What is 3and 2 fiths subtract 5 eighths

Answer:

They are not equal? I don't get what you're trying to ask.

Answer:

y = 3

Step-by-step explanation:

Answer:

Jamal  is correct.

Step-by-step explanation:

3:4 is equivalent to 9:12, not 18:12.

We can see that for 3:4, the left side is less than the right, but for 18:12, left side is greater than the right, which immediately tells us the ratios are not equivalent.

Jamal is correct. 18:12 and 3:4 are not equivalent ratios.

To determine if two ratios are equivalent, you can simplify them to their simplest form or find a common factor that divides both terms. In this case:

18:12 can be simplified by dividing both terms by their greatest common factor, which is 6:

18 ÷ 6 = 3

12 ÷ 6 = 2

So, 18:12 simplifies to 3:2.

Now, compare it to 3:4. Since they have different values (3:2 vs. 3:4), Jamal's statement is incorrect, and Margie is right; they are not equivalent ratios.

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Answer:

1.997 x 10²

Step-by-step explanation:

The number with the highest exponent is the greatest value.

10² is bigger than 10⁻⁶ and 10⁻⁸, so 1.997 x 10² is your answer.

Answer:

Length of the base = 8

Step-by-step explanation:

Area of a triangle = 1/2(h*b)

h = height

b = base

52 = 1/2 (13 * b)

Rearrange the equation to get b on it's own

52 * 2 = 13 * b

104 = 13 * b

104/13 = b

b = 8

A = 1/2(bh)

in this case, b = 2a/h. plug in the values:

steps

b = 2a/h

b = 2(52)/13

b = 104/13

b = 8 meters

Answer:

x-intercept

= 7/6

= 1.16667

Answer:

Step-by-step explanation:

Answer:

[tex]6 \frac{5}{9} [/tex]

is greater than

[tex]6 \frac{15}{28} [/tex]

Answer:6 5/9 is greater than 6 15/28

Step-by-step explanation: positive proper fractions: 15/28, 5/9;

1 positive integer number: 6; Any positive proper fraction is smaller than

any positive integer number Sort the positive proper fractions:

15/28 and 5/9 15/28 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

15 = 3 × 5;

28 = 22 × 7;

5/9 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

5 is a prime number;

9 = 32; 15 = 3 × 5;

5 is a prime number;

Multiply all the unique prime factors, by the largest exponents:

LCM (15, 5) = 3 × 5 = 15 Divide LCM by the numerator of each fraction:

For fraction: 15/28 is 15 ÷ 15 = (3 × 5) ÷ (3 × 5) = 1;

For fraction: 5/9 is 15 ÷ 5 = (3 × 5) ÷ 5 = 3;  Build up all the fractions to the same numerator (which is LCM).

Multiply the numerators and the denominators by their expanding number:

15/28 = (1 × 15)/(1 × 28) = 15/28;

5/9 = (3 × 5)/(3 × 9) = 15/27;

Answer:

OPTION A: [tex]$ \frac{12}{1 + 8x} $[/tex], where [tex]$ x \ne - \frac{1}{8} $[/tex].

Step-by-step explanation:

Given: [tex]$ \frac{- 12x^4}{x^4 + 8x^5} $[/tex]

Taking [tex]$ x^4 $[/tex] common outside in the denominator, we get:

[tex]$ = \frac{-12x^4}{(x^4)(1 + 8x)} $[/tex]

[tex]$ x^4 $[/tex] will get cancelled on the numerator and denominator, we get:

[tex]$ = \frac{-12}{1 + 8x} $[/tex]

we know that the denominator can not be zero.

That means, 1 + 8x [tex]$ \ne $[/tex] 0.

[tex]$ \implies 8x \ne -1 $[/tex]

[tex]$ \implies x \ne \frac{-1}{8} $[/tex]

So, the answer is: [tex]$ \frac{-12}{1 + 8x} $[/tex], where [tex]$ x \ne \frac{-1}{8} $[/tex].

Answer:

[tex]\displaystyle 2x - 3y = 6\:OR\:y = \frac{2}{3}x - 2 \\ \\ 3x - 2y = 40\:OR\:y = \frac{3}{2}x - 20[/tex]

Step-by-step explanation:

2 = ⅔[6] + b

4

[tex]\displaystyle -2 = b \\ \\ y = \frac{2}{3}x - 2[/tex]

If you want it in Standard Form:

y = ⅔x - 2

- ⅔x - ⅔x

_________

−⅔x + y = −2 [We do not want fractions in our standard equation, so multiply by the denominator to get rid it.]

−3[−⅔x + y = −2]

[tex]\displaystyle 2x - 3y = 6[/tex]

_______________________________________________

−5 = 3⁄2[10] + b

15

[tex]\displaystyle -20 = b \\ \\ y = \frac{3}{2}x - 20[/tex]

If you want it in Standard Form:

y = 3⁄2x - 20

- 3⁄2x - 3⁄2x

__________

−3⁄2x + y = −20 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]

−2[−3⁄2x + y = −20]

[tex]\displaystyle 3x - 2y = 40[/tex]

* Parallel Lines have SIMILAR RATE OF CHANGES [SLOPES], so ⅔ and 3⁄2 remain the way they are.

