q=2.50\times 10^{-8}\ C[/tex]
So, the magnitude of charge on each sphere is [tex]q=2.50\times 10^{-8}\ C[/tex]. Hence, this is the required solution.
Energizer batteries would be classified as which type of product? a. Shopping b. Convenience c. Industrial service d. Unsought e. Specialty
Answer:
i believe it would be classified as A shopping
Which of the following are core capabilities for a response?
a. Cybersecurity; community resilience; and housing
b. Forensics and attribution; physical protective measures; and economic recovery
c. Interdiction and disruption; access control; and threats/hazards identification
d. Critical transportation; situation assessment; and mass care services
Answer:
d. Critical transportation; situation assessment; and mass care services
Explanation:
The correct answer is option d which is Critical transportation: Situation assessment and mass care services are core capabilities for response.
As we know that critical transportation are very important factor which control capability for responses. Due to fast transportation a life can be saved, people can be out of danger in the situation of natural calamity.
A child bounces in a harness suspended from a door frame by three parallel elastic bands. (a) If each elastic band stretches 0.210 m while supporting a 6.80 kg child, what is the force constant for each elastic band?
Answer:
spring constant of the spring will be equal to 317.33 N/m
Explanation:
We have given mass of the child m = 6.80 kg
Spring is stretched by length of 0.210 m . so x = 0.210 m
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Force on the child will be equal to [tex]W=mg[/tex]
This force will be balanced by spring force
And spring force is equal to F = Kx
So kx = mg
[tex]k\times 0.210=6.80\times 9.8[/tex]
k = 317.33 N /m
So spring constant of the spring will be equal to 317.33 N/m
A conical paper cup is 10 cm tall with a radius of 10 cm. The bottom of the cup ispunctured so that the water leaks out at a rate of 16p3 cm³/sec. At what rate is the waterlevel changing when the water level is 3 cm?
Answer:
0.59 cm
Explanation:
height of cup (h) = 10 cm
radius of cup (r) = 10 cm
rate of change of water level (V') = 16π/3 [tex]cm^{3} /sec[/tex]
rate of change of height (h) = 3 cm
the ratio of the height to radius (h:r) = 10:10
h/r = 10/10
h/r = 1
r=h
formula for volume of a volume (v) = [tex]\frac{1}{3}[/tex].π[tex]r^{2}[/tex]h
substituting r=h into the formula above we have
v = [tex]\frac{1}{3}[/tex].π[tex]h^{2}[/tex]. h = [tex]\frac{1}{3}[/tex].π[tex]h^{3}[/tex]
differentiating the above we have
v' = 3([tex]\frac{1}{3}[/tex]π[tex]h^{2}[/tex])h' = π[tex]h^{2}[/tex].h'
rearranging the above we have
h' = v' / (π[tex]h^{2}[/tex])
where
v' = rate of change of water levelh' = rate of change of water levelh = water levelh' = ((16 x π) / 3) ÷ ( π x [tex]3^{2}[/tex])
h' = ((16 x 3.142) / 3) ÷ ( 3.142 x [tex]3^{2}[/tex])
h' = 16.76 / 28.28
h' = 0.59 cm
Which of the following could be a long-term health effect of chemical pesticide use?
A. cancer
B. neurological disorders
C. all of these
The oscilloscope can be thought of as a plotting machine. What is plotted on the a axis? What is plotted on the y axis? If you try to look at a 6 volt signal with the "volts/div" dial set on 0.2 you don't see anything. Why not? Should you turn the dial to 2 volts/div or to 0.02 volts/div to find the signal?
Answer: The oscilloscope is not a plotting machine.
Explanation: The Oscilloscope is not a plotting machine is a device which is use to measure the frequency,period, peak to peak Voltage Vpp or any signal. That is alternating.
So, if you're such you wired your circuit whose output signal you want to measure very well and all connections and settings are done accurately, then you can reduce the volt/div below 0.2. You not seeing any signal at 0.2v/div shows that the amplitude of the signal coming into the Oscilloscope is not up to that.
