Answer:
y+4=7/4(x-3)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-4)=7/4(x-3)
y+4=7/4(x-3)
WILL GIVE BRAINLIEST . (06.02) Which of these is the algebraic expression for "eight less than some number?" (3 points) 8 − b b − 8 Fraction 8 over b Fraction b over 8
Answer: b - 8
Step-by-step explanation:
Answer:
same
Step-by-step explanation:
Find an ordered pair ( x, y ) that is a solution to the equation. 3x+y=7
Answer:
2,1
Step-by-step explanation:
y=-3x+7
y=-3(2)+7
y=-6+7
y=1
so (2,1)
The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y^8 and 30y^6. What is the length and width of the rectangle?
Answer:
Width [tex]10y^6[/tex] units
Length [tex]7y^2+3[/tex] units
Step-by-step explanation:
The rectangle has an area of [tex]70y^8+30y^6.[/tex]
The width of the rectangle is equal to the greatest common monomial factor of [tex]70y^8[/tex] and [tex]30y^6.[/tex] Find this monomial factor:
[tex]70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6[/tex]
Hence, the width of the rectangle is [tex]10y^6[/tex] units.
The area of the rectangle can be rewritten as
[tex]10y^6(7y^2+3).[/tex]
The area of the rectangle is the product of its width by its length, then the length of the rectangle is [tex]7y^2+3[/tex] units.
7. Which of the following equations illustrates the associative property of addition?
(1) (3+7)+(2+8)=(7+3)+(8+2)
(2) (5)(3-4)=(5-3)(4)
(3) (4+5)+5 = 4 +10
(4) 2(5+4)=10+8
3
Answer:
3. (4+5)+5 = 4 +10 expresses the ASSOCIATIVE PROPERTY OF ADDITION.
Step-by-step explanation:
The associative property of addition is given as:
For any three numbers A, B and C
(A +B) + C = A + ( B+ C)
Here, the ORDER OF ADDITION is not important, answer is always the SAME.
Now, in the following given expressions:
1. (3+7)+(2+8)=(7+3)+(8+2)
Here, ( 3+ 7)in L H S is replaced with ( 7 + 3) in R H S
Similarly, ( 2+ 8)in L H S is replaced with (8 + 2) in R H S
Hence, the given expression is expresses the Commutative PROPERTY OF ADDITION.
2. (5)(3-4)=(5-3)(4)
Here, the operation between 5 and (3-4) is MULTIPLICATION
Hence, the given expression DO NOT expresses the ASSOCIATIVE PROPERTY OF ADDITION.
3. (4+5)+5 = 4 +10
Here, the form of ASSOCIATIVE PROPERTY OF ADDITION is
(4 +5 )+5 = 4 + (5 + 5) = 4 + (10)
So, the given expression expresses the ASSOCIATIVE PROPERTY OF ADDITION.
4. 2(5+4)=10+8
Here, the operation between 2 and (5 + 4) is MULTIPLICATION
Hence, the given expression DO NOT expresses the ASSOCIATIVE PROPERTY OF ADDITION.
The associative property of addition means the way numbers are grouped in an addition does not change the sum. From the given equations, equation (1) illustrates this property as shown by the same results 20 in both groupings (3+7)+(2+8) or (7+3)+(8+2).
Explanation:The associative property of addition is a property in Mathematics that states that the way in which numbers are grouped when added does not change the sum. From the given equations, equation (1) (3+7)+(2+8)=(7+3)+(8+2) perfectly shows this property. It demonstrates that it doesn't matter how we group the numbers when we're adding them - the result will be the same.
For example, in equation (1), (3+7)+(2+8), if we add the numbers in brackets first, we get 10 + 10 = 20. This is the same result we get if we re-group the numbers like this: (7+3)+(8+2), that is, 10 + 10 = 20.
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Which expression can be used to check the answer to 56 divided by negative 14 =n
Answer:
n=-4
Step-by-step explanation:
n=56/-14
n=-4
In each pair, tell if the fractions are equal by using cross multiplication.
a. 5/30 and 1/6
b.4/12 and 21/60
c. 17/34 and 41/82
d. 6/9 and 25/36
Answer:
a. 5/30 and 1/6 ---> are equal
b.4/12 and 21/60 ---> are not equal
c. 17/34 and 41/82 ---> are equal
d. 6/9 and 25/36 ---> are not equal
Step-by-step explanation:
case a) we have 5/30 and 1/6
equate the fractions
[tex]\frac{5}{30}=\frac{1}{6}[/tex]
using cross multiplication
[tex](5)(6)=(30)(1)[/tex]
[tex]30=30[/tex] ----> is true
therefore
The fractions are equal
case b) we have 4/12 and 21/60
equate the fractions
[tex]\frac{4}{12}=\frac{21}{60}[/tex]
using cross multiplication
[tex](4)(60)=(21)(12)[/tex]
[tex]240=252[/tex] ----> is not true
therefore
The fractions are not equal
case c) we have 17/34 and 41/82
equate the fractions
[tex]\frac{17}{34}=\frac{41}{82}[/tex]
using cross multiplication
[tex](17)(82)=(41)(34)[/tex]
[tex]1,394=1,394[/tex] ----> is true
therefore
The fractions are equal
case d) we have 6/9 and 25/36
equate the fractions
[tex]\frac{6}{9}=\frac{25}{36}[/tex]
using cross multiplication
[tex](6)(36)=(25)(9)[/tex]
[tex]216=225[/tex] ----> is not true
therefore
The fractions are not equal
Answer:
a. The fractions are equal.
b. The fractions are not equal
c. The fractions are equal.
d. The fractions are not equal
Step-by-step explanation:
By definition, equivalent fractions have the same value, but they look different.
