Answers
Answer:
[tex]\large\boxed{551.5\%=5\dfrac{103}{200}}[/tex]
[tex]\large\boxed{0.5\%=\dfrac{1}{200}}[/tex]
[tex]\large\boxed{350\%=3\dfrac{1}{2}}[/tex]
Step-by-step explanation:
[tex]p\%=\dfrac{p}{100}\\\\27)\ 551.5\%=\dfrac{551.5}{100}=\dfrac{551.5\cdot10}{100\cdot10}=\dfrac{5515}{1000}=\dfrac{5515:5}{1000:5}=\dfrac{1103}{200}=5\dfrac{103}{200}\\\\29)\ 0.5\%=\dfrac{0.5}{100}=\dfrac{0.5\cdot10}{100\cdot10}=\dfrac{5}{1000}=\dfrac{5:5}{1000:5}=\dfrac{1}{200}\\\\31)\ 350\%=\dfrac{350}{100}=\dfrac{35}{10}=\dfrac{35:5}{10:5}=\dfrac{7}{2}=3\dfrac{1}{2}[/tex]
Related Questions
which is the solution set of the compound inequality 3.5x - 10 > -3 and 8x - 9 < 39
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The weights of steers in a herd are distributed normally. the standard deviation is 200 lbs and the mean steer weight is 1300 lbs. find the probability that the weight of a randomly selected steer is between 1000 and 1437 lbs. round your answer to four decimal places.
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You have deposited $800 in a savings account, which pays three percent interest compounded quarterly. Find the amount in the account for 5 years
Answers
You take $800 and multiply it by 0.0075 which is 1/4 of 3% since there are 4 quarters per year. Every time you multiply it you add the previous number and you have to do this 20 times since there are 20 quarters in 5 years. For example, 800 x 0.0075 = 6 + 800 = 806 x 0.0075 = 6.045 + 806 = 812.045 x 0.0075 = 6.0903375 + 812.045 = 818.1353375 and you just keep doing thing until you reach your total amount of quarters. Then you just round your decimal point to the hundredth place.
Janet earns $300 per week plus a commission of 10% on all sales that she makes. Write a formula for E, Janet's weekly earnings, in term of s, her sales for the week. Then solve your firmula for s
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0.1 x 300
E= 0.1(s) (300)
s being the sales that she makes
s = (E - 300) / 0.1
"15. describe the three data fragmentation strategies. give some examples of each."
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2. Vertical fragmentation – the table is distributed into rational groups of attributes (columns). Each fragment covers a unique columns and is stored at a dissimilar position. The content in the fragment is attained by using the “PROJECT” statement.
3. Mixed fragmentation –This approach is the mix of horizontal and vertical strategies. In other words, each row fragment may be a blend of groups of attributes.
Find 1/4+13/20
. Write your answer as a fraction in simplest form.
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A fraction is a way to describe a part of a whole. The sum of the two of the given fractions is equal to 9/10.
What is a Fraction?A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.
The given fractions can be added as shown below.
(1/4) + (13/20)
Taking the LCM of the denominator which is equal to 20,
= (1×5 / 4×5) + (13/20)
= (5/20) + (13/20)
= (5 + 13)/20
= 18/20
Divide both the numerator and the denominator by 2,
= 9/10
Hence, the sum of the two of the given fractions is equal to 9/10.
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The price of an item selling at 150% of its $63 value is
Answers
:D
Answer:
94.50
Step-by-step explanation:
i used a calculator
Which doubles fact would you use to find 6+7
A. 2+2=4
B. 4+4=8
C. 6+6=12
D. 8+8=16
Answers
The population and areas of four states are shown.
Answers
The answer is B) The state with the second lowest population has the lowest population density.
What is 800+60+4 in standard form
Answers
Just add the numbers.
