The chemical formula for the unknown molecule shown above is...

Answer: 3.5 moles V2O5

Explanation: First balance the chemical equation to find the stoichiometric factor between VOCl3 and V2O5

2 V2O5 + 6 Cl2 => 4 VOCl3 + 7 O2

So the mole to mole ratio is 2 moles V2O5 to 4 moles of VOCl3

Solution

7 moles VOCl3 x 2 moles V2O5 / 4 moles VOCl3 = 3.5 moles V2O5

Answer:

2HBr + Mg(OH)2 => MgBr2 + 2 H2O

Explanation: To balance the equation put 2 in H2O in the product side. Then balance the other Hydrogen atoms by adding 2 in HBr. Since there is another 2 atoms of H in (OH)2 so hydrogen atoms are balanced having 4 atoms each sides. Also Mg and Br are balanced

Answer:

1 mol of C2H6 contains 6.023 x 10^23 molecules and each molecule e of ethane contain 2 carbon atoms . so to tal no. of carbon atoms = 2 X 6X 10^23

Explanation:

Answer:

The equilibrium constant Kc for the reaction is :

16.07

Explanation:

The balanced equation is :

[tex]H_{2}(g)+I_{2}(g)\rightleftharpoons 2HI(g)[/tex]

First ,

"At the equilibrium, 60% of the hydrogen gas had reacted"

This means the degree of dissociation = 60% = 0.6

Here we are denoting degree of dissociation by ="x" =  0.6

Now , consider the equation again,

[tex]H_{2}(g)+I_{2}(g)\rightleftharpoons 2HI(g)[/tex]

H2                       I2                 2HI

0.35                   1.6                0            (Initial Concentration)

0.35(1 - x)           1.6(1 - x)         2x    (At equilibrium)

0.35(1 - 0.6)       1.6(1 - 0.6)      2(0.6)

0.14                     0.64                 1.2

calculate the concentration of each:

[tex]Concentration =\frac{moles}{Volume(L)}[/tex]

[tex]C_{H_{2}}=\frac{0.14}{2}[/tex]  

[tex]C_{H_{2}}=0.07moles/L[/tex]

[tex]C_{I_{2}}=\frac{0.64}{2}[/tex]  

[tex]C_{I_{2}}=0.32moles/L[/tex]

[tex]HI=\frac{1.2}{2}[/tex]  

[tex]HI=0.6moles/L[/tex]

The equilibrium constant for this reaction "Kc" can be written as:

[tex]Kc=\frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex]  

[tex]Kc=\frac{0.6^{2}}{0.07\times 0.32}[/tex]

[tex]Kc=\frac{0.36}{0.0224}[/tex]

[tex]Kc=16.07[/tex]

Answer:

392

Explanation:

According to the law of conservation of energy, energy cannot vanish,so the lost potential energy must be converted into another form of energy (in this case, Kinetic Energy).

(mass*g*height)-(mass*g*halfway height)=(2*9.8*40)-(2*9.8*20)

784-392=392

This makes sense because since the rock has fallen halfway, half of its potential energy has become kinetic energy. Once the rock reaches a height of 0 Meter, all of its potential energy will be kinetic energy.

Answer: I’ve got you man ,

Cl has comparitively huger size than carbon and needs just one electron to fill its valence shell and be stable. ... Hydrogen is a halogen and is above chlorine in the 17th group but still it is not more electronegative than chlorine.

Explanation:

have a good day

Final answer:

Chlorine is more reactive than carbon because the bonds between chlorine atoms are weaker compared to the strong carbon-fluorine bonds. Reactivity increases from fluorides to iodides, with chlorides being more reactive than fluorides due to easier bond breaking.

Explanation:

In terms of reactivity, the key factor is the strength of the bonds that need to be broken for a reaction to occur. A carbon-chlorine bond is relatively strong but not as strong as a carbon-fluorine bond. Therefore, in a series of carbon-halogen bonds, the strength decreases and thus reactivity increases in the following order: C-F (least reactive), C-Cl, C-Br, to C-I (most reactive).