The x-axis on an oscilloscope represents time, while the y-axis represents voltage. To view a 6 volt signal when the 'volts/div' is set at 0.2, you should adjust it to 2 volts/div or higher, as the current setting is too low to display the signal's amplitude correctly.
Explanation:On an oscilloscope, the horizontal axis (or x-axis) typically represents time, allowing you to see how a signal changes over time. The vertical axis (or y-axis) represents voltage, displaying the amplitude of the signal. If you are attempting to view a 6 volt signal with the "volts/div" setting at 0.2 volts per division, the signal will be off-scale, because each division will represent only 0.2 volts, and a 6 volt signal would require 30 divisions to be fully displayed, which is beyond the scope of a standard oscilloscope screen.
To properly view the 6 volt signal, you should turn the dial to 2 volts/div or higher. This adjustment will ensure that the signal occupies fewer divisions on the screen, making it visible. If you set it to 0.02 volts/div, the signal would be even less visible because the signal would then require 300 divisions, which is impractical to display.
1. refers to all liquid fresh water located above ground.
2. Precipitation that infiltrates Earth's surface and percolates downward becomes .
3. A is a large body of water that has extensive areas of open water, some of which is too deep for photosynthetic life.
4. A meanders across land and structures the landscape.
5. A is the entire land area that supplies a river or stream with water from precipitation.
6. A has water-saturated soil, shallow standing water, and ample vegetation.
Answer:
1- Surface water
2- Groundwater
3- Lake
4- River
5- Watershed/Catchment basin
6- Wetland
Explanation:
Surface water refers to all the water bodies that are present on the surface of the earth. This includes rivers, streams, ponds, lakes. Groundwater refers to the subsurface flow of water. When precipitation occurs, the water percolates downward through the rocks in the region where the rocks are porous and permeable, and this water then becomes groundwater. A lake is usually defined as a large water body that is comprised of nutrient minerals and has extensive areas of open water. The depth of the lakes from one place to another and some are so deep that sunlight cannot penetrate into the deeper zone and the plants cannot carry out the process of photosynthesis. A river is defined as a water body that flows from a region of higher elevation to the region of lower elevation and it flows across the land surface and configures the landscape. Catchment basin is usually defined as a large area in which the precipitation occurs and the waters are accumulated and flow downward and mix up with the river channel and streams. Wetlands are usually defined as an ecosystem that is comprised of shallow standing water, and a sufficient amount of vegetation.The questions are defining concepts involved in the study of Geography, specifically hydrology. These concepts include surface water, groundwater, a lake, a river, a watershed, and a wetland.
Explanation:The series of questions relates to the nature and characteristics of different water bodies and water-related geographical phenomena.
1. Surface water refers to all liquid fresh water located above ground.
2. Precipitation that infiltrates Earth's surface and percolates downward becomes groundwater.
3. A lake is a large body of water that has extensive areas of open water, some of which is too deep for photosynthetic life.
4. A river meanders across land and structures the landscape.
5. A watershed is the entire land area that supplies a river or stream with water from precipitation.
6. A wetland has water-saturated soil, shallow standing water, and ample vegetation.
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Explain the mathematical equation for KVL (The voltage of a circuit through each component in that circuit is proportional to the resistance).
Explanation:
Kirchhoffs Voltage Rule, or KVL, explains that "the overall voltage throughout the circuit in any closed loop network is equal to the sum of all voltage decreases inside the same loop" which is equivalent to zero. In other words, the mathematical sum of all within the loop voltages must be equal to zero.
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point a distance 34.0 m below its starting point at a time 5.00 s after it leaves the thrower's hand. Air resistance may be ignored.
A) What is the initial speed of the egg?
B) How high does it rise above its starting point?
C) What is the magnitude of its velocity at the highest point?
E) What are the magnitude and direction of its acceleration at the highest point?
Part A. The initial speed of the egg is 17.7 m/s.
Part B. The maximum height of the egg is 15.98 m.
Part C. The magnitude of the velocity at its highest point is 0 m/s.
Part E. The magnitude and direction of the acceleration in the upward direction is 9.8 m/s2.