In order to verify if two fractions are equivalent, you can use Cross multiplication.
The procedure is: multiply the numerator of the first fraction by the denominator of the second fraction, and the numerator of the second fraction by the denominator of the first fraction.
Then:
[tex]a.\ \frac{5}{30}=\frac{1}{6}\\\\5*6=1*30\\\\30=30\ (The\ fractions\ are\ equal)[/tex]
[tex]b.\ \frac{4}{12}=\frac{21}{60}\\\\4*60=21*12\\\\240=252\ (FALSE.\ The\ fractions\ are\ not\ equal)[/tex]
[tex]c.\ \frac{17}{34}=\frac{41}{82}\\\\17*82=41*34\\\\1394=1394\ (The\ fractions\ are\ equal)[/tex]
[tex]d.\ \frac{6}{9}=\frac{25}{36}\\\\6*36=25*9\\\\216=225\ (FALSE.\ The\ fractions\ are\ not\ equal)[/tex]
x+6/x+2=x+3/x-5
a. x=1
b. x=5
c. x=-9
d. x=-8
[tex]\dfrac{x+6}{x+2}=\dfrac{x+3}{x-5}\qquad\qquad\text{cross multiply}\\\\(x+6)(x-5)=(x+2)(x+3)\\\\x^2-5x+6x-30=x^2+3x+2x+6\\\\x^2+x-30=x^2+5x+6\\\\x^2+x-x^2-5x=6+30\\\\-4x=36\quad|:(-4)\\\\\boxed{x=-9}[/tex]
Answer C.
you send out 20,000 emails of 6% are opened of those 9% clicked on the link to register for something of those who clicked on the link 30% complete the registration how many people completed the registration
Answer:
The answer is 32.
Step-by-step explanation
hope this helps :D
ChoiceA- f(x)axhk ChoiceB- f(x)axh2 k
ChoiceC- f(x)ax3 bx2 cxd ChoiceD- f(x)a xhk
ChoiceE- f(x) a k xh
Requirements:
*a should never equal 0
*h and k can’t both be 0
*b, c, and d can’t all be 0 *Can’t duplicate any values
TASK #2
1) Select 4 of the 5 graph choices to the left.
2) Fill in values/numbers for the generic equations, replacing variables
a, h, and k or a, b, c, and d as necessary, to create actual equations that can be graphed. You may use your calculator to help. Write this equation at the top of the graph page you use. Recommendation - use small #s☺(keep between -5 and 5)
3) Graph each of the 4 chosen graphs A - E, one on each of the graphs provided, #1 - 4. You may use your calculator to help. Requirements:
*Be sure that part of the graph drawn on its selected graph paper is actually located in the shaded region on the graph you choose. If not, select a different graph paper #1-4 or select different values/numbers for your equation. You may graph any of the equation choices on any of the graph papers.
*You must graph the entire function on the given graph paper for
the domain 15, 15 if the range is also between 15, 15. A
domain interval of at least 15 units wide must be present on the
graph.
4) Answer the questions below Graphs #1-4 in the spaces provided.
1) Take each shaded region (covering a domain interval of 5 units) of graphs 1-4 and graph ONLY that region from that graph onto Graph #5. (You should have a funky looking graph.) Be careful on the endpoints of your graph segment that you either graph a closed dot if including that value or an open dot if you are not including that value – see the domain intervals listed on the bottom of Graph #5 for help!
2) Fill in the information and answer the questions following the graph.
RUBRIC (Turn one copy in with your project):
Graph #1: Graph #2 Graph #3 Graph #4 Graph #5 Comments:
Equation: ____/1 Equation: ____/1 Equation: ____/1 Equation: ____/1 Equations: ____/4
Graph: _____/8 Graph: _____/8 Graph: _____/8 Graph: _____/8 Graph: _____/6
Questions: _____/11 = /20 Questions: _____/11 = /20 Questions: _____/11 = /20 Questions: _____/11 = /20 Questions: _____/10 = /20
TOTAL ______/100
did you ever complete this?
Step-by-step explanation:
If you ddi please send it to me
Adrian just got hired for a new job and will make $66,000 in his first year. Adrian was told that he can expect to get raises of $5,000 every year going forward. how much money in salary with Adriene make in his 26th year working at this job? round to the nearest 10th (if necessary).
Answer:
Adrian would make $196000 in his 26th year working.
Step-by-step explanation:
Adrian salary in first year = $66,000
As Adrian is expected to get raises of $5,000 every year going forward.
Here is the sequence of Adrian's raises:
5,000, 10000, 15000, 20000, 25000 .....
