Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing the direction for each of three successive vehicles. (Enter your answers in set notation. Enter EMPTY or ∅ for the empty set.)(a) List all outcomes in the event A that all three vehicles go in the same direction.A = (b) List all outcomes in the event B that all three vehicles take different directions.B = (c) List all outcomes in the event C that exactly two of the three vehicles turn right.C = (d) List all outcomes in the event D that exactly two vehicles go in the same direction.D = (e) List outcomes in D'.D' = List outcomes in C ∪ D.C ∪ D = List outcomes in C ∩ D.C ∩ D =

Answers

Answer 1

Answer:

a. A = {RRR,LLL,SSS}

b. B = {RLS, RSL, LSR, LRS, SRL, SLR}

c. C = {RRS, RRL, RSR, RLR, LRR, SRR}

d. D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

Step-by-step explanation:

a..

All three vehicles go in the same direction

This means that all the three vehicles either go straight, or right or left at the same time.

So, A { {RRR, LLL, SSS}

b..

All three vehicles take different directions

Thus means that all the vehicle take different routes

If a vehicle takes the the straight direction, the other 2 vehicles take right and left directions respectively

So, B = {RLS, RSL, LSR, LRS, SRL, SLR}

c..

Exactly two of the three vehicles turn right

This means that two vehicles take right direction while the last vehicle either tske the straight route or left route.

C = {RRS, RRL, RSR, RLR, LRR, SRR}

d..

Exactly two vehicles go in the same direction.

The means that if two vehicles pass straight direction then the third vehicle takes either the right or left direction.

Also, if two vehicles pass right direction, the third vehicle either takes the left direction or straight direction

Lastly, if two vehicles pass left direction then the third vehicle either pass the straight direction or right direction.

D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D = the union of items in C and D without repetition

So,

C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = Common items in C and D

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

List outcomes in D'.D' = List outcomes in C ∪ D.C ∪ D = List outcomes in C ∩ D.C ∩ D =

Answer 2
Final answer:

The question presents various scenarios of successive vehicles choosing directions. Outcomes are determined in cases where all vehicles choose the same direction, all choose different directions, exactly two choose right, exactly two choose the same direction (any), and the negation of the latter case. The outcomes of combining these scenarios (union and intersection) are also defined.

Explanation:

The events refer to the outcomes of the directions three successive vehicles could potentially take. There are three possibilities: right (R), left (L), or straight (S).

(a) Event A where all three vehicles go in the same direction, would include these outcomes: A = {RRR, LLL, SSS}.

(b) Event B where all three vehicles take different directions, would look like this: B = {RLS, RSL, LRS, LSR, SRL, SLR}.

(c) Event C where exactly two of the three vehicles turn right would include these outcomes: C = {RRS, RRL, SRR, LRR, RSR, RLR}.

(d) Event D where exactly two vehicles go in the same direction, would include these outcomes: D = {RRS, RRL, SRS, SSL, LRL, LLR, RRS, RLS, RSS, LSS, SLL, LLS, SSR, SRL, SRR, LLR, LRS, LRR}.

(e) Event D' which stands for everything that's not in event D, includes these outcomes: D' = {RLS, SLR, LRS, RSL, LSR, SRL}.

The union of events C and D, C ∪ D, combines the outcomes of both C and D, but without repetition: C ∪ D = {RRS, RRL, SRS, SSL, LRL, LLR, RRS, RLS, RSS, LSS, SLL, LLS, SSR, SRL, SRR, LLR, LRS, LRR, RSR, RLR}.

Finally, the intersection of event C and D, C ∩ D, includes only outcomes common to both C and D: C ∩ D = {RRS, RRL, SRR, LRR, RSR, RLR}.

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Related Questions

A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues, what will be the population of moose after 12 years? Show all your work! Round your answer to the nearest whole number.

Answers

Answer:

  7,692 moose.

Explanation:

The table that shows the pattern for this question is:

Time (year) Population

  0                   40

  1                     62

  2                    96

  3                   149

  4                   231

A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.

Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.

Thus you must find both P₀ and r.