Velocity and AccelerationGiven that the distance traveled by the egg is 34 m in time 5 seconds.
The distance at its initial point will be zero.
Part A
The initial speed of the egg can be calculated by the position equation of the egg.
[tex]x = x_0 + v_0t + \dfrac {1}{2}at^2[/tex]
Where x is the initial position of the egg that is 0 m, x_0 is the final position that is 34 m in time t = 5 s, v_0 is the initial speed and a is the acceleration. Since the egg is thrown vertically, hence the acceleration of the egg is similar to the gravitational acceleration.
[tex]0 = 34 + v\times 5 + \dfrac {1}{2}\times(- 9.8)\times 5^2[/tex]
[tex]v = \dfrac {122.5 - 34}{5}[/tex]
[tex]v = 17.7 \;\rm m/s[/tex]
The initial speed of the egg is 17.7 m/s.
Part BThe maximum height for the egg can be calculated by the equation given below.
[tex]v^2 = v_0^2 + 2gh[/tex]
For the highest point, the final speed v will be zero and the initial speed v_0 is 17.7 m/s. Hence,
[tex]0 = (17.7)^2 + 2\times (-9.8)\times h[/tex]
[tex]19.6 h = 313.29[/tex]
[tex]h = 15.98 \;\rm m[/tex]
The maximum height of the egg will be 15.98 m.
Part CThe velocity of the object thrown at a height will be zero at its highest point. Hence the velocity of the egg will be zero at its highest point.
Velocity [tex]v_h[/tex] = 0 m/s
Part EThe egg is thrown vertically upward, hence its acceleration is similar to the gravitational acceleration.
Acceleration a = 9.8 m/s2
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Ball 1, with a mass of 150 g and traveling at 15 m/s , collides head on with ball 2, which has a mass of 350 g and is initially at rest.A) What are the final velocities of each ball if the collision is perfectly elastic?B) What are the final velocities of each ball if the collision is perfectly inelastic?
Answer: A. Vb1 = -6m/s , Vb2 = 9m/s.
B. Vb1 = 4.5m/s , Vb2 = 4.5m/s
Explanation: A. In a perfectly elastic collision the objects involved moved with a different velocity after collision. Also kenitic energy is conserved. In other to get the different velocity of ball 1 (Vb1) and ball 2 (Vb2) after collision, we apply the following formula
Vb1 = {{m1 - m2}*V1}/{m1 +m2}
Vb2 = {{2m1}*V1}/{m1 + m2}
Where V1 = velocity of ball 1 before collision=15m/s
m1 = mass of ball 1
m2 = mass of ball 2.
Substituting in the above equation:
Vb1 = {{0.15kg - 0.35kg}*15}/{0.15 + 0.35}
= {{-0.2}*15}/0.5
= -3/0.5
= -6m/s
Also,
Vb2 = {{2*0.15kg}*15m/s}/{0.15kg + 0.35kg}
={0.3kg*15m/s}/0.5kg
=4.5/0.5
=9m/s
B. In a perfectly inelastic collision the object involved move with a common velocity after collision.
We have that ,
m1*V1 + m2*v2 = {m1 + m2} V¹
Where V¹ is the final velocity of both balls after a perfectly inelastic collision.
NOTE: v2 here is 0m/s since ball 2 was at rest before collision.
So we have,
0.15kg*15m/s + 0.35kg*0m/s = {0.15kg + 0.35kg}*V¹
2.25 kgm/s = 0.5kg* V¹
Making V¹ subject of formula we have,
V¹ = 2.25kgm per sec/0.5kg
=4.5m/s. vb1 = Vb2 = V¹
NOTE also that the mass of the balls from the question were given in gram hence we converted to kilogram the standard unit for mass by dividing by 1000.
Answer:
For both ball 1 and ball 2, the change in velocity is less in an inelastic collision.