I am joyous to assist you anytime.

Answer:

The numbers are 165 and 113

Step-by-step explanation:

Let

x ----> one number

y ----> the other number

we know that

[tex]x+y=278[/tex] ----> equation A

[tex]x=y+52[/tex] ----> equation B

substitute equation B in equation A

[tex](y+52)+y=278[/tex]

solve for y

[tex]2y=278-52[/tex]

[tex]2y=226[/tex]

[tex]y=113[/tex]

Find the value of x

[tex]x=y+52[/tex]

[tex]x=113+52=165[/tex]

therefore

The numbers are 165 and 113

Answer:

[tex]\angle a=35^o[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

An isosceles triangle has two equal sides and two equal interior angles

The angles opposite to the equal sides of an isosceles triangle are equal.

[tex]\angle b=\angle c[/tex]

we have

[tex]\angle c=55^o[/tex] -----> given problem

so

[tex]\angle b=55^o[/tex]

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

[tex]\angle b+\angle c+2\angle a=180^o[/tex]

substitute the given values

[tex]55^o+55^o+2\angle a=180^o[/tex]

[tex]110^o+2\angle a=180^o[/tex]

[tex]2\angle a=180^o-110^o[/tex]

[tex]2\angle a=70^o[/tex]

[tex]\angle a=35^o[/tex]

(gof)(0) cannot be evaluated

Solution:

Given that,

[tex]f(x) = \frac{1}{x}\\\\g(x) = x - 4[/tex]

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

[tex](g o f) (x) = g(\frac{1}{x})[/tex]

[tex]\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4[/tex]

[tex](g o f) (x) = \frac{1}{x} - 4[/tex]

Now to find (gof)(0), substitute x = 0

[tex](g o f) (x) = \frac{1}{0} - 4[/tex]

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

Answer:

You must evaluate the function f first.

Division by 0 is undefined.

The composition cannot be evaluated.

Step-by-step explanation:

Answer:

A ) The Original price of music player before it was marked down by  [tex]\dfrac{1}{4}[/tex]  is $512

B ) The price that store paid for player is $256

C ) The difference between discount price and price paid by store is $128

Step-by-step explanation:

Given as :

A ) The sale price of music player = $128

The music player is marked down by [tex]\dfrac{1}{4}[/tex] of original price

Let The original price = $x

Now, According to question

[tex]\dfrac{1}{4}[/tex] of original price = $128

i.e [tex]\dfrac{1}{4}[/tex] × $x = $128

Or, x = 128 × 4

∴ x = $512

So, The Original price of music player before it was marked down by  [tex]\dfrac{1}{4}[/tex]  is $512

B ) The music player is marked up by [tex]\dfrac{1}{2}[/tex] before it was placed on sales floor .

Let The price that store paid for player = $y

Now, According to question

∵ The original price of player = $512

So, The price that store paid for player = [tex]\dfrac{1}{2}[/tex]  × original price of player

i.e y =  [tex]\dfrac{1}{2}[/tex]  × $512

Or , y = $256

So,The price that store paid for player = $256

C ) Let The difference between discount price and price paid by store = $z

So, According to question

z = y - discount price

Or , z = $256 - $128

∴  z = $128

So, The difference = $128

Hence, A ) The Original price of music player before it was marked down by  [tex]\dfrac{1}{4}[/tex]  is $512

B ) The price that store paid for player is $256

C ) The difference between discount price and price paid by store is $128

Answer

Answer:

2/25

Step-by-step explanation:

Answer:

0.08

Step-by-step explanation:

Answer:

The x-axis, it would be between quadrant 2 and quadrant 3

Answer:

The width of the sandbox is 4 feet

Step-by-step explanation:

Area = Length x Width

Fill in known values

26 sq ft = 6.5 ft x w

Divide by 6.5 on both sides

4 ft = w

Width = 4 ft

:)

Answer:

k=2

Step-by-step explanation:

3k-k+5k-7=7

2k+5k=7+7

7k=14

k=14/7

k=2

Answer:

[tex] \: \: \: \: \: \: \: \: 3k - k + 5k - 7 = 7 \\ = > 8k - k = 7 + 7 \\ = > 7k = 14 \\ = > k = \frac{14}{7} \\ = > k = 2[/tex]

The slope is -4/5

Step-by-step explanation:

We have to observe the graph to find two points to find slope.

The graph has two points

(-5,0) and (0, -4)

The formula for slope is given by:

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\[/tex]

Here

(x1,y1) = (-5,0)

(x2,y2) = (0,-4)

Putting the values

[tex]m = \frac{-4-0}{0+5}\\=-\frac{4}{5}[/tex]

Hence,

The slope is -4/5

Keywords: slope, steepness

Learn more about slope at:

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Scenario:

Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write an inequality that would be used to solve for the least amount of money he needs to deposit to avoid a fee.