1) P₀

  Using the first term of the sequence (0, 40) you get:

   P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀

Then, P₀ = 40

 2) r

Take two consecutive terms of the sequence:

P(0) = 40 r⁰ = 40P(1) = 40 r¹ = 40r = 62P(1) / P(0) = 40r / 40 = 62/40r = 62/40 = 1.55

 

You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55

3) Model

 

Thus, your model is P(x) = 40(1.55)ˣ

4) Population of moose after 12 years

P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.

Tara ran 3 laps around her neighbor for a total of 1 mile yesterday. Today she wants to run 2 over 3 of a mile. How many laps she will need to run around her neighbor

Answers

Answer:

Tara need to run 2 laps today.

Step-by-step explanation:

Number of laps in 1 mile = 3 laps

number of miles she wants to run today = [tex]\frac{2}{3}[/tex]

We need to find the number of lap she need to run today;

Solution:

Now we know that;

in 1 mile = 3 laps

In [tex]\frac{2}{3}[/tex] miles = number of laps in [tex]\frac{2}{3}[/tex] miles

By using Unitary method we get;

number of laps in [tex]\frac{2}{3}[/tex] miles = [tex]3\times\frac{2}{3} = 2\ laps[/tex]

Hence Tara need to run 2 laps today.

A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower cost $329.99. If 30 total mowers were sold and the total sales for a given year was 8379.70, find how many of each type were sold

Answers

Answer:

Therefore, ' 19 ' smaller lawn mover and '11' larger lawn mover were sold.

Step-by-step explanation:

Given:

let the smaller lawn mover  be 'x'

let the larger lawn mower be 'y'

According to condition total mover will be

[tex]x+y=30\\x=30-y[/tex]................( 1 )

and total cost will be given as

[tex]249.99x+329.99y=8379.7[/tex]................( 2 )

To Find:

x =? and y =?

Solution:

Substituting equation 1 in equation 2 we get

[tex]249.99(30-y)+329.99y=8379.7\\7499.7-249.99y+329.99y=8379.7\\80y=880\\\\y=\dfrac{880}{80}\\\\y=11[/tex]

Substituting ' y 'in ( 1 ) we get

[tex]x=30-11=19\\x=19[/tex]

Therefore, ' 19 ' smaller lawn mover and '11' larger lawn mover were sold.

How is the sum expressed in sigma notation?

11 + 17 + 23 + 29 + 35 + 41

Answers

Answer:

The given sums 11+17+23+29+35+41  can be written as in sigma notation is  [tex]\sum\limits_{i=1}^{6}5+6i[/tex]

Therefore 11+17+23+29+35+41=[tex]\sum\limits_{i=1}^{6}5+6i[/tex]

Step-by-step explanation:

Given series is 11+17+23+29+35+41

To find the given sum expressed in sigma notation :

11+17+23+29+35+41  can be written as the given sums in sigma notation is  [tex]\sum\limits_{i=1}^{6}5+6i[/tex]

That is

11+17+23+29+35+41=[tex]\sum\limits_{i=1}^{6}5+6i[/tex]

Now expand the sums and to verify that whether the summation is true or not :

[tex]\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))[/tex]

[tex]=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)[/tex]

[tex]=11+17+23+29+35+41[/tex]

Therefore 11+17+23+29+35+41=[tex]\sum\limits_{i=1}^{6}5+6i[/tex]

The sum can be expressed as [tex]\sum_{(i=1)}^6 = 5+6i[/tex].

Given to us,11 + 17 + 23 + 29 + 35 + 41

As we can see in the following series,

Every number in the series can be expressed in the form of (5+6i) where i is the position of the series,

11 = 5 + 6(1),17 = 5 + 6(2),23 = 5 + 6(3),29 = 5 + 6(4),35 = 5 + 6(5),41 = 5 + 6(6),

Verification

The sum can be verified by expanding the sum from i=1 to6.

[tex]\sum_{(i=1)}^6 = 5+6i\\\sum_{(i=1)}^6 = [5 + 6(1)]+[5 + 6(2)]+[5 + 6(3)]+[5 + 6(4)]+[5+ 6(5)]+[5 + 6(6)]\\\sum_{(i=1)}^6 = 11 + 17 + 23 + 29 + 35 + 41\\\sum_{(i=1)}^6 = 156[/tex]

therefore, the sum can be expressed as,

[tex]\sum_{(i=1)}^6 = 5+6i[/tex].