When certain kinds of chemicals are combined, the rate at which the new compound is formed is modeled by the autonomous differential equation dX/dt = k(a-X)(B-X) where k > 0 is a constant of proportionality and B > a > 0. Here X(t) denotes the number of grams of the new compound formed in time t. (a) Use a phase portrait of the differential equation to predict the behavior of X(t) as t -> infinity. (b) Consider the case when a = B. Use a phase portrait of the differential equation to predict the behavior of X(t) as t -> infinity when X(0) < a. When X(0) > a. (c) Verify that an explicit solution of the DE in the case when k=1 and a=B is X(t)=a-1/(t+c). Find a solution that satisfies X(0) = a/2. Then find a solution that satisfies X(0)=2a. Graph these two solutions. Does the behavior of the solutions as t->infinity agree with your answers to part (b)?
Answers
To predict the behavior of the autonomous differential equation as t -> infinity, analyze the phase portrait of the system. The behavior of X(t) as t approaches infinity depends on the initial conditions. Verify the explicit solution of the DE when k=1 and a=B. Graph the solutions and observe their behavior as t-> infinity.
Explanation:To predict the behavior of the autonomous differential equation dX/dt = k(a-X)(B-X) as t -> infinity, we can analyze the phase portrait of the system. The phase portrait will show the equilibrium points and the direction of the solutions as time increases. In this case, there will be two equilibrium points, one at X = a and one at X = B, assuming a < B. The behavior of X(t) as t approaches infinity depends on the initial conditions. If X(0) < a, the solution will approach X = a, and if X(0) > a, the solution will approach X = B.
To verify the explicit solution of the differential equation when k=1 and a=B, we substitute these values into the equation: X(t) = a - 1/(t+c). For the solution that satisfies X(0) = a/2, we substitute t=0 and X(0) = a/2 into the equation and solve for c. Similarly, for the solution that satisfies X(0) = 2a, we substitute t=0 and X(0) = 2a into the equation and solve for c. We can then graph these two solutions and observe that as t approaches infinity, X(t) approaches a for both solutions, which confirms our analysis from part (b).
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Kersha has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. Her office job pays her $12.00 per hour. Her cashier job pays her $8.25 per hour. In one week, Kersha worked 55 hours. She earned a total of $585.
How many hours did Kersha work in each job?
a.) Office clerk: 35 hours; cashier: 20 hours
b.) Office clerk: 31 hours; cashier: 24 hours
c.) Office clerk: 20 hours; cashier: 35 hours
d.) Office clerk: 28 hours; cashier: 27 hours
Answers
Let y = hours worked as a cashier ($8.25 per hour).
She worked 55 hours, therefore
x + y = 55 (1)
She earned $585, therefore
12x + 8.25y = 585 (2)
From (1), obtain
y = 55 - x (3)
Substitute (3) into (2).
12x + 8.25(55 - x) = 585
12x + 453.75 - 8.25x = 585
3.75x = 131.25
x = 35
y = 55 - x = 55 - 35 = 20
Answer: a) Office clerk: 35 hours; cashier: 20 hours.
the ratio of the sides of two squares is 3:1. what is the ratio of their perimeters?
Answers
The ratio of the perimeters of two squares with a side ratio of 3:1 is 3:1.
Explanation:The ratio of the sides of two squares is 3:1. To find the ratio of their perimeters, we need to compare the lengths of their sides. Let's assume the length of the larger square is 3x and the length of the smaller square is x. The perimeter of the larger square is 4 times the length of its side, so it is 4 × 3x = 12x. The perimeter of the smaller square is 4 times the length of its side, so it is 4 × x = 4x. Therefore, the ratio of their perimeters is 12x:4x. Simplifying this ratio gives us 3:1.
Is the difference of 1.48-0.25 less than or greater than one explain
Answers
1 < 1.23
find the discriminant & describe the nature of the roots 2x2=3x+5
Answers
A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
a. is the sampling distribution of the sample mean with n = 16 and n = 36 normally distributed? yes, both the sample means will have a normal distribution. no, both the sample means will not have a normal distribution. no, only the sample mean with n = 16 will have a normal distribution. no, only the sample mean with n = 36 will have a normal distribution.
b. can you use the standard normal distribution to calculate the probability that the sample mean falls between 66 and 68 for both sample sizes? yes, for both the sample sizes, standard normal distribution could be used. no, for both the sample sizes, standard normal distribution could not be used. no, only for the sample size with n = 16, standard normal distribution could be used. no, only for the sample size with n = 36, standard normal distribution could be used.
c. calculate the probability that the sample mean falls between 66 and 68 for n = 36. (round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answer to 4 decimal places.)
