what is d/dx(1/sinx) ...?

Let

a--------> the total cost in dollars of [tex]6[/tex] ounces of coconut oil

b--------> the total cost in dollars of [tex]5[/tex] ounces of beeswax

we know that

[tex]a=0.50 \frac{\$}{ounce}*6=\$3[/tex]

[tex]b=2.00 \frac{\$}{ounce}*5=\$10[/tex]

therefore

the answer is

the total cost in dollars of [tex]6[/tex] ounces of coconut oil is [tex]a=\$3[/tex]

the total cost in dollars of [tex]5[/tex] ounces ofbeeswax is [tex]b=\$10[/tex]

Answer:

The linear equation is v = 4.5t +138

The product had value of $138 in 2000.

Step-by-step explanation:

In 2004, dollar value(v) = $156 and rate of change (m) = $4.50

The linear equation is in the form of y = mx + b, where "m" is slope or rate of change, b is the y-intercept.

We can rewrite the equation as v = m(t) + b.

Now let's find the value of b, when t = 4, m = 4.5, v = 156

156 = 4.5(4) + b

b = 156 - 4.5(4)

b = 156 - 18

b = 138

So, the linear equation is v = 4.5t +138

When t=0, the dollar value (v) = 4.5(0) + 138

v = $138

So, the product had value of $138 in 2000

The unknown length YZ can be found through the ratios of corresponding sides in similar figures ABCD and WXYZ. Given AD=12, DC=3, WZ=35, the equation 3/YZ = 12/35 is formed. Solving for YZ, we find that YZ is 8.75.

In the given question, ABCD and WXYZ are similar figures which mean the ratio of corresponding sides are equal. So, the ratio AD/WZ equals to the ratio DC/YZ. Given, AD=12, DC=3 and WZ=35. The length of YZ can be found by cross multiplying these ratios.

So, DC/YZ = AD/WZ.

By substituting the given values:

3/YZ = 12/35.

To find YZ, we simply cross-multiply and solve for YZ:

3 × 35 = 12 × YZ,

Hence, YZ = (3 × 35) / 12, which is 8.75 units.

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Height of water in hexagonal prism vase = 384 inches, given equal volume of water and wet portion.

Let's denote the height of the water in the vase as [tex]\( h \)[/tex] inches.

The volume of a hexagonal prism can be calculated using the formula:

[tex]\[ V = \frac{3\sqrt{3}}{2}a^2h \][/tex]

where [tex]\( a \)[/tex] is the length of one side of the hexagon (which represents the base of the prism), and [tex]\( h \)[/tex] is the height of the prism.

Since the base of the vase is a hexagon, we need to find the side length of this hexagon.

The area of a regular hexagon can be calculated using the formula:

[tex]\[ A = \frac{3\sqrt{3}}{2}a^2 \][/tex]

Given that the volume of water in the vase is 512 cubic inches, and the wet portion's volume and its height are equal, we have:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}a^2h \][/tex]

We are also given that the wet portion's volume is numerically equal to its height, so:

[tex]\[ h = 512 \][/tex]

Substituting this value of [tex]\( h \)[/tex] into the volume equation, we have:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}a^2(512) \][/tex]

Now, we can solve for [tex]\( a \).[/tex]

[tex]\[ a^2 = \frac{512}{\frac{3\sqrt{3}}{2} \times 512} \]\[ a^2 = \frac{512}{\frac{3\sqrt{3}}{2} \times 512} \]\[ a^2 = \frac{2}{3\sqrt{3}} \]\[ a^2 = \frac{2\sqrt{3}}{9} \]\[ a = \sqrt{\frac{2\sqrt{3}}{9}} \]\[ a = \frac{\sqrt{2\sqrt{3}}}{3} \][/tex]

Now, let's find the height of the water by substituting the value of [tex]\( a \)[/tex]into the volume equation:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{\sqrt{2\sqrt{3}}}{3}\right)^2h \]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{2\sqrt{3}}{9}\right)h \]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{2\sqrt{3}}{9}\right)h \]\[ 512 = \frac{4}{3}h \]\[ h = \frac{512 \times 3}{4} \]\[ h = 384 \][/tex]

So, the height of the water in the vase is 384 inches.