Explanation:
a short simple answer
Particle 1 carrying -4.0 μC of charge is fixed at the origin of an xy coordinate system, particle 2 carrying +8.0 μC of charge is located on the x axis at x = 4.0 m , and particle 3, identical to particle 2, is located on the x axis at x = -4.0 m . What is the vector sum of the electric forces exerted on particle 3? Determine the x and y components of the vector sum.
To find the vector sum of the electric forces exerted on particle 3, calculate the electric forces exerted by particle 1 and particle 2 and add them as vectors. Use Coulomb's law to find the electric forces. Add the x and y components of the forces to get the vector sum.
Explanation:To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric forces exerted on particle 3 by particle 1 and particle 2 and then add them together as vectors. The electric force exerted on particle 3 by particle 1 can be found using Coulomb's law, which states that electric force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Calculate the electric force exerted on particle 3 by particle 1 using Coulomb's law: F1 = (k * q1 * q3) / r13^2Next, calculate the electric force exerted on particle 3 by particle 2 using Coulomb's law: F2 = (k * q2 * q3) / r23^2Add the x-components and y-components of the electric forces to get the vector sum: Fx = F1x + F2x and Fy = F1y + F2yBy substituting the given values into the equations, you can calculate the x and y components of the vector sum of the electric forces exerted on particle 3.
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Final answer:
To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric force between particle 3 and both particle 1 and particle 2. The electric force between two charges is given by Coulomb's Law. By plugging in the charges and distances, we can calculate the electric forces and find the vector sum.
Explanation:
To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric force between particle 3 and both particle 1 and particle 2. The electric force between two charges is given by Coulomb's Law:
F = k * (|q1| * |q2|) / r^2
Where F is the electric force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges. Since particle 1 is fixed at the origin, the distance between particle 3 and particle 1 is |-4.0 m| = 4.0 m. Similarly, the distance between particle 3 and particle 2 is |4.0 m - (-4.0 m)| = 8.0 m. Plugging in the values, we can calculate the electric forces between particle 3 and both particle 1 and particle 2.
Let's calculate:
F3-1 = (9 * 10^9 N.m^2/C^2) * (|-4.0 μC| * |8.0 μC|) / (4.0 m)^2
F3-2 = (9 * 10^9 N.m^2/C^2) * (|-4.0 μC| * |8.0 μC|) / (8.0 m)^2
Now, we can find the vector sum of the electric forces by adding the x-components and the y-components of both forces.
A boy and his dog are out for a morning excursion to the river, whichis located 4.0 km away. The boy walks briskly at 2.0 m/s in a straight line. The dog isunleashed and runs back and forth at 4.5 m/s between the boy and the river, until bothreach the river. What is the distance run by the dog?
Answer:
9 Km
Explanation:
given,
distance of the river = 4 Km = 4000 m
speed of the boy = 2 m/s
speed of the dog back and forth = 4.5 m/s
distance ran by the dog = ?
time taken by the boy to cover the distance
we know,
distance = speed x time
[tex]t = \dfrac{4000}{2}[/tex]
t = 2000 s.
now, distance travel by the dog.
d= 4.5 x 2000
d = 9000 m
d = 9 Km
distance covered by the dog is equal to 9 Km.
A ball that is thrown upwards from the ground will eventually reach its highest point and fall back to the ground. Which of the following quantities will be constant over the course of this up and down motion?
a. The ball's position.b. The ball's speed.c. The ball's acceleration.d. Nonsense! None of these are constant.
Answer:
option (c)
Explanation:
When an object thrown upwards, the value of acceleration acting on the object is acceleration due to gravity which is always acting towards the earth.
As it falls downwards, the acceleration is again equal to the acceleration due to gravity.
So, the ball's acceleration is constant.
Final answer:
The acceleration of the ball remains constant throughout its up and down motion since it is solely influenced by gravity, which provides an acceleration of approximately 9.81 m/s² downward
Explanation:
When a ball is thrown upwards from the ground and then falls back down, the acceleration of the ball is what remains constant throughout its motion. This is due to gravity, which acts downward on the ball with an acceleration denoted as "g". While the ball's position and speed are changing throughout the motion, its acceleration due to gravity remains constant at approximately 9.81 m/s2 (on Earth), regardless of its state of motion. Therefore, the quantity that remains constant over the course of this up and down motion is the ball's acceleration.
