Round 430 to nearest thousand

The answer is: only one pair of sides is parallel a.k.a b

Answer:

Should be f(x) = x^3 + 3x^2 − x − 3  because this is written in standard form.

Step-by-step explanation:

The value of log₆ 5 as a logarithm of base 4 is,

⇒ log₄ 5 / log₄ 6

We have to given that;

Logarithmic function is,

⇒ log₆ 5

Now, WE can write in as a logarithm of base 4 as;

Since, WE know that;

⇒ logₐ b = logₓ b / logₓ a

Hence, By above rule we get;

⇒ log₆ 5

⇒ log₄ 5 / log₄ 6

Thus, The value of log₆ 5 as a logarithm of base 4 is,

⇒ log₄ 5 / log₄ 6

Learn more about logarithmic equations here:

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The percent of change from the original amount of $90 to the new amount of $84.50 is approximately a 6.11% decrease.

To calculate the percent of change, we need to determine the difference between the original and new amounts, then divide that difference by the original amount and multiply by 100 to get the percentage. In this case, the original amount is $90, and the new amount is $84.50. The difference between these two amounts is $90 - $84.50 = $5.50. We then take this change and divide it by the original amount: $5.50 / $90. Finally, to get the percent change, we multiply by 100:

($5.50 / $90)  times 100 = 6.11%

The percent of change from the original amount of $90 to the new amount of $84.50 is approximately 6.11% decrease.

the solution to the equation [tex]\(0.6(r - 0.2) = 1.8\) is \(r \approx 3.2\).[/tex]

To solve the equation 0.6(r - 0.2) = 1.8, we first distribute the 0.6 to the terms inside the parentheses:

0.6r - 0.6(0.2) = 1.8

0.6r - 0.12 = 1.8

Next, we add 0.12 to both sides of the equation to isolate 0.6r:

0.6r - 0.12 + 0.12 = 1.8 + 0.12

0.6r = 1.92

Now, to solve for r, we divide both sides of the equation by 0.6:

[tex]\[ \frac{0.6r}{0.6} = \frac{1.92}{0.6} \][/tex]

[tex]\[ r = \frac{1.92}{0.6} \][/tex]

[tex]\[ r \approx 3.2 \][/tex]

So, the solution to the equation [tex]\(0.6(r - 0.2) = 1.8\) is \(r \approx 3.2\).[/tex]

The probable question maybe:

solve the equation 0.6(r - 0.2) = 1.8

To have a greater percent increase than private investigators between 2006 to 2016, there must be approximately 760,945 police officers in 2016. This is found by applying the formula for percentage increase and adjusting it to find the required final number.

The percent increase of private investigators from 2006 to 2016 is found by subtracting the initial number from the final number, then dividing by the initial number and multiplying by 100%. This formula gives us (61000 - 52000) / 52000 * 100 = 17.3%, rounded to the nearest tenth of a percent.

To have a greater increase in police officers than that of private investigators, the percent increase must be more than 17.3%. To find the required number of police officers in 2016, we first express 17.3% as a decimal, which is 0.173. Then we use the formula for percentage increase, which is (final number - initial number) / initial number = percentage increase. By rearranging the formula, we get the required final number = (initial number * percentage increase) + initial number. Substituting the given figures, we have (648982 * 0.173) + 648982 = 760945, rounded to the nearest whole number.

Therefore, there must be approximately 760,945 police officers in 2016 to have a greater percent increase than that of the private investigators.

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Algebra problems may not seem like 'real-life' problems, but they help build a deeper understanding of mathematical concepts.

Often, in algebra, you are given problems that may not seem like 'real-life' problems because they are designed to emphasize understanding the underlying concepts rather than simply executing a mathematical recipe. These problems aim to build a more meaningful understanding of the content by focusing on what the numbers represent and how they relate to each other. For example, in the problem 'Twice the sum of a number and 5 is 24. Find the number,' you can practice solving by setting up an equation and using algebraic manipulation to find the number.

