Mutt and Jeff are running along a path each pushing a cart loaded with rocks. If Mutt's wagon has a mass two times greater than Jeff's and they want to stay together, arriving at their destination at the same time, what must happen?
Answer:
Mutt have to apply twice the larger force than applied by Jeff
Explanation:
Since Mutt and Jeff want to reach the destination at same time
As given that wagon carried by Mutt is twice heavy than wagon of Jeff
Now to reach the destination both of the wagon must be pulled with same acceleration so that both wagon can cover equal distance in equal interval of time
Now we know that
[tex]F = ma[/tex]
since mass of wagon carried by Mutt is twice heavy than wagon of Jeff so here the force applied by Mutt must be twice larger than the force applied by Jeff.
Answer:
Mutt must use twice as much force to push his cart.
Explanation:
yw.
a circular flow of warmer fluid and cooler fluid is called a(n) _________ PLEASE HELP
if grapefruit juice has a ph of 3.0 and egg white have a ph of 8.0, which contains more h+ ions ? how many more ?
Answer:
concentration of H+ ions is more in pH 3.0
Explanation:
As we know that pH of a solution is defined as
[tex]pH = - Log H^+[/tex]
here we know that grape fruit has pH given as 3
[tex]3 = - Log H^+[/tex]
[tex]H^+ = 10^{-3}[/tex]
Now for pH of 8 type solutions we will have
[tex]8 = - Log H^+[/tex]
[tex]H^+ = 10^{-8}[/tex]
So concentration of H+ ions is more in pH 3.0
The prefix kilo- means
When a pendulum swings,if it is not continuously pushed, it will stop eventually because some of its energy is changed into ____ energy?
When a candle burns, which forms of energy does the chemical energy in the candle change to?
A charge of 40 µC is pushed by a force of 15 µN a distance of 1.3 mm in an electric field. What is the electric potential difference?
Answer:
ΔV=V1-V2 = 27692307.69volts
Explanation:
Hello! Let's solve this!
The formula to calculate the power difference is
ΔV=V1-V2
V = k * (q / r)
k is a constant that equals [tex]k=9*10^{9}N*m^{2}/C^{2}[/tex]
The data we have are:
[tex]k=9*10^{9}N*m^{2}/C^{2}[/tex]
r = 0.0013m
[tex]q1=40*10^{-6}C\
F=15*10^{-6} N[/tex]
From the following formula we can calculate how much q2 is
F = k * (q1 * q2 / r2)
q2 = (F * r2) / (k * q1)
q2 = (15*10^{-6} N[/tex] * 0.00132) / (9*10^{9}N*m^{2}/C^{2}[/tex] *40*10^{-6}C\)
[tex]q2=7.0417x^{-17}C[/tex]
Now we calculate with q1 and q2, V1 and V2 respectively.
V1 = (9*10^{9}N*m^{2}/C^{2}[/tex] * 40*10^{-6}C\) /0.0013m
V1 = 27692307.69 volts
V2 = (9*10^{9}N*m^{2}/C^{2}[/tex] * 7.0417x^{-17}C[/tex]) /0.0013m
[tex]V2=4.875*10^{-4}volts[/tex]
Then we solve the potential difference:
V1-V2 = 27692307.69 volts-4.875*10^{-4}volts[/tex]
ΔV=V1-V2 = 27692307.69volts
Answer:
C. 4.9 × 10-4 V
Explanation:
ΔV = E d
E = force/charge = 15 µN / 40 µC = 0.375 N/C
ΔV = 0.375 N/C * 0.0013 m = C. 4.9 × 10-4 V
A cat pushes a ball from a 7.00 m high window, giving it a horizontal velocity of 0.20 m/s. how far from the base of the building does the ball land? (assume no air resistance and that ay= g = 9.81 m/s2.)
Assuming constant temperature, what volume would a gas occupy at 82.3 kpa if the volume is 344 cm3 at 110 kpa
what is the force driving all of these transport mechanisms?
Active transport includes the utilization of vitality to move particles against a main impetus or, as such, up an electrochemical angle. There are two essential types of Active transport: Primary active utilizes the vitality source (ATP) to straightforwardly ship atoms.
Further Explanation:
Force driving:
Main impetus is a term having more extensive importance than the term Force. To place it in basic words, the Cause of any wonder in nature is the Driving Force of/in that marvel. This reason can likewise be an option that is other than the Force (as saw by and large, which is mechanical power estimated in Newton or pounds).
transport mechanism:
To move substances against a focus or electrochemical angle, a cell must utilize vitality. Dynamic vehicle components do only this, consuming vitality (frequently as ATP) to keep up the correct centralizations of particles and atoms in living cells.
the two kinds of transport machanism:
The two principle kinds of transport into and out of cells incorporate aloof transport and dynamic transport.