One drawback of dams is that they can flood land upstream from the dam and reduce water flow downstream from the dam. Question 2 options: True False
Answer:
True
Explanation:
It can cause flooding and destruction of habitat because of dammed rivers create large reservoirs upstream which can spill out to the surrounding during heavy rainfall causing flooding and destruction of natural habitat.
Which of the following refers to applications and technologies that are used to gather, provide access to, and analyze data and information to support decision-making efforts?
a) data
b) information
c) information technology
d) business intelligence
Answer:
d) business intelligence
Explanation:
Business intelligence refers to applications and technologies that are used to gather, provide access to, and analyze data and information to support decision-making efforts. Business Intelligence uses technologies for the data analysis of business information to make strategic decision for enterprises. Common functions of business intelligence technologies include reporting, online analytical processing, analytics, data mining, process mining, complex event processing, business performance management, benchmarking, text mining, predictive analytics and prescriptive analytics.
The technologies that support decision-making by collecting and analyzing data are known as business intelligence. Transforming data into information is achieved through asking relevant questions and using information systems. Information technology advancements have greatly improved this process.
Explanation:The application and technologies used to gather, provide access to, and analyze data and information to support decision-making efforts are referred to as business intelligence. The process of transforming data into information involves collecting raw data, which are simply facts, measurements, or characteristics, and then analyzing these data to gain valuable insights or knowledge. Clearly, to obtain information, one must ask the right questions and use information systems to process the raw data. Due to advancements in information technology, such as computerized databases and database management systems, data can be stored, retrieved, manipulated, and analyzed more efficiently than ever, contributing significantly to the Information Age we live in today.
A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (mproton = 1.67 × 10-27 kg, e = 1.60 × 10-19 C)
The acceleration of the proton is 6.7×10¹⁰ m/s² in the direction of the electric field.
Electrostatic force:
The force on a charged particle due to an electric field is given by:
F = qE
where q is the charge = 1.6×10⁻¹⁹C
and E is the electric field = 700N/C
Also, from Newton's laws of motion;
F = ma
where m is mass = 1.67×10⁻²⁷kg and a is acceleration
ma = qE
a = qE/m
[tex]a=\frac{1.6\times10^{-19}\times700}{1.67\times10^{-27}}\;m/s^2\\\\a=6.7\times10^{10}\;m/s^2[/tex]towards the direction of the electric field.
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A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting? (Assume that up is the positive direction.) a. +2.93 times 10^5 J b. 0J c. Answer is not obtainable, because insufficient information about the skydiver's speed is given. d. -2.93 times 10^5 J
Answer: Workdone293.02KJ
Explanation: The equation to use to calculate Workdone = Change in KE + Change in PE
Assuming velocity is constant,KE becomes 0
Workdone= Change in PE=mg
W=92×9.8×325=293.02KJ
If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the gas?
Answer:
Explanation:
According to Boyle's law for constant temperature of gas Pressure is inversely proportional to the volume of gas.
[tex]PV=nRT[/tex]
[tex]PV=constant[/tex]
[tex]P\propto \frac{1}{V}[/tex]
if Pressure is tripled then
[tex]P\times V_1=3P\times V_2[/tex]
[tex]V_2=\frac{V_1}{3}[/tex]
Volume becomes one-third of original volume
Final answer:
According to Boyle's Law, tripling the pressure on a gas at constant temperature will reduce its volume to one third of the original volume.
Explanation:
The question is based on Boyle's Law which states that for a given mass of an ideal gas at constant temperature, the volume of the gas is inversely proportional to its pressure. Therefore, if the pressure acting on a gas is tripled (pressure is proportional to 3), the volume will be reduced to one third of its original value (volume is proportional to 1/3), assuming that the temperature and the amount of gas remain constant.