Equation:

727.29 − 248.50 + x ≥ 500

Answer:

x  ≥  21.21

Answer:

For [tex]d=-2[/tex] rational expression will be undefined.

Step-by-step explanation:

Given function is [tex]\frac{6d-4}{d+2}[/tex]

We need to find for what value of variable [tex]d[/tex] this rational expression will be undefined.

The rational expression will be undefined if the denominator of the expression will become zero.

So, let us plug denominator equal to zero.

[tex]d+2=0\\\\Subtracting\ both\ side\ 2\\\\d+2-2=-2\\\\d=-2[/tex]

Hence, this rational expression will be undefined if the value of variable [tex]d=-2[/tex].

Answer:

6^h=126

Step-by-step explanation:

6 to the power of h is just 6^h

Plug it into an equation with =126

Boom you have the equation 6^h=126

Answer:

Very bottom graph

Step-by-step explanation:

Go .75 units right (positive x) then go 1.5 units down (negative y)

Answer:

Your answer will be D.

Step-by-step explanation:

Coordinate grid shown from negative 2 to positive 2 on the x-axis and negative 2 to positive 2 on the y-axis in increments of 1 over 4. Only the whole numbers are labeled. A point A is shown at the intersection of 3 grid lines to the right of the y-axis and 6 grid lines below the x-axis.

Answer:

AY = 10 cm.

Step-by-step explanation:

Given that, ΔABC is similar to ΔAXY

and [tex]\frac{AB}{AX }  = \frac{5}{3}[/tex]

⇒  [tex]\frac{AC}{AY }  =  [tex]\frac{BC}{XY } = \frac{5}{3}[/tex]

⇒ BC = XY× \frac{5}{3}[/tex] =  \frac{20}{3}[/tex] (as XY = 4 cm given)

Now, check the attached figure,

given, BY bisects ∠XYC

let ∠XYB = ∠BYC = x

⇒ ∠AYX = 180-2x (angle on a straight line)

and also ∠AYX = ACB (similar triangle properties)

⇒ ∠ACB = 180-2x

Now, sum of angles in ΔBYC = 180°

⇒ ∠YBC = x

⇒ BC = YC (as two sides of equal angles are equal in a triangle)

⇒ YC =  \frac{20}{3}[/tex]

And also [tex]\frac{AC}{AY }  = \frac{5}{3}[/tex]

AC = AY + YC

⇒ [tex]\frac{AY+YC}{AY }  = \frac{5}{3}[/tex]

⇒ [tex]\frac{AY+\frac{20}{3}[/tex]}{AY }  = \frac{5}{3}[/tex]

⇒ 5AY = 3AY + 20

⇒ AY = 10 cm

Complete Question:

As you may have unintentionally forgotten to add the answer choices in your question, but I was able to find the complete the question and answering your question based on this as it may surely clear your concepts. Here is the complete question.

In which of the following functions would it be appropriate to use only positive integers for the domain? Select all that apply.

The function c(p) represents The cost for P people to attend the movies. The function m(t) represents the miles driven over T hours. The function t(m) represents the average high temperature for a given number of months. The function p(w) represents the prophet of a farmer who sells whole watermelons. The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

Answer Explanation:

Domain is termed as all the input values on a certain interval that define the function.

Here are the appropriate function scenarios where it is appropriate to use only positive integers.

The function c(p) represents The cost for P people to attend the movies.

As the function c(p) contains people. And People are not counted as negative, although they can be zero. So, only positive integers should be appropriate to use in this scenario.

The function m(t) represents the miles driven over T hours

As the function m(t) contains miles. And miles are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function t(m) represents the average high temperature for a given number of months.

As the function t(m) contains months. And months are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function p(w) represents the prophet of a farmer who sells whole watermelons.

As the function p(w) contains the number of watermelons. And watermelons are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

As the function h(n) contains the number of engines. And engines are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

Keywords: domain, function, positive integer

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Answer:

Step-by-step explanation:

X=-1/2

Hope this helps mark me as brainiest pls

Yes, -1/2 will be the x-coordinate for the solution. We can also find the y-coordinate by subbing in -1/2 for x in the equation y=4x+7.

y=4(-1/2)+7

y=-2+7

y=5

The intersection point would be (-1/2,5).

Answer:

m=7

Step-by-step explanation:

2m-(-3m)+(-15)=20

2m+3m-15=20

5m-15=20

5m=20+15

5m=35

m=35/5

m=7

Answer:

26.4 ft^2 (1 d.p.)

Step-by-step explanation:

[tex]area \: of \: circle = \pi {r}^{2} [/tex]

Since it is given that r, the radius of the circle, is 2.9 ft,

area of circle= π(2.9)^2= 8.41π= 26.4 ft^2 (1 d.p.)