Answers
The sampling distributions of both sample sizes are normally distributed due to the Central Limit Theorem. The standard normal distribution can be used to calculate the probability for both sample sizes. The probability that the sample mean falls in a particular range for a given sample size can be found by calculating the z-scores for that range and looking at the area under the standard normal curve.
Explanation:The subject of this question relates to the concepts of sampling distribution, normal distribution, and probability in the field of statistics. To answer this:
a. The sampling distribution of the sample means for both n = 16 and n = 36 will be normally distributed. According to the Central Limit Theorem, if the sample size is large enough (generally n > 30), the sampling distribution of the mean tends to be normal regardless of the shape of the population distribution.
b. Yes, a standard normal distribution could be used for both sample sizes to calculate the probability that the sample mean falls between 66 and 68. Since we are dealing with standard normal distribution, we first need to convert the samples into z-scores.
c. To calculate the probability for n = 36, we need to calculate the z-score for both 66 and 68 using the formula z = (X - μ) / (σ / sqrt(n)), where X is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size. The probability that the sample mean falls between 66 and 68 for n = 36 is then simply the area under the standard normal curve bounded by these two z-scores.
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What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to finish.
1.Construct a line perpendicular to line m through point F. Label a point on this line as point G.
2.Use a straightedge to draw line m and label a point on the line as point F.
3.Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK .
4.Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
5.With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
6.Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.
Answers
1. Use a straightedge to draw line m and label a point on the line as point F
2. Construct a line perpendicular to line m through point F. Label a point on this line as point G.
3. With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
4. Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.
5. Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.
6. Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
These are the right answers
Calculate the quotient and remainder of –111 divided by 11. (quotient, remainder)
Answers
Final answer:
The quotient of –111 divided by 11 is –10, and the remainder is –1. We obtain this by dividing –111 by 11 and then finding the difference between the product of the quotient and 11 and –111.
Explanation:
To calculate the quotient and remainder of –111 divided by 11, we perform the division as follows:
Divide –111 by 11 to find the quotient. Since 111 is divisible by 11, the quotient is –10.To find the remainder, we calculate –10 multiplied by 11, which is –110, and subtract it from –111. The difference is –1, so the remainder is –1.Therefore, the quotient is –10 and the remainder is –1.
The rate in which a function increases or decreases between its points are called the slope, or the rate of change. For any function, the rate of change is calculated by the slope formula. Slope formula: where m = slope (a, f(a)) and (b, f(b)) are two points on the function. Here is an example: For the function, f(x) = 2x - 1, calculate the rate of change between the points, (-1, f(-1)) and (4, f(4)). Let(-1,f(-1))=(a,f(a)) and (4,f(4))=(b,f(b)). Use the given functin, f(x)=2x-1, to complete the points. For (-1, f(-1): For (4,f(4)) f(x)=2x-1 f(x)=2x-1 f(-1)=2(-1)-1 f(4)=2(4)-1 f(-1)=-3 f(4)=7 (-1,f(-1))=(-1,-3) (4,f(4))=(4,7) Next, calculate the slope for the function, using the points (-1, -3) and (4, 7). For the formula, let(-1,-3) =(a,f(a)) and (4,7) = (b,f(b)): The slope of the function, f(x)=2x-1, between the points (-1, -3) and (4,7) is 2. For each function, use the slope formula to calculate the rate of change between the points. In your final answer, include all of your calculations. f(x): (a, f(a) and (b,f(b) 1.) f(x)=x - 3 (0,f(0)) and (6,f(6)) 2.) f(x) = -x (-4,f(-4)) and(2,f(2)) 3.) f(x)=x2 (-2,f(-2)) and (0,f(0)) 4.) f(x)=x3 (-1,f(-1)) and (1,f(1)) 5.) f(x)=2x (0,f(0)) and (4,f(4))