How did new technology such as the telescope and new theories such as Pascal's Law laid the foundation of the Scientific Revolution? *
Answer:
"Scientists used them to create new theories"
Explanation:
The Scientific Revolution was a sequence of actions that manifest the development of contemporary science through the early contemporary period, when advances in mathematics, physics, astronomy, biology and chemistry altered the opinions of civilization around nature. The scientific revolution denotes to the quick developments in European scientific, mathematical, and political assumed, grounded on a new philosophy of experimentation and a belief in growth that defined Europe in the 16th and 17th centuries.
Final answer:
The telescope and Pascal's Law played a significant role in laying the foundation of the Scientific Revolution. The telescope allowed for groundbreaking observations of the solar system and the universe, while Pascal's Law led to advancements in fluid mechanics and hydraulic engineering.
Explanation:
The new technology, such as the telescope, and new theories, such as Pascal's Law, played a significant role in laying the foundation of the Scientific Revolution.
Firstly, the invention of the telescope in 1608 allowed astronomers like Galileo Galilei to make groundbreaking observations of the solar system and the universe, leading to the development of new theories and understandings of celestial bodies.
Secondly, Pascal's Law, formulated by Blaise Pascal, established the principle that pressure exerted on a fluid is transmitted uniformly in all directions, which laid the foundation for the field of fluid mechanics and led to advancements in hydraulic engineering and other areas.
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator and a 70 kg person that is 0.5 meters from the refrigerator.
Answer:
3.735×10⁻⁶ N
Explanation:
From newton' s law of universal gravitation,
F = Gmm'/r² .............................. Equation 1
Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.
Given: m = 70 kg, m' = 200 kg, r = 0.5 m
Constant: G = 6.67×10⁻¹¹ Nm²/kg².
F = (6.67×10⁻¹¹×70×200)/0.5²
F = 93380×10⁻¹¹/0.25
F = 373520×10⁻¹¹
F = 3.735×10⁻⁶ N
Hence the force between the person and the refrigerator = 3.735×10⁻⁶ N
You are given two infinite, parallel wires each carrying current I. The wires are separated by a distance d, and the current in the two wires is flowing in the same direction. This problem concerns the force per unit length between the wires.
What is the force per unit length F/L between the two wires?
Express your answer in terms of I, d, and constants such as μ0 and π.
Answer:
[tex]\dfrac{F}{L}=\dfrac{\mu_oI^2}{2\pi d}[/tex]
Explanation:
If the current flowing in two wires is I and they are separated by a distance of d. We know that the magnetic field due to a wire is given by :
[tex]B=\dfrac{\mu_oI}{2\pi d}[/tex]
Where
d is the separation between wires
The magnetic force between the wires is given by :
[tex]F=BIL[/tex]
I is the current in wire
L is the length of the wires
[tex]F=\dfrac{\mu_oI^2L}{2\pi d}[/tex]
The magnetic force per unit length is given by :
[tex]\dfrac{F}{L}=\dfrac{\mu_oI^2}{2\pi d}[/tex]
So, the force per unit length F/L between the two wires is [tex]\dfrac{\mu_oI^2}{2\pi d}[/tex]. Hence, this is the required solution.
How does artificial transmutation differ from nuclear decay
Explanation:
In both cases the conversion of one chemical element into another is obtained, modifying the number of protons in the nucleus. The difference is that artificial transmutation needs an outside cause, since an outside particle reacts with the nucleus, while in nuclear decay not cause outside is needed.
In a study, the data you collect is Habits on a Always/Sometimes/Never scale. What is the level of measurement? nominal ordinal interval ratio
Answer:
It's an ORDINAL Level of measurement.
The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal.
Explanation:The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal. In an ordinal scale, data can be categorized and ordered, but the intervals between data points may not necessarily be equal or meaningful. In this case, the habit categories would have a natural order (Always, Sometimes, Never), but the difference between Always and Sometimes may not be the same as the difference between Sometimes and Never.
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Suppose wave pulses in an aquarium are produced by a mechanical motor that moves a bob up and down at the surface. The setup uses a 10-W motor and has a period of 1.9 s between bobs. How much kinetic energy is in each pulse.