The slope-intercept form equation for the word problem is [tex]\( y = \frac{3}{4}x + 1 \).[/tex]

Let's consider a word problem where a local gym charges a $1 sign-up fee and $3 for every hour of use. If we let [tex]\( x \)[/tex] represent the number of hours a member uses the gym and [tex]\( y \)[/tex] represent the total cost, we can write an equation in slope-intercept form.

The slope-intercept form of a linear equation is given by [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope of the line and [tex]\( b \)[/tex] is the y-intercept.

In this scenario, the slope [tex]\( m \)[/tex] is the cost per hour, which is $3. The y-intercept [tex]\( b \)[/tex] is the initial sign-up fee, which is $1.

Therefore, the equation representing the total cost [tex]\( y \)[/tex] as a function of the number of hours [tex]\( x \)[/tex] used at the gym is:

[tex]\[ y = 3x + 1 \][/tex]

However, to make the equation more precise and to express the cost per hour as a fraction, we can write $3 as [tex]\( \frac{3}{1} \)[/tex] and then multiply both the numerator and the denominator by 4 to get [tex]\( \frac{3 \times 4}{1 \times 4} = \frac{12}{4} \)[/tex]. Simplifying the fraction [tex]\( \frac{12}{4} \)[/tex] gives us [tex]\( \frac{3}{4} \)[/tex]per hour.

Thus, the final slope-intercept form equation for the word problem is:

[tex]\[ y = \frac{3}{4}x + 1 \][/tex]

Answer:

A and C

Step-by-step explanation:

A.between 8 and 10 years of age

C.between 10 and 12 years of age

Answer:

69 420 911

Step-by-step explanation:

The circumference of a unit circle is calculated using the formula C = 2πr. For a unit circle, where the radius (r) is 1, the circumference (C) is 2π, approximately 6.2832.

The Circumference of a Unit Circle

In mathematics, the circumference of a circle is the distance around its perimeter. For a unit circle, which is a circle with a radius of 1, the formula to calculate circumference is given by C = 2πr, where r is the radius.

Since the radius of a unit circle is 1, substituting in the formula gives us:

C = 2π(1) = 2π

Thus, the circumference of a unit circle is 2π, which is approximately 6.2832 when using the value of π ≈ 3.1416.

Answer:

The statement satisfied the  expression 10 + x 12 = 12x + 10 is

Option (e) i.e commutative - multiplication and Option (a) i.e commutative - addition .

Step-by-step explanation:

Commutative Property

Let a, b be two numbers thus they satisfied the commutative property

i.e a + b = b + a

As given the expression.

10 + x ×12 = 12x + 10

First apply the Option (e) i.e Commutative - multiplication.

Thus expression becomes

10 + 12x = 12x + 10

Now apply the Option (a) i.e Commutative - addition.

Therefore the statement satisfied the  expression 10 + x 12 = 12x + 10 is

Option (e) i.e commutative - multiplication and Option (a) i.e commutative - addition .

Answer:

D. y = 6x

Step-by-step explanation:

In order to conclude which pair is a real solution to one of these equations, we need to evaluate the point in each equation.

Let:

[tex](x,y)=(2,12)[/tex]

So, this pair will be a solution if when evaluating the value of x=2 in the function the result is y=12.

For A.

[tex]y(x)=\frac{1}{5}x \\\\y(2)=\frac{2}{5} =0.4\neq12[/tex]

This pair is not a solution to this equation.

For B.

[tex]y(x)=\frac{1}{2}x\\\\y(2)=\frac{2}{2} =1 \neq 12[/tex]

This pair is not a solution to this equation.

For C.

[tex]y(x)=2x\\\\y(2)=2*2=4 \neq 12[/tex]

This pair is not a solution to this equation.

For D.

[tex]y(x)=6x\\\\y(2)=6*2=12[/tex]

This pair is a solution to this equation.