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A small farm field is a square measuring 350 ft on a side. What is the perimeter of the field? If you double the length of each side of the field what is the new perimeter

Answers

Answer:The new perimeter of the field is 2800 feet.

Step-by-step explanation:

The formula for determining the area of a square is expressed as

Area = 4L

Where L represents length of each side of the square.

The small farm field is a square measuring 350 ft on a side. This means that the perimeter of the field would be

Perimeter = 350 × 4 = 1400 feet.

If you double the length of each side of the field, the new length would be

350 × 2 = 700 feet.

The new perimeter of the field would be

700 × 4 = 2800 feet

Bryan earned $9 per hour walking dogs. He paid $20 to print some flyers to advertise his dog walking business. After his expenses, he had $52. How many hours did he walk dogs? Let h= the number of hours Bryan walked the do

Answers

Answer:

bryan walked dogs for 5.8 hours

Step-by-step explanation:

if he had $52 and the walk per hour is $9

you have to divide 52/9

52/9 is 5.77777777777...

after you roud it to the nearest tenth that is 5.8

Bryan earned $9 per hour and had a $20 expense for flyers. After subtracting his expenses from his net income of $52, we can set up an equation to find the number of hours he worked, which is 8 hours.

Let h equal the number of hours Bryan walked dogs.

Calculate his earnings by multiplying h by the rate per hour, which is $9.

Subtract his expenses, which are $20 for the flyers, from his earnings to find his net income.

Set up the equation: 9h - 20 = $52.

Add $20 to both sides of the equation to isolate the term with h on one side: 9h = $52 + $20.

Simplify the right side of the equation: 9h = $72.

Divide both sides by 9 to solve for h: h = $72 ÷ 9.

Solve for h: h = 8.

Therefore, Bryan walked dogs for 8 hours to earn a net income of $52 after his $20 expense on flyers.

Sophia pays a$9.99 membership fee for Apple Music. A. If Sophia purchases n songs for $0.99 each,write an expression for the total cost. B. If she buys two songs from a new album at a price of $0.99 each ,use your expression from part A to determine the total cost?.

Answers

Answer: A) 0.99n + 9.9

B) the total cost is $11.88

Step-by-step explanation:

Let n represent the number of songs that Sophia purchases.

A) Sophia pays a $9.99 membership fee for Apple Music. If Sophia purchases n songs for $0.99 each,then an expression for the total cost would be

0.99n + 9.9

B) If she buys two songs from a new album at a price of $0.99 each, it means that the total cost would be

0.99 × 2 + 9.9

= 1.98 + 9.9

= $11.88

If y(x) = -2x2+3 and v(x) = x, what is the range of (Jov(x)?
(3.00)
(-60,3)
0 (0o,00)

Answers

Answer:

The answer to your question is (-∞, 3)

Step-by-step explanation:

Data

y(x) = -2x² + 3

v(x) = x

Process

1.- Evaluate y(x) in v(x)

   yov(x) = -2(x)² + 3

   yov(x) = -2x² + 3

2.- Graph the function

In the graph we observe that the posible values of "y" are from (-∞, 3) that is the range.

Samples of size n=600 are taken from a telephone survey and the mean age is taken from each sample. What is the distribution of the sample means?

A. not enough infomation
B. skewed to left
C. normal
D. skewed to right

Answers

Final answer:

The distribution of the sample means from samples of size n=600 is a normal distribution, according to the Central Limit Theorem, option C.

Explanation:

When samples of size n=600 are taken and the mean age is calculated from each sample, the distribution of sample means is best described by a normal distribution. This is due to the Central Limit Theorem which states that as the sample size becomes large (n ≥ 30 is a commonly used threshold), the sampling distribution of the sample means will tend to be normal regardless of the shape of the population distribution.

This property of the distribution of sample means applies as long as the samples are taken with replacement or if sampling without replacement, the population is at least ten times larger than the sample. In this case, with a sample size of 600, which is well above 30, we can confidently expect the distribution of sample means to follow a normal distribution.

Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?A. 5 : 1B. 10 : 5C. 15 : 2D. 20 : 2E. 25 : 2

Answers

Final Answer:

The correct simplified ratio of US to British stamps is 25 : 2, which corresponds to answer choice E.

Explanation:

To determine the ratio of US to British stamps, we must use the given ratios of US to Indian and Indian to British stamps.

The given ratio of US to Indian stamps is 5 to 2. This means for every 5 US stamps there are 2 Indian stamps. We can represent this as:

US : Indian = 5 : 2

The given ratio of Indian to British stamps is 5 to 1. This implies that for every 5 Indian stamps, there is 1 British stamp. We can write this as:

Indian : British = 5 : 1

To find the ratio of US to British stamps, we need to combine these two ratios. To do this, we should express each ratio such that the Indian stamp part of each ratio is the same. Since the ratios already have the same number of Indian stamps (5 of them), we can directly multiply the US part by the British part across these ratios.

Thus, we multiply the number of US stamps (5 from the first ratio) by the number of British stamps (1 from the second ratio):

US to British = 5 (US) * 1 (British)
US to British = 5

Since we did not have to multiply the number of British stamps by anything (they were only multiplied by 1), the British part of the ratio remains unchanged.

Next, we multiply the Indian part of the first ratio by the British part of the second ratio:

Indian to British = 2 (Indian from the first ratio) * 5 (British from the second ratio)
Indian to British = 10

Now we can combine these two results to express the US to British ratio:

US to British = 5 (US) : 10 (British)

To simplify this ratio, we divide both sides by the common factor between them. In this case, that common factor is 5. So when we divide both numbers by 5, we have:

US to British = (5/5) : (10/5)
US to British = 1 : 2

However, this is not the option given in the question. Let's revisit the calculation and see if there was an error:

The correct approach to combining the ratios is to multiply the two ratios directly:

US : Indian = 5 : 2
Indian : British = 5 : 1

Multiplying across gives us:

US : British = (5 * 5) : (2 * 1)
US : British = 25 : 2
The correct simplified ratio of US to British stamps is 25 : 2, which corresponds to answer choice E.

A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues, what will be the population of moose after 12 years? Show all your work! Round your answer to the nearest whole number.

Time (year) Population
0 40
1 62
2 96
3 149
4 231

Answers

Answer:

7,692 moose.

Explanation:

First, you must find the pattern behind the set of data in the table shown in the question.

It is said that this is a growing exponentially pattern. Thus, the data should be modeled by a function of the form P(x) = A(B)ˣ.

And you must find both A and B.

Finding the multiplicative rate of change (B).

B is the multiplicative rate of change of the function which is a constant that you can find by dividing consecutive terms:

62/40 = 1.5596/62 ≈ 1.548 ≈ 1.55149/96 ≈ = 1.552 ≈ 1.55231/149 ≈ 1.550 ≈ 1.55

Thus, B = 1.55

Finding the initial value A

So far, you know P(x) = A (1.55)ˣ

To find A, you can use P(0)=40, which drives to:

40 = A (1.55)⁰ = A(1) = A

Thus, your function is P(x) = 40(1.55)ˣ

Finding the answer to the question

The population of moose after 12 years, is given by P(12):

P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692

Thus, round to the nearest whole number, those are 7,692 moose.

George is twice as old as Edward, and Edward's age exceeds Robert's age by 4 years. If the sum of the three ages is at least 56 years, what is Robert's minimum age?

Answers

Answer:Robert's minimum age is 11 years.

Step-by-step explanation:

Let x represent George's age.

Let y represent Edward's age.

Let z represent Robert's age.

George is twice as old as Edward. It means that

x = 2y

Edward's age exceeds Robert's age by 4 years. It means that

z = y - 4

If the sum of the three ages is at least 56 years, it means that

x + y + z ≥ 56 - - - - - - - - - - 1

Substituting x = 2y and z = y - 4 into equation 1, it becomes

2y + y + y - 4 ≥ 56

4y - 4 ≥ 56

4y ≥ 56 + 4

y ≥ 60/4

y ≥ 15

z = y - 4 = 15 - 4

z ≥ 11

Final answer:

To find Robert's minimum age, we need to calculate the ages of Edward, George, and Robert based on the given information.