Answer:
kinetic energy in each pulse = 9.5J
Explanation:
The concept used here is that of work, energy and power.Power P = Work /TimeWork = energy in this caseE = Power x time = Ptbut Power = 10W and t = 1.9sEnergy E = 10W x 1.9s = 19JConventionally, overall energy = kinetic + potential
Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19
energy = 9.5J
The kinetic energy is in each pulse is 19J.
The Power delivered is defined at the rate of work done, if P be the power, W be the work done and t be the time for which the work is done then:
P = W/t
W = Pt
given that P = 10w and t = 1.9s
W = 10×1.9 J
W = 19J
Now, the work done is equal to the change in Kinetic energy (KE)
ΔKE = W = 19J
Hence, the kinetic energy is 19J.
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If you weigh 675 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 21.0 km?
Answer:
8.29 * 10^{13} N
Explanation:
Weigth is the force of gravity a body of mass experiences due to the gravity of another mass.
Force=mass*acceleration (to calculate the mass of the object);
675=m*9.8; Mass = 68.88 kg
Force= [tex]\frac{GMm}{r^{2} }[/tex]; M is the mass of the bigger object, m is the mass of the smaller object, r is the seperation in between (radius in this case) and G is the Gravitational constant.
Mass of the sun = 1.989 × 10^30 kg
G = 6.67 × 10-11 m3 kg-1 s-2
mass of the object = 68.88 kg;
Applying the formula:
Force=[tex]\frac{(6.67 * 10^{-11} ) * (68.88) * (1.989 * 10^{30} )}{(((21 *10^{3} ))/2)^{2} }[/tex]
Force = 8.29 * 10^{13} N
The weight on the surface of a neutron star that has the same mass as our Sun and a diameter of 21.0 km will be 8.29 × 10¹³ N
Gravitational force:Given that the weight of the person on the earth is 675N.
mg = 675N
where m is the mass of the person.
m = 675/g
m = 675/9.8
m = 68.87 kg
The gravitational force on the surface of a celestial body is given by:
F = GMm/R²
where G is the gravitational constant
M is the mass of the body
m is the mass of the person
and, R is the radius of the body
F = (6.67 × 10⁻¹¹)( 2 × 10³⁰)(68.87) / (21/2 × 10³)²
F = 8.29 × 10¹³ N
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A floating ball normally weighs 5.5 N. The acceleration of gravity is 9.8 m/s 2 . What is the size of the buoyant force that acts on it?
Answer:
5.5 N
Explanation:
Weigh of floating ball=5.5 N
Acceleration due to gravity=9.8 [tex]m/s^2[/tex]
We have to find the size of the buoyant force that acts on it.
We know that
Buoyant force is that force which act in upward direction and exert by fluid and opposes the weight of an immersed object.
Therefore,
Buoyant force=Weight of ball
Buoyant force=5.5 N
Hence, the size of buoyant force acts on the ball=5.5 N
Given the ball's weight of 5.5 N, the buoyant force is also 5.5 N.
To determine the buoyant force acting on a floating ball, we can use the principles of buoyancy and the given information about the ball's weight. The ball's weight in air is 5.5 N, and we know the acceleration due to gravity (g) is 9.8 m/s².
For a floating object, the buoyant force (Fb) is equal to the weight of the object when it is floating. Therefore, since the ball is floating, the buoyant force must equal the weight of the ball:
Buoyant force Fb = Weight of the ball
Given that the weight of the ball is 5.5 N, the buoyant force acting on the ball is:
Fb = 5.5 N
This force is what keeps the ball afloat in the fluid.
A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original direction of the cue ball and 2.0 N·s perpendicular to that direction. What is the momentum of the cue ball after the collision?
Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,P₁ = 9 N.s
momentum of nine ball in x- direction, P₂ = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
P₁ + p = x + P₂
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 = x + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'₁ + p = y + P'₂
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .
[tex]P = \sqrt{x^2+y^2}[/tex]
[tex]P = \sqrt{7^2+(-2)^2}[/tex]
P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
The momentum of the cue ball after the collision is calculated to be 6.2 N·s in based on the conservation of momentum.