Answers
Find the average rate of change of f(x) = x^2 from x = -2 to x = 0:
f(0) - f(-2) (0)^2 - (-2)^2) 0-4
arc = ------------------ = ---------------------- = ---------- = -2 (answer)
0-(-2) 2 2
1. f(x)=1/2x-3 f(x)=1/2x-3
f(0)=1/2(0)-3 f(6)=1/2(6)-3
f(0)=-3 f(6)=0
m=f(b) - f(a)/b - a = 0- (-3)/6 - 0 = 3/6 = 1/2
2. f(x) = -x f(x) = -x
f(-4) = -(-4) f(2) = -2
f(-4) = 4 f(2) = -2
m=f(b) - f(a)/b - a = -2 - 4/2 - (-4) = -6/6 = -1
3. f(x) = x^2 f(x) = x^2
f(-2) = -2^2 f(0) = 0^2
f(-2) = -4 f(0) = 0
m=f(b) - f(a)/b - a = 0 - (-2)/0 - (-2) = 2/2 = 1
4. f(x) = x^3 f(x) = x^3
f(-1) = -1^3 f(1) = 1^3
f(-1) = -1 f(1) = 1
m=f(b) - f(a)/b - a = 1 - (-1)/1 - (-1) = 2/2 = 1
5. f(x) = 2^x f(x) = 2^x
f(0) = 2^0 f(4) = 2^4
f(0) = 1 f(4) = 16
m=f(b) -f(a)/b - a = 4 - 0/ 4 - 0 = 4/4 = 1
i hope this is right, have a good day
If 9:7 is the ratio, there are here 116 more boys than girls how many total students are there
Answers
[tex]\bf \cfrac{boys}{girls}\qquad 9:7\qquad \cfrac{9}{7}\implies \cfrac{9}{7}=\cfrac{\stackrel{boys}{g+116}}{\stackrel{girls}{g}}\implies 9g=7g+812 \\\\\\ 2g=812\implies g=\cfrac{812}{2}\implies g=\stackrel{girls}{406}[/tex]
what's the total class? well is g + b or g + ( g + 116).
12x−3y=, when x=−1/4 and y=3
Answers
(answer)
12(-1/4)-3(3)
-3-9
-12
Sam’s parents agreed to pay 25 percent of the cost of a new bike if Sam paid the rest.If Sam’s parents paid $65, what was the price of Sam’s new bike?
Answers
You have a 5" by 7" photo that you would like to have enlarged to fit an 8" by 10" frame. Would the two photographs be similar? Explain
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5/8 = 0.625
7/10 = 0.7
the 2 ratios are different so it would not be similar
Given:
A = O, WA = NO, AS = OT.
SSS
SAS
ASA
AAS
Answers
Use multiplication and distributive property to find the quotient of 75 divided by 3
Answers
The amount of cholesterol in a person's body produced by their liver and other cells is proposed to be normally distributed with mean 75% and standard deviation 0.5%. the probability that a person produces more than 76.7% of the cholesterol in their body is
Answers
After standardizing the given value using a Z-score, it is found that the probability of a person producing more than 76.7% of the cholesterol in their body is essentially zero.
Explanation:The question is asking for the probability that a person produces more than 76.7% of the cholesterol in their body, given this production is normally distributed with a mean of 75% and a standard deviation of 0.5%. To calculate this, we can utilize Z-score which standardizes the deviation of a value from the mean, considering the standard deviation.
The Z-score for the value 76.7% is calculated as follows: (76.7 - 75) / 0.5 = 3.4.
Using the standard normal distribution, the probability of a Z-score being above 3.4 is extremely low, it's practically zero. Therefore, the probability that a person produces more than 76.7% of the cholesterol in their body is essentially zero.
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A trial has markers every 1/8 mile. Jody starts at the 2 1/4-mile marker, hikes to the 4 3/8-mile marker, and then hikes back to the 1 1/2 mile marker. Did Jody hike more than 4 miles? Explain.
Answers
4 3/8 - 2 2/8 = 2 1/8 miles.
2) determine how many miles she hikes, leaving the 4 3/8 mile marker and arriving at the 1 1/2 mile marker. Again, subtract:
4 3/8 - 1 4/8 = 3 11/8 - 1 4/8 = 2 7/8 miles.
Adding together 2 1/8 miles and 2 7/8 miles, we get 5 miles.
Did Jody hike more than 4 miles? You decide.