Active transport:
Active transport is the development of particles over a film from an area of their lower focus to a locale of their higher fixation against the focus inclination. Dynamic vehicle requires cell vitality to accomplish this development.
Passive transport:
Passive transport is a development of particles and other nuclear or atomic substances crosswise over cell layers without need of vitality input. In contrast to Active transport, it doesn't require a contribution of cell vitality since it is rather determined by the propensity of the system to develop in entropy.
Subject: physics
Level: High School
Keywords: Force driving, transport mechanism, the two kinds of transport mechanism, Active transport, Passive transport.
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The force driving all of these transport mechanisms is the diffusion down the concentration gradient.
Diffusion is the process of movement of molecules under the higher-to-lower concentration gradient. Transport by diffusion of the molecule down its concentration gradient. The transport mechanism is a spontaneous process that requires no energy.
The transport mechanism is of two types that transport molecules through any biological membrane. These are active and passive transport. Passive transport is the common mechanism called diffusion, which occurs along a concentration gradient from high to low concentration. No energy is required for this process.
Hence, the force driving all of these transport mechanisms is because of diffusion down the concentration gradient.
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During a fission each time an atom divides ___.
Half the energy released
More energy released
Double the energy is released
a car slows down from 28m/s to rest in a distance of 88m. what was its acceleration assumed constant?
Answer:
The acceleration of the car was -4.4545 m/sec² where the negative sign indicates deceleration (decrease in acceleration)
Explanation:
To answer this question, we will use the following equation of motion:
v² = u² + 2as
where:
v is the final velocity = 0 m/sec (car became at rest)
u is the initial velocity = 28 m/sec
a is the acceleration we want to find
s is the distance covered = 88 m
Substitute with the givens in the equation to get "a" as follows:
v² = u² + 2as
0 = (28)² + 2(a)(88)
0 = 784 + 176a
176a = -784
[tex] a = \frac{-784}{176} [/tex] = -4.4545 m/sec²
Hope this helps :)
Mass is 80g. Volume is 40ml. What is the density?
It takes 100 n to move a box 10 meters in 5 seconds. how much power is required?
Answer: 200 w in apex
Why do you think the area swept out by a planet in a given period of time remains constant, even as the planet speeds up and slows down?
Answer:
Since there is no torque on the planet with respect to position of Sun
So the angular momentum of the planet is always constant
hence the rate of change in area with respect to sun is always constant
Explanation:
As we know that rate of area swept by the planet is given as
[tex]v_a = \frac{dA}{dt}[/tex]
here we know that small area swept by the planet is given as
[tex]dA = \frac{1}{2}r^2\theta[/tex]
now rate of area swept by the planet is given as
[tex]\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}[/tex]
[tex]\frac{dA}{dt} = \frac{1}{2}r^2\omega[/tex]
so we have
[tex]\frac{dA}{dt} = \frac{1}{2m}(mr^2\omega)[/tex]
here we know that angular momentum of the planet with respect to sun is given as
[tex]L = mr^2\omega[/tex]
so we have
[tex]\frac{dA}{dt} = \frac{L}{2m}[/tex]
since we know that there is no torque on the system of planet with respect to sun
So angular momentum of the planet will remain constant
hence we can say
[tex]\frac{dA}{dt} = \frac{L}{2m}[/tex] = constant always
Which layer of the earth takes up the most of earth's volume?
If you average 22.8 meters/min, how many seconds will it take you to travel 467 m?
A woman flies 300 kilometers north, 200 kilometers west, and 500 kilometers south. How far is she from her starting point?
The woman is 282.84 kilometers far from her starting point. The distance is calculated from the given values that women travel.
Given:
The distance covered in the north direction = 300 km
The distance covered in the west direction = 200 km
The distance covered in the south direction = 500 km
The net displacement between the south and north points are:
Distance from the South direction - Distance from the North direction
D = 500 - 300
D = 200 km
From Pythagoras's theorem, the distance from the starting point is:
Distance = √[(200 km)² + (200 km)²]
Distance = √(40000 km² + 40000 km²)
Distance = 282.84 kilometers
Hence, the woman is 282.84 kilometers far from her starting point.