Explanation:This physics problem involves the principle of conservation of momentum. Initially, the cue ball has a momentum of 9.0 N·s. After the collision, the nine-ball has a momentum of 2.0 N·s in the original direction and another 2.0 N·s in a perpendicular direction. To find the momentum of the cue ball after the collision, we need to take into account that the total momentum of the system is conserved before and after the collision.
In this case, the total initial momentum is the momentum of the cue ball, which is 9.0 N·s. After the collision, the total momentum should still be 9.0 N·s. The sum of the momenta of the nine-ball (which is the square root of the sum of the squares of the two momentum components, due to the Pythagorean theorem) is 2.8 N·s. Therefore, the momentum of the cue ball after the collision will be the total initial momentum minus the momentum of the nine-ball after the collision, which gives us 9.0 N·s - 2.8 N·s = 6.2 N·s.
To solve this problem, we can use the principle of conservation of momentum. Before the collision, we have the momentum of the cue ball which is 9.0 N·s. After the collision, we have the momentum of the nine-ball which is 2.0 N·s in the original direction of the cue ball and 2.0 N·s perpendicular to that direction. Since momentum is conserved, the total momentum before the collision is equal to the total momentum after the collision. Therefore, the momentum of the cue ball after the collision is the difference between the total momentum before the collision and the momentum of the nine-ball after the collision.
To calculate the momentum of the cue ball after the collision, we subtract the momenta of the nine-ball from the initial momentum of the cue ball. The momentum of the cue ball after the collision is therefore 9.0 N·s - (2.0 N·s + 2.0 N·s) = 5.0 N·s in the original direction of the cue ball.
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If you very lightly touch a guitar string at its midpoint, you can hear a tone that is one octave above the fundamental for that string.Explain?
Answer:
Change, increase in note frequency of the sound that comes as a result of the reduction in the vibrating length (wavelength) when the string movement is slightly restricted at its midpoint
Explanation:
When the midpoint of a vibrating guitar string is lightly touched it reduces the wavelength of the guitar string sound, halving it and such increases the the frequency inversely by a factor of 2
The relationship
f = vw/λ, for sound wave where vw is the speed of sound, frequency, f and λ is the wavelength
Frequency varies inversely with wavelength
An Octave
is the frequency vibration of sound-wave twice that of its lower note
A least squares regression line was created to predict the Exam 3 score of STA 2023 students based on their Exam 1 score. The study found that the value of R-squared was 28.8% and the least squares regression line was yhat=50.57+0.4845x. What is the correlation coefficient, r?
1.0.54
2.-0.54
3.5.37
4.-5.37
5.0.08
6.-0.08
Answer: Option (1) is the correct answer.
Explanation:
Formula to calculate correlation coefficient is as follows.
Correlation coefficient = [tex]\sqrt{R^{2}}[/tex]
As the slope for given equation is positive so, it means that the correlation will also be positive in nature.
Therefore, we will calculate the value of correlation coefficient as follows.
Correlation coefficient = [tex]\sqrt{R^{2}}[/tex]
= [tex]\sqrt{(0.288)^{2}}[/tex]
= 0.54
Thus, we can conclude that the correlation coefficient, r is 0.54.
A mass ofm= 0.7 kg hung vertically fromthis spring stretches the spring 0.1 m.The acceleration of gravity is 9.8 m/s2.Calculate the value of the force constantkfor the spring?
Answer:
Spring constant of the spring will be 68.6 N/m
Explanation:
It is given mass which is vertically hung m = 6.80 kg
Spring is stretched by length of 0.1 m , so x = 0.210 m
Acceleration due to gravity will be equal to [tex]g=9.8m/sec^2[/tex]
Force on the mass which is vertically hung will be equal to mg
This force will be balanced by spring force acting on the mass
And spring force is equal to F = Kx
So kx = mg
[tex]k\times 0.1=0.7\times 9.8[/tex]
k = 68.6 N /m
So spring constant of the spring will be equal to 68.6 N/m