1.5x+2.5y=21.50

x+y=9

8 people ordered chicken sandwich

The simplified form of the expression [tex]8a+4b-3a+5b[/tex] is [tex]\boxed{5a+9b}[/tex].

Further explanation:

The given expression is [tex]8a+4b-3a+5b[/tex].

The given expression consists of [tex]2[/tex] different variables [tex]a[/tex] and [tex]b[/tex]. These variables can take any values since, its value is not fixed.

An algebraic expressions are formed if different variables and are added, subtracted, multiplied and divided.

The given expression is obtained when the variable [tex]a[/tex] and variable [tex]b[/tex] is added and subtracted with multiplication with different integers.

In the given expression there are [tex]4[/tex] terms with each term having different coefficients.

Like terms in the given expression are those whose algebraic factors are same that is [tex]8a[/tex] and [tex]-3a[/tex] are like terms and [tex]4b[/tex] and [tex]5b[/tex] are like terms.

The given expression is a binomial since, it have two unlike terms.

To simplify the given expression first we have to identify the like and unlike terms.

The like terms are [tex]8a[/tex] and [tex]-3a[/tex] and other set of like terms are [tex]4b[/tex] and [tex]5b[/tex]

Since, [tex]a[/tex] and [tex]b[/tex] are variable and they are numbers they can be added or subtracted using distributive property.

[tex]8a[/tex] and [tex]-3a[/tex] are subtracted as follows:

[tex]\begin{aligned}8a-3b&=(8\cdot a)-(3\cdot a)\\&=(8-3)\cdot a\\&=5\cdot a\\&=5a\end{aligned}[/tex]  

[tex]4b[/tex] and [tex]5b[/tex] are added as follows:

[tex]\begin{aligned}4b+5b&=(4\cdot b)+(5\cdot b)\\&=(4+5)\cdot b\\&=9\cdot b\\&=9b\end{aligned}[/tex]  

Therefore, simplified form of the given expression is [tex]5a+9b[/tex] since both are positive terms.

Thus, the simplified form of the expression [tex]8a+4b-3a+5b[/tex] is [tex]\boxed{5a+9b}[/tex].

Learn more:

1. Learn more about equations https://brainly.com/question/1473992

2. Learn about solving equation https://brainly.com/question/5723059

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Algebraic expressions

Keywords:  Simplify, 8a+4b-3a+5b, expression, 5a+9b, terms, coefficients, like, unlike, addition, subtraction, variables, values, distributive property, like terms, unlike terms.

Answer:

4 lbs

Step-by-step explanation:

There are 16 ounces in a pound, so divide 64 by 16 to get the number of pounds.  64 ÷ 16 = 4 lbs

To solve mx+4y=3t for x, subtract 4y from both sides to isolate the x term, giving mx = 3t - 4y. Then, divide both sides by m to solve for x, resulting in x = (3t - 4y) / m.

To solve the equation mx+4y=3t for the value of x, follow these steps:

You can now plug in the known values for y, t, and m to find the value of x.

The slope-intercept form of equation of the line that has slope -6 and y-intercept (0, 2) is y=-6x+2.

The slope intercept form of a straight line is one of the most common forms used to represent the equation of a line. The slope intercept formula can be used to find the equation of a line when given the slope of the straight line and the y-intercept.

The standard form of the slope intercept form is y=mx+c.

Given that, the line that has slope -6 and y-intercept (0, 2).

The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0.

Here, m=-6 and c=2

Substitute m=-6 and c=2 in y=mx+c, we get

y=-6x+2

Therefore, the slope-intercept form of equation of the line that has slope -6 and y-intercept (0, 2) is y=-6x+2.

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Answer:

It's mainly 25% as the percent error.