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How much time should be allowed for a 605-mile car trip if the car will be traveling at an average speed of 55 miles per hour? A. 8.75 hours B. 10.5 hours C. 11 hours D. 9 hours
What is the largest mountain free land area in europe it stretches 2000 miles?
The East European Plain is the largest mountain-free land area in Europe. It expands roughly 2000 miles and has a variety of geographic features including ice blocks reaching 2 to 3 kilometers in height.
Explanation:The largest mountain-free land area in Europe is the East European Plain, also known as the Russian Plain. This geographical feature stretches for about 2000 miles and is roughly a thousand kilometers wide. The structure of the East European Plain exhibits intriguing cells or polygons that have an average width of more than 30 kilometers.
Despite no large mountains, the Plain shows diversity with some areas like the ice blocks in the middle, which are of frozen water and reach heights of nearly 2 to 3 kilometers. This example lends an interesting insight into the geomorphological features of the area despite not being classified as a mountain.
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What is the relationship between the horizontal and vertical components of velocity for a projectile launched at an angle between 0° and 90°?
A) Each is independent of the other.
B) Each is dependent on the other.
C)The horizontal component is dependent on gravitational acceleration.
D)The horizontal component decreases with an increase in the vertical component.
Answer:
A. Each is independent of the other.
Hope this helps!
Explanation:
The vertical velocity of a projectile is unaffected by the horizontal velocity; these two components of motion are independent of each other.
Most engines will contain how many cylinders in order to maintain a proper balance of weight and forces? A. An even number B. Always six C. An odd number D. Always four
Answer:
Cylinder is the most important working part of the engine it is arranged adjacently in the engine.
So, we need to tell how many cylinders are there in order to maintain a proper balance.
So, Some engines have 6 some have 4 cylinders.
So., always 6 and always 4 that is option B and D are discarded.
Therefore, The option A is correct that is an even number.
When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains this?
a) Gases do not have a definite volume.
B)The particles of gases are closely packed.
C)The force of attraction between particles in gases is very high.
D)Gases are not matter.
Answer:
Gases do not have definite volume.
Explanation:
Solids, liquids and gas are three forms of matter. Solids have fixed shape and volume. Liquids do not have fixed shape but have fixed volume. Gases neither have fixed shape nor volume. The particles of solid are tightly packed whereas the particles of gas are very loosely packed and the force of attraction between the particles of gas is very weak.
When the perfume bottle is opened, some liquid changes to gas and fragrance spreads around the room because the particles of gas are very loosely packed and the force of attraction between the particles of gas is very weak. The gas particles do not have fixed volume and easily spread.
Why does all light have a wavelength between about 400 and 700 nm?
The race officials want to set up portable bleachers near the finish line. Each set of bleachers is 4.50 meters long and 2.85 meters wide. How many square meters of open ground space do they need for each set?
The amount of open ground space needed for each set of bleachers is 12.825 square meters.
To calculate the area required for the portable bleachers, which are 4.50 meters in length and 2.85 meters in width, we multiply the length by the width. Thus, the area (A) is given by the formula A = length imes width. By substituting the given dimensions, A = 4.50 m imes 2.85 m = 12.825 m2. This calculation provides the total ground space necessary for setting up a single set of bleachers, assuming that no additional space is required for clearances or walkways between the bleachers.
A swimmer heading directly across a river 200 m wide reaches the opposite bank in 6 min 40 s. she is swept downstream 480 m. how fast can she swim in still water?a swimmer heading directly across a river 200 m wide reaches the opposite bank in 6 min 40 s. she is swept downstream 480 m. how fast can she swim in still water?
Final answer:
The swimmer's speed in still water is determined by dividing the river width (200 m) by the total swimming time (400 s), which gives a speed of 0.5 m/s.
Explanation:
The question involves calculating the speed at which a swimmer can swim in still water. The swimmer crosses a 200 m wide river and is swept downstream 480 m, reaching the opposite bank in 6 minutes and 40 seconds. To determine the speed in still water, we'll need to consider two components of the swimmer's velocity: one perpendicular to the river's flow (the swimmer's own speed in still water) and one parallel to the flow (the river's current).
Let v be the speed of the swimmer in still water (m/s) and u be the speed of the river current (m/s). The swimmer's downstream displacement due to the current is 480 m, which is equivalent to u × t, where t is the total swimming time. The total time taken is 400 seconds (6 min 40 s).
The perpendicular component of the swimmer's motion relative to the river banks is 200 m, which should be equal to v × t. From this, we can solve for v by dividing the river width by the total swimming time:
v = 200 m / 400 s = 0.5 m/s
Thus, the swimmer's speed in still water is 0.5 m/s.