Looking specifically at chlorine, it forms diatomic molecules (Cl₂) with a relatively weak bond between the atoms, making Cl₂ quite reactive. Chlorine reacts with a variety of substances, including metals, to form chlorides. Considering alkyl halides, iodides are the most reactive and fluorides the least because it is easiest to break a carbon-iodine bond and hardest to break a carbon-fluorine bond.

The reactivity of chlorination products must take into account the polarity of the bond. The carbon-chlorine bond's polarization leads to increased reactivity as it can be more easily attacked due to its partial positive charge on the carbon atom.

To lower the pH of vinegar, it should be boiled to concentrate the acetic acid. Mixing vinegar with baking soda triggers a reaction where bicarbonate acts as a base.

To lower the pH of vinegar, which means to make it more acidic, one should concentrate the acetic acid content in the vinegar. This can be done by option B, boiling the vinegar to concentrate it. Boiling causes the water to evaporate, leaving behind a higher concentration of acetic acid. Adding sugar, freezing, or diluting with water would not lower the pH, but diluting with water would actually raise the pH, making the vinegar less acidic.

When vinegar and baking soda are mixed, a chemical reaction occurs, producing carbon dioxide gas, water, and sodium acetate. However, the question requires an understanding of what species in vinegar serves as a base. In the reaction with baking soda (sodium bicarbonate), vinegar (acetic acid) acts as the acid, and the bicarbonate ion in baking soda acts as the base.

Final answer:

To lower the pH of vinegar, you can add water to dilute it, which decreases the concentration of acetic acid.

Explanation:

To lower the pH of vinegar, you can add water to dilute it. When you add water to vinegar, it increases the amount of solvent and decreases the concentration of acetic acid, which is responsible for the acidic properties of vinegar. This dilution results in a lower pH.

Answer:

A) Fission reactors release harmful gases into the atmosphere — mainly CO₂.  

Explanation:

Fission reactors release no CO₂ into the atmosphere.

B, C, and D are correct.

Answer:

A

Explanation:

USA Test prep

The given chemical and physical properties can be most useful as a machinery lubricant. Therefore, option A is correct.

A lubricant can be described as a substance that helps to decrease friction between surfaces in mutual contact, which reduces the heat produced when the surfaces move.

The lubricant-to-surface friction is generally much less than surface-to-surface friction without any lubrication. Therefore, the use of a lubricant reduces friction in types of machinery.

It has the function of transmitting forces, transporting particles, or heating or cooling the surfaces. The property of reducing friction between the surfaces is called lubricity.

A machine lubricant has the property to stay liquid within a wide range of temperatures. They have high viscosity index, thermal stability, Hydraulic stability, Corrosion prevention, and high resistance to oxidation.

These properties of Lubricants are the same as the given chemical and physical properties. Therefore, the given properties can be useful as a machinery lubricant.

Learn more about lubricants, here:

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Answer: option D. CO2 and SO2

Explanation:

Answer:

The answer is letter A, are in constant random motion.

Explanation:

"Kinetic Molecular Theory of Gases" shows the behavior of gases in relation to heat and temperature (thermodynamics). "Kinetic" means motion, thus it is very normal to say that the theory is about the motion of gas particles.

When it comes to "ideal gases" (gases which obey the gas law), the gas is made of of molecules or atoms, which are very small particles. These have the same amount of mass and are constantly colliding in a rapid motion. However, their collisions are "elastic," which means that, there is "no net conversion" of the molecules' or atoms' kinetic energy. This means that the "total kinetic energy "is the same or stable, but is dependent on the temperature.

Remember that the gas particles in one sample have varying speed, which means that their kinetic energy are not the same.

Answer:    n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT, you can find P

P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L

P = 1.642 atm = 1.6 atm (to 2 significant figures)

Final answer:

The pressure inside a container with 3 moles of gas, a volume of 60 liters, and a temperature of 400 K is approximately 1247.2 mm Hg, calculated using the Ideal Gas Law.

Explanation:

To calculate the pressure inside the container we can use the Ideal Gas Law, which is expressed as PV = nRT. In this formula, P stands for pressure, V for volume, n for number of moles, R for the ideal gas constant, and T for temperature. The ideal gas constant (R) has various values depending on the units of pressure and volume.