Explanation:

Minimum Age Calculation:

Let's denote the age of Edward as E, George as 2E (twice as old as Edward), and Robert as E - 4 (Edward's age exceeds Robert's by 4 years).

The sum of their ages is at least 56, so E + 2E + (E - 4) ≥ 56.

Solving the inequality, we get E ≥ 20, George's age (2E) is at least 40, and Robert's minimum age (E - 4) is at least 16.

The cold water faucet can fill a sink in 2 minutes. The drain can empty a full sink in 3 minutes. If the faucet were left on and the drain was left open, how long would it take to fill the sink?

Answers

Answer:

6 minutes

Step-by-step explanation:

Let the volume of the sink be Xm^3

The rate of filling the sink by the first faucet is R1 while the rate of draining the faucet is -R2(negative since it’s draining)

R1 = x/2

R2 = -x/3 ( negative as it is draining)

The time it would take both of them working at the same rate to fill the sink is as follows:

x/(R1 - R2) = T

x/( x/2 - x/3) = T

x = T(x/2 - x/3)

x = T( (3x - 2x)/6)

x = T(x/6)

x = Tx/6

6x = Tx

T = 6 minutes

A garden contains 110110 ​flowers, each of which is either red or orange. There are 5555 orange flowers. If R represents the number of red flowers in the​ garden, what equation could you use to find the value of​ R?

Answers

Answer:

The equation use to find the value of R is [tex]55+R=110[/tex].

Step-by-step explanation:

Given:

Total Number of flowers = 110

Number of orange flowers = 55

Let the number of red flowers be represented by 'R'

We need to find the equation used to find the value of R.

Solution:

Now we know that;

Total Number of flowers is equal to sum of Number of orange flowers and Number of red flowers.

representing in equation form we get;

[tex]55+R=110[/tex]

Hence The equation use to find the value of R is [tex]55+R=110[/tex].

On Solving the above equation we get;

We will subtract both side by 55 using Subtraction property of equality.

[tex]55+R-55=110-55\\\\R=55[/tex]

Hence There are 55 red flowers in the garden.

22. Model each situation below with an equation. Select the correct equation for each situation. Then solve each problem. A. A company employs 72 workers. It plans to increase the number of employees by 6 per month until it has twice its current workforce. How many months will it take to double the number of employees?

Answers

Answer:

The equation representing the the scenario is [tex]72+6m=144[/tex].

It will take 12 month for the company to doubled the number of employees.

Step-by-step explanation:

Given:

Number of employees in the company =72

Number of employee increase per month = 6

We need to find the number of months required to double the number of employees.

Solution:

Doubled number of employees = [tex]2\times[/tex] Number of employees = 144

Let the number of months be 'm'

So we can say that;

Doubled number of employees is equal to Current number of employees in the company plus Number of employee increase per month multiplied by number of months.

framing in equation form we get;

[tex]72+6m=144[/tex]

Hence The equation representing the the scenario is [tex]72+6m=144[/tex].

On solving the above equation we get;

we will subtract both side by 72 we get;

[tex]72+6m-72=144-72\\\\6m=72[/tex]

Dividing both side by 6 we get;

[tex]\frac{6m}{6}=\frac{72}{6}\\\\m =12[/tex]

Hence It will take 12 month for the company to doubled the number of employees.

If you flip a coin and roll a 666-sided die, what is the probability that you will flip a tails and roll at least a 222?

Answers

Answer:

5/12

Step-by-step explanation:

For a coin

Number of sample space = 2

Probability of flipping a tail = 1/2

P(T) = 1/2

For a die

Number of sample space = 6

Let D be the event of rolling at least 2.

D = {2,3,4,5,6}

P(D) = 5/6

P(T) and P(D) = P(T) * P(D)

= 1/2 * 5/6

= 5/12

Answer:

1/12

Step-by-step explanation:

got it right

What is (-7)^2 × (-7)?

I will mark the Brainliest, thank, and comment!

Thank you!

Answers

Answer:

The answer is -343.

Step-by-step explanation:

If a term doesn't have an exponent, it's considered that the exponent is 1 (so basically, (-7)² x (-7)^1.