Step-by-step explanation:

Answer: The correct expansion is,

[tex]x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5[/tex]

Step-by-step explanation:

Since, by the binomial expansion,

[tex](p+q)^n=\sum_{r=0}^{n} ^nC_r (p)^{n-r}(q)^r[/tex]

Where,

[tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]

Here, p = x and q = y and n = 5,

By substituting values,

[tex](x+y)^5=\sum_{r=0}^{5} ^5C_r (x)^{n-r}(y)^r[/tex]

[tex] =^5C_0(x)^{5-0}(y)^0+^5C_1 (x)^{5-1}(y)^1+^5C_2 (x)^{5-2}(y)^2+^5C_3 (x)^{5-3}(y)^3+^5C_4 (x)^{5-4}(y)^4+^5C_5(x)^{5-5}(y)^{5}[/tex]

[tex]=1(x)^5(y)^0+\frac{5!}{4!(5-4)!}x^4y^1+\frac{5!}{3!(5-3)!}x^3y^2+\frac{5!}{2!(5-2)!}x^2y^3+\frac{5!}{1!(5-1)!}xy^4+\frac{5!}{5!(5-5)!}x^0y^5[/tex]

[tex]=x^5+\frac{5!}{4!1!}x^4y^1+\frac{5!}{3!2!}x^3y^2+\frac{5!}{2!3!}x^2y^3+\frac{5!}{1!4!}x^1y^4+\frac{5!}{5!0!}x^0y^5[/tex]

[tex]=x^5+\frac{5\times 4!}{4!}x^4y^1+\frac{5\times 4\times 3!}{3!2!}x^3y^2+\frac{5\times 4\times 3!}{2!3!}x^2y^3+\frac{5\times 4!}{4!}x^1y^4+\frac{5!}{5!}y^5[/tex]

[tex]=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5[/tex]

Which is the required expansion.

To find the probability that exactly two of the five will take the same test, we use combinations. The probability is 2/3 or 0.667. To find the probability that the two women will take the same test, we use combinations. The probability is 1/2 or 0.500.

To find the probability that exactly two of the five will take the same test, we can use the concept of combinations. There are six different tests, and we need to choose two of them to be taken by two people. The total number of ways to select two tests out of six is given by the combination formula C(6,2) = 6!/(2!(6-2)!) = 15. Now, for each of these two selected tests, there are two people (either two men or two women) who can take the test, resulting in a total of two possibilities. Therefore, the number of favorable outcomes is 2 * 15 = 30. Finally, the probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes, which is 6!/(2!3!) = 15. So the probability is 30/15 = 2/3 or 0.667 (rounded to three decimal places).

To find the probability that the two women will take the same test, we can use similar reasoning. There are six different tests, and we need to choose one of them to be taken by both women. The total number of ways to choose one test out of six is given by the combination formula C(6,1) = 6!/1!(6-1)! = 6. Now, for the chosen test, there are three possible ways both women can take it, since they can be the first two applicants, the last two applicants, or the middle two applicants. Therefore, the number of favorable outcomes is 3. The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes, which is also 6. So the probability is 3/6 = 1/2 or 0.500 (rounded to three decimal places).

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Final answer:

The probability that exactly two of the five will take the same test is 0.00463. The probability that the two women will take the same test is 1.167.

Explanation:

To find the probability that exactly two of the five will take the same test, we can use combinations. There are 6 different tests and we want to select 2 of them for the same test. Since order doesn't matter, we can use combinations. The number of ways to choose 2 tests out of 6 is 6 choose 2 = 15.

Now, for each pair of tests, we have 5 people who can take those tests. The probability that exactly 2 of the five will take the same test is the probability that exactly 2 people are randomly assigned to the same test out of the 5 people. The total number of possible outcomes is 6^5 since each person has 6 choices for which test to take, and there are 5 people.

So, the probability that exactly two of the five will take the same test is 15/6^5, which is approximately 0.00463.

To find the probability that the two women will take the same test, we consider the different possibilities. The two women can take the same test out of the 6 tests, or they can take different tests.

If they take the same test, there are 5 possible tests for them to choose from. The probability of this happening is 5/6.

If they take different tests, there are 5 possible tests for each of them to choose from. The probability of this happening is (5/6) * (4/5) = 2/3.

Therefore, the probability that the two women will take the same test is (5/6) + (2/3) = 7/6, which is approximately 1.167.