For this problem, we will use R = 62.36 L mm Hg / mol K, since we are asked to find the pressure in millimeters of mercury (mm Hg) and the volume is given in liters (L).

First, we need to correctly plug in our given values: we have n = 3 moles, V = 60 liters, and T = 400 K. When these values are substituted into the ideal gas equation, we get P(60 L) = (3 moles)(62.36 L mm Hg / mol K)(400 K).

Solving for pressure P gives us:

P = (3 moles × 62.36 L mm Hg / mol K × 400 K) / 60 L

Now, let's do the math:

P = (74832 mm Hg K / mol) / 60 L= 1247.2 mm Hg

The pressure inside the container is therefore approximately 1247.2 mm Hg.

Answer:

Number of moles = 0.116 mol

Explanation:

Given data:

Number of moles of potassium bromide = ?

Volume of solution = 68.5 mL

Molarity of solution = 1.65 M

Solution:

First of all we will convert the mL into L.

68.5 mL × 1 L /1000 mL

0.07 L

Molarity = Number of moles / Volume in litter

we will rearrange the formula:

Number of moles = molarity × volume in litter

Now we will put the values in formula:

Number of moles = 1.65 M  ×0.07 L

Number of moles = 0.116 mol

Answer: 0.11

Explanation:

Answer:

Empirical formula is CCl₄

Explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

            C                      :              Cl            

           0.64/0.64        :             2.6/0.64

            1                      :                4        

C : Cl  = 1 : 4

Empirical formula is CCl₄.

The empirical formula for the compound that is 7.70% carbon and 92.3% chlorine is [tex]{CCl_4}[/tex].

The empirical formula of a compound represents the smallest whole-number ratio of atoms present in a molecule. To find the empirical formula for a compound given the percentage composition, follow these steps:

1. Assume a 100 g sample of the compound. The percentages given are then directly equal to the mass of each element in grams.

2. Convert the mass of each element to moles using the molar mass of each element.

3. Divide the moles of each element by the smallest number of moles obtained to find the mole ratio.

4. If necessary, multiply the mole ratio by the smallest whole number to get whole numbers, which will give the empirical formula.

Let's apply these steps to the given problem:

1. For a 100 g sample of the compound, we have:

 - Carbon (C): 7.70 g

 - Chlorine (Cl): 92.30 g

2. Convert the mass of each element to moles:

 - Moles of C = mass of C / molar mass of C = 7.70 g / 12.01 g/mol = 0.641 mol

 - Moles of Cl = mass of Cl / molar mass of Cl = 92.30 g / 35.45 g/mol= 2.603 mol

3. Find the mole ratio by dividing by the smallest number of moles:

 - Mole ratio of C = 0.641 mol / 0.641 mol = 1

 - Mole ratio of Cl = 2.603 mol / 0.641 mol = 4

4. The mole ratio is C:Cl = 1:4. Therefore, the empirical formula of the compound is CCl4

The empirical formula for the compound that is 7.70% carbon and 92.3% chlorine is [tex]{CCl_4}[/tex].

The complete question is:

What is the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine?

Answer:

x = 1.01166

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Explanation:

Step 1: Define

y = 1.2345x - 0.6789

y = 0.570

Step 2: Solve for x

Final answer:

To solve the given linear equation for x, add 0.6789 to both sides, divide by 1.2345, and then substitute y = 0.570 to find the value of x as 1.012 .

Explanation:

To solve the equation y = 1.2345x - 0.6789 for x, given that y = 0.570, we will isolate x on one side of the equation. First, we add 0.6789 to both sides to get y + 0.6789 = 1.2345x. Then, we divide both sides by 1.2345 to find x:

x = (y + 0.6789) / 1.2345

Substituting 0.570 for y, we get:

x = (0.570 + 0.6789) / 1.2345

x= 1.012

After performing the calculations, we find the value of x to be 1.012 that satisfies the given equation with y equal to 0.570.

The volume of the helium gas will be 11.2L when the pressure increases to 2.00 atm and the volume of the neon gas syringe will be 2.24L at STP. After adding 0.10 mol of argon gas to the syringe, keeping pressure and temperature constant, the volume will increase to 4.48 L.