Multiply the terms with the same base (by adding the exponents - (-7)²+1<- (as the exponential value) (couldn't find the sign so sorry.)

Add the numbers: (-7)³

A negative base raised to an odd power equals a negative: -7³

Write the problem out: -(7 x 7 x 7).

Multiply: -343

Find the six trigonometric function values of the angle θ in standard position, if the terminal side of θ is defined by x + 2y = 0, x ≥ 0.

Answers

Answer:

[tex]\sin \theta = \frac{y}r} = \frac{-1}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = -\frac{\sqrt{5}}{5}\\\\\cos \theta = \frac{x}{r} = \frac{2}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = -\frac{2\sqrt{5}}{5} \\\\\tan \theta = \frac{y}{x} = \frac{-1}{2} = -\frac{1}{2} \\\\\cot \theta = \frac{x}{y} = \frac{2}{-1} = -2\\\\\sec \theta = \frac{r}{x} = \frac{\sqrt{5}}{2} \\\\\csc \theta = \frac{r}{y} = \frac{\sqrt{5}}{-1} = -\sqrt{5}[/tex]

Step-by-step explanation:

First, we need to draw the terminal position of the given angle. To do so, we need to find a point that lies on the straight line [tex] x + 2y= 0, x\geq 0 [/tex]

If we choose [tex] x = 2 [/tex] (we can do so because of the condition [tex] x \geq 0 [/tex], which means that any positive value is suitable for [tex] x [/tex]), then we have

[tex] 2 +2y = 0\implies 2 = -2y \implies y = -1 [/tex]

Therefore, the terminal side of the angle [tex] \theta [/tex]  is passing through the origin and the point  [tex] (2,-1) [/tex] and now we can draw it.

The angle  [tex] \theta [/tex]  is presented below.

The distance of the point  [tex] (2,-1) [/tex] from the origin equals

[tex]r = \sqrt{2^2 + (-1)^2} = \sqrt{5}[/tex]

Now, we can determine the values of the six trigonometric function, by using their definitions.

[tex]\sin \theta = \frac{y}r} = \frac{-1}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = -\frac{\sqrt{5}}{5}\\\\\cos \theta = \frac{x}{r} = \frac{2}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = -\frac{2\sqrt{5}}{5} \\\\\tan \theta = \frac{y}{x} = \frac{-1}{2} = -\frac{1}{2} \\\\\cot \theta = \frac{x}{y} = \frac{2}{-1} = -2\\\\\sec \theta = \frac{r}{x} = \frac{\sqrt{5}}{2} \\\\\csc \theta = \frac{r}{y} = \frac{\sqrt{5}}{-1} = -\sqrt{5}[/tex]

Which table represents points on the graph of h(x) = RootIndex 3 StartRoot negative x + 2 EndRoot?

Answers

Answer:

Table 3

Step-by-step explanation:

The third one.

We have the function

                               [tex]h(x) = \sqrt[3]{-x+2}[/tex]

Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:

                  [tex]h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2[/tex]

We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)

Answer:

C

Step-by-step explanation:

HELP❕❗

Simplify:

a^2b^7c^2/a^2c^2

A. ab^7c

B. b^7

C. a^2c^2

D. b^6

Answers

Option B

[tex]\frac{a^2b^7c^2}{a^2c^2} = b^7[/tex]

Solution:

Given that, we have to simplify the given expression

Given expression is:

[tex]\frac{a^2b^7c^2}{a^2c^2}[/tex]

We can simplify the expression by cancelling the common terms in numerator and denominator

Take the common terms out in given expression

[tex]\frac{a^2b^7c^2}{a^2c^2} = \frac{a^2c^2(b^7)}{a^2c^2}[/tex]

Cancel the common terms in numerator and denominator

[tex]\frac{a^2b^7c^2}{a^2c^2} = \frac{a^2c^2(b^7)}{a^2c^2} = b^7[/tex]

Thus the simplified form of given expression:

[tex]\frac{a^2b^7c^2}{a^2c^2}=b^7[/tex]

Thus option B is correct

The material used to make a storage box costs $1.10 per square foot. The boxes have the same volume. How much does a company save on materials by choosing to make 900 boxes using the box with the least surface area?