A ray of violet light has a wavelength of about 4.2×10−7 m. will exposure to violet light cause electrons to be emitted from cesium?
Yes, violet light cause electrons to be emitted from caesium.
Given that;
A ray of violet light has a wavelength of about 4.2×10⁻⁷ m.
When exposed to violet light, caesium does have the potential to emit electrons through a phenomenon called the photoelectric effect.
The photoelectric effect occurs when light, in this case, violet light, transfers its energy to electrons in a material, causing them to be emitted.
The emission of electrons is influenced by factors like the intensity of the light, the frequency (or wavelength) of the light, and the properties of the specific material.
In the case of caesium, violet light with a wavelength of about 4.2×10⁻⁷ m falls within the visible light spectrum and can provide enough energy to cause electron emission.
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Final answer:
The subject is photoelectric effect in physics, where the energy of violet light (wavelength of about 4.2×10−7 m) is compared to cesium's work function to determine if electrons will be emitted.
Explanation:
The question involves the concept of photoelectric effect in physics, where light can cause electrons to be emitted from a material. This phenomenon is governed by the work function of the material, which is the minimum energy needed to remove an electron. For cesium, we need to compare the energy of the violet light (approximately 4.2×10−7 m) to the work function of cesium to determine if photoemission would occur.
Using the photoelectric equation and Planck's constant, we can calculate the energy of the photon and then compare it to the work function of cesium. As discussed in the references provided, certain wavelengths of light, like 420-nm violet light with an energy of 2.96 eV, are just above the threshold frequency for materials like calcium. Since the threshold wavelength for cesium is not directly provided, we need to look at the stopping potential mentioned (0.33V for 546nm light for cesium), which gives a hint about the work function of cesium. We understand that if the photon's energy is higher than this work function, electrons will be emitted.
The law of reflection states that if the angle of incidence is 62 degrees, the angle of reflection is degrees.
By how many degrees fahrenheit can the temperature of one metric ton of water be raised with the addition of 110 thousand btus of heat?
Final answer:
The amount by which the temperature can be raised is calculated by using the specific heat capacity of water and converting BTUs to joules to find the temperature change in Celsius, which is then converted to Fahrenheit.
Explanation:
To determine by how many degrees Fahrenheit one metric ton of water can be raised with the addition of 110 thousand BTUs of heat, we need to use the specific heat capacity of water and convert the energy from BTUs to a compatible unit.
The specific heat capacity of water is 4.184 joules per gram per degree Celsius (J/g°C). Moreover, the conversion from BTUs to joules is necessary for the calculations. Since 1 BTU corresponds to approximately 1055.06 joules, 110,000 BTUs is equivalent to 110,000 × 1055.06 joules.
A metric ton of water is equal to 1,000,000 grams. Assuming the specific heat capacity of water is 4.184 J/g°C, we can set up an equation to find the temperature change in Celsius, which can then be converted to Fahrenheit.
The heat energy equation is heat energy (Q) = mass (m) × specific heat capacity (c) × temperature change (ΔT).
Q = m × c × ΔT
Substituting our values, we have:
110,000 BTUs × 1055.06 J/BTU = 1,000,000 g × 4.184 J/g°C × ΔT
This gives us the temperature change in Celsius, which can then be multiplied by 1.8 to convert to Fahrenheit.
A student puts air into a balloon and ties it shut. Which action listed below will lead to a decrease in pressure inside the balloon?
A) Leaving the balloon inside a car on a hot, summer day.
B) Compressing the balloon with both hands.
C) Sticking the balloon in a freezer.
D) Taking the balloon to the top of a hill.
Answer:C) Sticking the balloon in a freezer.
Explanation:
Sticking the balloon in a freezer will cause the pressure to drop because the air inside will become colder and lead to the particles having lower kinetic energies. In, turn their rate of collisions will decrease and cause the pressure to drop. Leaving the balloon in a hot car and squeezing the balloon will cause a pressure increase and taking the balloon to the top of a hill may or may not cause a pressure increase.
Answer:
C) Sticking the balloon in a freezer.
Explanation:
When we put the balloon into the freezer then due to decrease in the temperature we can find the effect on its pressure using ideal gas Law
It is given as
[tex]PV = nRT[/tex]
so here on decreasing the temperature if volume is assumed to be constant the pressure is given as
[tex]P = \frac{nR}{V} T[/tex]
so pressure will also decrease on decreasing the temperature
so correct answer will be
C) Sticking the balloon in a freezer.