The student is asking about the behavior of gases under different conditions and these questions deal with the application of the ideal gas law. The ideal gas law formula is PV=nRT, where P is pressure, V is volume, n is number of moles, R is gas constant, and T is temperature. We can utilize this formula to solve each of these problems.

1.00 mol helium gas at STP in a balloon: At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 L. So, if the pressure doubles to 2.00 atm, the volume will reduce to half(by Boyle's Law (P1V1=P2V2)) which is 11.2L.

0.10 mol neon gas at STP in a syringe: At STP, 0.10 mol of gas will occupy a volume of 0.10 mol x 22.4 L/mol = 2.24 L.

Adding 0.10 mol argon gas to the syringe: After adding the argon, the total amount of moles of gas is 0.10 mol neon + 0.10 mol argon = 0.20 mol. At STP, 0.20 mol gas will occupy a volume of 0.20 mol x 22.4 L/mol = 4.48 L. So, the syringe will indicate 4.48 L after the argon is added and the pressure and temperature remain constant.

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Answer:

4

Explanation:

I took the test and got it right!

Answer:the volume will be 2.15L

Explanation:

V1 = 2.35L

V2 =?

T1 = 20°C = 20 +273 = 293k

T2 = - 5°C = - 5 + 273 = 268k

V1 /T1 = V2 /T2

2.35 /293 = V2 /268

V2 = (2.35 / 293) x 268

V2 = 2.15L

Answer:

c

Explanation:

gradpoint

Answer:

pour out some of the solution from the beaker

Answer: option C. between gases should in all cases be extremely rapid because the average kinetic energy of the molecules is great.

The speed of a chemical reaction is influenced by temperature and concentration. Reactions between gases are generally rapid due to the high average kinetic energy of the molecules.

The speed of a chemical reaction is influenced by various factors, including temperature, concentration, and the nature of the reactants. The statement that best aligns with these factors is: c. Between gases should in all cases be extremely rapid because the average kinetic energy of the molecules is great.

Temperature plays a crucial role in determining the speed of a reaction. Increasing the temperature increases the kinetic energy of the molecules, causing them to move faster and collide more frequently, leading to faster reaction rates. Additionally, the statement that mentions the effect of concentration on reaction rates is: When a reaction occurs between two reactant species, it proceeds faster at higher concentrations of the reactants.

It is important to note that factors like surface area and the presence of bonds to be broken also influence reaction rates, but they are not addressed in the given options.

The amount of grams of phosphorus that are recommended is 0.700 g

Why?

This is an unit conversion problem. To convert between units we use conversion factors. In this case the conversion factor we want is from mg to g, and this is relatively simple: 1000 mg = 1 g. Now, we arrange the quantities in the following way:

[tex]700 mg P*\frac{1g}{1000mg}=0.700 g[/tex]

Conversion factors are really useful for converting units! Just remember to put the unit you don't want at the bottom, and the one you want at the top.

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Answer:

0.700mg

Explanation:

Elemental Phosphorus is probably different than supplement phosphorus. We cannot ingest red, yellow, or white phosphorus.

So 700mg of something is technically .7grams of that something, but supplemental phosphorus would weigh a bit more per volume of supplement because it would contain other atoms besides just phosphorus, to allow it to become BIOAVAILABLE. So depending on the molecular makeup of that edible phosphorus it may weigh 2grams per .7gram of pure phosphorus, or it could weigh 1.4grams or .9grams…. anything over that original .7grams

700mg of phosphorus is .7grams pure, but you will consume more than .7grams to get it in your system.

Answer:

Malleable

Explanation:

The percentage yield if 4.65 g of copper is produced will be 70.4 %.

Explanation:

The balanced equation is given as

                  2Al + 3CuSO4 ----> Al2(SO4)3 + 3Cu

1.87 g of Al =  0.0693 moles of Al *  3 moles of Cu / 2 moles of Al

                  = 0.10396 moles of Cu.

This corresponds to 6.606 g of Cu which refers to theoretical yield.

% yield = (actual / theoretical) * 100

            = (4.65 / 6.606) * 100

% yield = 70.4 %.  

To calculate the percent yield for copper production, convert the given mass of aluminum to moles, use stoichiometry to determine the theoretical yield of copper, and then divide the actual yield by the theoretical yield and multiply by 100%.