Answers

Final answer:

We need more data about the box dimensions to calculate the savings. The formula involves multiplying the cost per square foot with the difference in surface areas and number of boxes. The idea of economies of scale isn't directly applicable in this context.

Explanation:

In order to answer this question, we would require additional information about the dimensions of the boxes and their surface areas. The cost difference between making boxes with different surface areas can be found by multiplying the difference in surface areas by the cost per square foot and then by the number of boxes.

The formula used would be: $1.10 (Cost per Square Foot) * Difference in Surface Areas * 900 (Number of Boxes).

In case of economies of scale, like the information provided about alarm clocks, the cost per box would decrease as the number of boxes produced increases. But this concept isn't directly applicable here as we're dealing with the material cost of the boxes, not the production cost.

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To estimate the percentage of defects in a recent manufacturing​ batch, a quality control manager at General Foods General Foods selects every 14th soup cansoup can that comes off the assembly line starting with the sixth sixth until she obtains a sample of 130 soup canssoup cans. What type of sampling is​ used?

Answers

Answer:

Systematic sampling.

Step-by-step explanation:

The systematic sampling is the type of random sampling when the first unit is selected at random from k units and then every kth unit is selected. The k is known as sampling interval which is equal to the population size divided by sample size i.e. N/n.

In the given scenario a quality control manager start with 6th and then every 14th soup canssoup is selected. The sampling units can be selected as  6, 20, 34, 48, 62, 76... and so on. Here the value of k is 14. Thus, the given sampling is the systematic sampling.

Help with #5 above!!!!!

Answers

Answer:  38.66 degrees

==========================================

Explanation:

As you stated in problem 4, tan(angle) = opposite/adjacent

We'll use this idea to help find angle Z. First lets set up the proper tangent ratio for this problem

tan(Z) = XY/YZ

tan(Z) = 8/10

tan(Z) = 0.8

To isolate Z, we need to undo the tangent function. We will use the inverse tangent or the arctangent function to do this.

tan(Z) = 0.8

arctan( tan(Z) ) = arctan(0.8)

Z = 38.6598 which is approximate

This rounds to 38.66

A pet store has 19 goldfish tanks. The store can place 12 fish in each tank. How many goldfish can it keep? Write a division equation with a variable.

Answers

The division equation is: [tex]\frac{x}{19} = 12[/tex]

228 goldfish can be kept

Solution:

Given that,

A pet store has 19 goldfish tanks

The store can place 12 fish in each tank

Let "x" be the number of gold fish that can be kept in tank

From given information,

Number of goldfish tanks = 19

Number of fish kept in 1 tank = 12 fish

We know that,

number of gold fish that can be kept in tank = Number of goldfish tanks x Number of fish kept in 1 tank

[tex]x = 19 \times 12[/tex]

[tex]\frac{x}{19} = 12[/tex]

Thus the division equation is found

On solving we get,

x = 19 x 12 = 228

Thus 228 goldfish can be kept

Levi went to the bookstore traveling 12 mph and returned home traveling 24 mph. If the total trip took 9 hours, how long did Levi travel at each speed?

Answers

Answer:

The answer to your question is

a) t₁ = 6 h

b) t₂ = 3h

Step-by-step explanation:

Data

v1 = 12 mph

v2 = 24 mph

total time = 9 h

Process

1.- Write equations to solve the problem

d₁ = v₁t₁    ------------------ Equation l

d₂ = v₂t₂

d₁ = d₂     because the distance is the same in both directions

t₁ = t₁

t₂ = 9 - t₁

d₂ = v₂(9 - t₁)  -------------- Equation 2

- Equal both equations

    v₁t₁ = v₂(9 - t₁)

- Substitute v₁ and v₂

   12t₁ = 24(9 - t₁)

- Solve for t₁

    12t₁ = 216 - 24t₁

    12t₁ + 24t₁ = 216

              36t₁ = 216

                  t₁ = 216 / 36

                  t₁ = 6 h

- Calculate t₂

t₂ = 9 - 6

t₂ = 3 h

An urn contains four colored balls: two orange and two blue. Two balls are selected at random without replacement, and you are told that at least one of them is orange. What is the probability that the other ball is also orange?