The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges $3157 to rent trucks plus an additional fee of $50.25 for each ton of sugar. The second company does not charge to rent trucks but charges $275.75 for each ton of sugar.
For what amount of sugar do the two companies charge the same?
What is the cost when the two companies charge the same?
Answers
First company:
The cost is $3157 truck rental plus $50.25 per ton of sugar.
Total cost = 3157 + 50.25x dollars
Second company:
There is no charge for truck rental, but it costs $275.75 per ton of sugar.
The total cost is
275.75x
When the two costs are the same, then
275.75x = 3157 +50.25x
225.5x = 3157
x = 14 tons
The total cost is 275.75*14 = $3,860.50
Answer:
14 tons
$3,860.50
Both companies will charge the same $3,860.50 for 14 tons of sugar.
CalculusGiven that The Sugar Sweet Company will choose from two companies to transport its sugar to market, and the first company charges $3157 to rent trucks plus an additional fee of $50.25 for each ton of sugar, while the second company does not charge to rent trucks but charges $275.75 for each ton of sugar, to determine for what amount of sugar do the two companies charge the same, and what is the cost when the two companies charge the same, the following calculation must be made:
Company 1 =
3157 + 50.25 x 10 = 3157 + 502.5 = 3659.503157 + 50.25 x 20 = 3157 + 1005 = 41623157 + 50.25 x 15 = 3157 + 753.75 = 3910.753157 + 50.25 x 14 = 3157 + 703.50 = 3860.50Company 2 =
275.75 x 10 = 2757.50275.75 x 20 = 5515275.75 x 15 = 4136.25275.75 x 14 = 3860.50Therefore, both companies will charge the same $3,860.50 for 14 tons of sugar.
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Use the chain rule to find ∂z/∂s and ∂z/∂t. z = sin(θ) cos(ϕ), θ = st5, ϕ = s7t
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[tex]\theta=st^5[/tex]
[tex]\phi=s^7t[/tex]
[tex]\dfrac{\partial z}{\partial s}=\dfrac{\partial z}{\partial\theta}\dfrac{\partial\theta}{\partial s}+\dfrac{\partial z}{\partial\phi}\dfrac{\partial\phi}{\partial s}[/tex]
[tex]\dfrac{\partial z}{\partial s}=\cos\theta\cos\phi t^5-\sin\theta\sin\phi (7s^6t)[/tex]
[tex]\dfrac{\partial z}{\partial s}=t^5\cos(st^5)\cos(s^7t)-7s^6t\sin(st^5)\sin(s^7t)[/tex]
[tex]\dfrac{\partial z}{\partial t}=\dfrac{\partial z}{\partial\theta}\dfrac{\partial\theta}{\partial t}+\dfrac{\partial z}{\partial\phi}\dfrac{\partial\phi}{\partial t}[/tex]
[tex]\dfrac{\partial z}{\partial t}=\cos\theta\cos\phi(s5t^4)-\sin\theta\sin\phi s^7[/tex]
[tex]\dfrac{\partial z}{\partial t}=5st^4\cos(st^5)\cos(s^7t)-s^7\sin(st^5)\sin(s^7t)[/tex]
We use the chain rule to find the partial derivatives ∂z/∂s and ∂z/∂t, considering z as a function of θ and ϕ, treating θ and ϕ as intermediate variables. We then differentiate θ with respect to s and t, and similarly for ϕ.
Explanation:To find the partial derivatives ∂z/∂s and ∂z/∂t, we first need to make use of the chain rule in calculus. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. Here, z is a function of θ and ϕ, which are themselves functions of s and t - θ = st^5 and ϕ = s^7t.
First, find the partial derivative ∂z/∂s. We differentiate z = sin(θ)cos(ϕ) with respect to s, treating θ and ϕ as intermediates, and then differentiate θ and ϕ with respect to s.
Similarly, to find the partial derivative ∂z/∂t, we differentiate z = sin(θ)cos(ϕ) with respect to t treating θ and ϕ as intermediates, and then differentiate θ and ϕ with respect to t.
Please note that further calculation will require the exact differentiation of trigonometric functions and power functions.
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Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credited her account with $36.61. What is her new balance?
$2,179.57
$2,252.79
$2,642.77
$2,715.77