To calculate the percent yield in the reaction where 1.897 grams of aluminum reacts with an excess of copper (II) sulfate to produce copper, we first need to determine the theoretical yield of copper that can be produced from the given amount of aluminum. Utilizing stoichiometry, we start with the balanced chemical equation:

2Al + 3CuSO4 (aq) → Al2(SO4)3 (aq) + 3Cu

This equation tells us that 2 moles of aluminum can produce 3 moles of copper. However, since we have the mass of aluminum, we need to convert it to moles using aluminum's molar mass. Then by the stoichiometric relationship, we can find out how many moles of copper would theoretically be formed and then convert that number to grams by using the molar mass of copper.

Once the theoretical yield is found, we use the actual yield (4.65 grams) to calculate the percent yield using the following formula:

percent yield = (actual yield / theoretical yield) x 100%

Note that in some cases, the theoretical yield may need to be determined by other means, such as by identifying the limiting reactant if not all reactants are in excess. For the provided example, the theoretical yield can be calculated directly since the aluminum is limiting and is completely consumed in the reaction.

Answer:

B. 159.6 g

Explanation:

balanced reaction:

∴ moles taht react of Fe = 2 mol

∴ mm Fe = 55.845 g/mol

⇒ g Fe2O3 = ?

∴ moles Fe2O3 = ( 2 mol Fe )×( 2 mol Fe2O3/ 4 mol Fe ) = mol Fe2O3

∴ mm Fe2O3 = 159.6882 g/mol

⇒ g Fe2O3 = ( 1 mol Fe2O3 )×( 159.6882 g/mol) = 159.6882 g

Answer:

1.06 g/cm³

Explanation:

Data given:

volume of liquid = 95.5 cm³

mass of the liquid = 101 g

density = ?

Solution:

To calculate density formula will be used

                   d = m/v

where

d = density

m = mass

v = volume

put values in above formula

                  d =  101 g / 95.5 cm³

                  d = 1.06 g/cm³

so. the density of liquid = 1.06 g/cm³

Final answer:

The density of a liquid, given its mass is 101 grams and volume is 95.5 cm³, is calculated using the formula Density = Mass / Volume, resulting in a density of 1.057 g/cm³.

Explanation:

The question asks to calculate the density of a liquid when given its mass and volume. Density is found by dividing the mass of a substance by its volume. We can use the formula Density = Mass / Volume to find the answer.

In this case, the mass of the liquid is 101 grams and the volume is 95.5 cm3. Plugging these values into the formula gives:

Density = 101 grams / 95.5 cm3 = 1.057 g/cm3.

Therefore, the density of the liquid is 1.057 g/cm3.

Answer:

               The H⁺ concentration in solution is increased by an Acid.

Explanation:

To understand this we will simply define each given option.

An Acid:

             Is any specie which when dissolved in water increases the concentration of Hydrogen Ions (i.e. H⁺) like HCl, or donated H⁺ to base like HBr or accepts lone pair electrons like BF₃.

Salt:

      Salt is formed from the neutralization reaction of Acid and Base. So, when the salt is formed it decreases both the concentration of H⁺ or Hydroxide ions if present.

Base:

          It is any specie which when dissolved in solution produces hydroxyl ions like NaOH, or accepts proton or donate lone pair of electrons like :NH₃.

Water:

          Water is neither an acid nor a base. It is a neutral compound which on ionization produces hydroxyl and hydrogen ions at the same time which at that time neutralize each other. Hence, we can conclude that water does not increase the concentration of H⁺ ions.

Answer:

The density of a substance is the same regardless of the amount.

Explanation:

Option B

25°C and 1 M reactants are the standard conditions under which reduction potentials are measured

Explanation:

A reduction potential contains the drift of a particle to be subdued by exerting up supplementary particles. The standard reduction potential is the reduction potential of a particle beneath particular, regular situations. Standard reduction potentials can be beneficial in discovering the directionality of a reaction.

This is usually estimated in volts. Proportionately variety has its individual inherent reduction potential.  The standard reduction potential is regulated beneath conventional circumstances: 25 °C and 1 M concentration for all ion engaging in the reaction

Answer:

60

Explanation:

60