Answers

Answer: 1/5

Step-by-step explanation:

P(both are Orange)

P(at least one is orange)

By using conditional probability:

-The P(both are Orange) is (2C2)/4C2)=1/6

-at least one orange is 1 - 1/6=5/6

P(both are Orange / at least one is orange)=(1/6) / (5/6)

=6/30

=1/5

Final answer:

Given one ball has been established to be orange with no replacement, there are three possible outcomes left in the urn (OO, OB, BO). Only one outcome contains both balls as orange, hence, the probability is 1/3 or approximately 0.333.

Explanation:

Here, we already know that one ball selected is orange from an urn containing two orange and two blue balls. There was no replacement after the first draw, reforming the context of the problem and the counts of the balls in the urn for the second draw.

For the two-draw scenario under question, there are a total of six possible outcomes: (Orange, Orange), (Orange, Blue), (Blue, Orange), (Blue, Blue) - but since we know that at least one ball is orange, the (Blue, Blue) outcome is impossible, leaving us with three valid outcomes. Among these, only one outcome has both balls Orange.

Therefore, the probability that the other ball is also orange, given that at least one is Orange, is 1/3 or approximately 0.333, assuming that all outcomes are equally likely.

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A jar contains 10 red marbles and 15 blue marbles. If you randomly draw two marbles from the jar (without replacement), what is the probability that they are the same color?

Answers

Answer:

0.5

Step-by-step explanation:

Probability is the possibility of an event happening,

probability = number of required outcomes/ number of possible outcomes

number of red marbles = 10

number of blue marbles = 15

The selection of two marbles  is done without replacement.

Pr( of same color) = RR or BB

which means; (the first is red and second is red) or (the first is blue and the second is blue)

OR in probability means adition while AND means multiplication.

Pr( of same color) = [tex](\frac{10}{25}*\frac{15}{24})+(\frac{15}{25}*\frac{10}{24})[/tex]

                    =[tex]\frac{1}{4} +\frac{1}{4}[/tex]

      =0.5

Probabilities are used to illustrate the chances of an event

The probability that marbles of the same color are picked is 0.50

The numbers of marbles are given as:

[tex]\mathbf{Red =10}[/tex]

[tex]\mathbf{Blue =15}[/tex]

[tex]\mathbf{Total =25}[/tex]

The probability that marbles of the same color are picked is:

[tex]\mathbf{Pr = (Red\ and\ Red) + (Blue\ and\ Blue)}[/tex]

So, we have:

[tex]\mathbf{Pr = (10/25 \times 9/24) + (15/25 \times 14/24)}[/tex]

[tex]\mathbf{Pr = (0.15) + (0.35)}[/tex]

Add

[tex]\mathbf{Pr = 0.50}[/tex]

Hence, the probability that marbles of the same color are picked is 0.50

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A​ quality-control manager randomly selects 80 bottles of soda that were filled on March 11 to assess the calibration of the filling machine. What is the population in the​ study?

Answers

Answer:

Bottles of soda filled on March 11.

Step-by-step explanation:

Population is usually constitutes of the set that contains the set of all possible observation in the undergoing study.

Here, sample known as the part of population consists of 80 bottles selected from the bottles of soda filled on March to check the calibration of filling machine. So, the population in the given scenario consists of the bottles of soda filled on March 11.

How to graph. y = 1/3x + 3

Answers

The y intercept is 3 then do y/x so go up one over 3 for each other point
The Y intercept is 3 and the slope is 1/3. If you would like to see a graph, I would go to desmos.com and plug in your equation

Lisa and Bill made 60 magnets for a craft fair. They sold about 55% of the magnets. Lisa says they sold about 30 magnets. Bill says that they sold about 36 magnets. Could they both be correct? Explain.

Answers

Answer:

Step-by-step explanation:

The total number of magnets that Lisa and Bill made for the craft fair is 60.

They sold about 55% of the magnets. The number of magnets that they sold would be about

55/100 × 60 = 0.55 × 60 = 33

If Lisa says that they sold about 30 magnets, she is correct because if we round off 33 to the nearest ten, it would be 30 magnets.

If Bill says that they sold about 36 magnets, he is wrong because if we round off 36 to the nearest ten, it would be 40 magnets.

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