As the common difference between consecutive terms is constant.
d = 10000 - 5,000 = 5,000 ⇒ d = 15000 - 10000 = 5,000
So, Adrian's raises is in Arithmetic sequence.
a₁ = 5,000
n = 26
[tex]{\displaystyle \ a_{n}=a_{1}+(n-1)d}[/tex]
Put n = 26 to get the total amount of salary raises in Adrian's 26th year.
[tex]{\displaystyle \ a_{26}=5000+(26-1)5000}[/tex]
[tex]{\displaystyle \ a_{26}=5000+(25)5000}[/tex]
[tex]{\displaystyle \ a_{26}=5000+125000}[/tex]
[tex]{\displaystyle \ a_{26}=130000}[/tex]
Total raises amount after 26th year = $130000
Adding total raises after 26th year to the initial salary would let us figure out the total salary Adrian would make in his 26th year.
So,
Total Salary after 26th year = initial salary + total raises of 26 years
= 66000 + 130000
= $196000
So, Adrian would make $196000 in his 26th year working.
Keywords: arithmetic sequence, salary, raises, common difference
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In a grocery store’s circular, it states that plant-based meatless ground beef is on sale for $5.99/lb. If you buy a package that weighs 2.37 lbs, how much did it cost (round to the nearest cent)?
$5.99 divided by 100 = 0.0599
0.0599 x 237 = $14.19
What is the answer to 2*3(15-5+3)4*4-6
Answer:
1242
Step-by-step explanation:
[tex]1. \: 6(15 - 5 + 3)4 \times 4 - 6 \\ 2. \: 6(10 + 3)4 \times 4 - 6 \\ 3. \: 6(13)4 \times 4 - 6 \\ 4. \: 78 \times 4 \times 4 - 6 \\ 5. \: 312 \times 4 - 6 \\ 6. \: 1248 - 6 \\ 7. \: = 1242[/tex]
WHO EVER CAN FIGURE THIS OUT GETS THE BRAINLIEST
(34+65)X(98-123)
Answer:
-2475
Step-by-step explanation:
What is the equation of a line that passes through points (0,4) and (-4,-8)? Y=2x+4, y=2x-4, y=3x+4, y=3x-4
Answer:
(-8 - 4)/(-4 - 0) = -12/-4= 3
y - 4 = 3(x - 0)
y - 4 = 3x - 0
y = 3x + 4
the answer is c
Please please need help on these two
Answer:
( f + g ) (x) = [tex] 2 x^{2} + x - 4[/tex]
g(x) - f(x) = [tex] x^{2} - 2 x - 4[/tex]
Step-by-step explanation:
f(x) = 4 x - 4 and g(x) = [tex] 2 x^{2} - 3 x[/tex]( f + g ) (x) = f(x) + g(x)
= [tex] 4 x - 4 + 2 x^{2} - 2 x[/tex]
= [tex] 2 x^{2} + x -4[/tex]
2. g(x) = [tex] x^{2} + 1[/tex] and f(x) = 2 x + 5
g(x) - f(x) = [tex] x^{2} + 1 - (2 x + 5)[/tex]
= [tex] x^{2} + 1 - 2 x - 5[/tex]
= [tex] x^{2} - 2 x - 4[/tex]
The Golden Years Senior Citizen Center uses a phone tree to announce when the center will be closed for poor weather. When each person receives a phone call, that person has a list of three more people to call. The function c approximates the total number of calls made after m minutes since the start of the phone tree. c(m) = 3/2 * (3 ^ (m/10) - 1) Approximately how many minutes will it take for the number of calls to reach 363?
Answer:
50 Minutes.
Step-by-step explanation:
The function c approximates the total number of calls made after m minutes since the start of the phone tree.
[tex]c(m)=\frac{2}{3}\times (3^{\frac{m}{10}}-1)[/tex]
We need to find the number of minutes after which the total number of calls will 363.
Substitute c(m)=363 in the given function.
[tex]363=\frac{2}{3}\times (3^{\frac{m}{10}}-1)[/tex]
Multiply 3/2 both sides.
[tex]363\times \frac{3}{2}=(3^{\frac{m}{10}}-1)[/tex]
[tex]242=3^{\frac{m}{10}}-1[/tex]
Add 1 on both sides.
[tex]243=3^{\frac{m}{10}}[/tex]
[tex]3^5=3^{\frac{m}{10}}[/tex]
On comparing both sides we get
[tex]5=\frac{m}{10}[/tex]
Multiply both sides by 10.
[tex]50=m[/tex]
Therefore, the total number of calls will 363 after 50 minutes since the start of the phone tree.
Answer:
50 minutes
Step-by-step explanation:
A regular section of land made up of wheat farms has a length of 5x10^4 and the width of 6x10^3 what is the area of the length in square meters?
Answer:
The Area of land is 30 × [tex]10^{7}[/tex] meters² .
Step-by-step explanation:
Given as :
The length of rectangular wheat farm land = L = 5 × [tex]10^{4}[/tex] meter
The width of rectangular wheat farm land = w = 6 × [tex]10^{3}[/tex] meter
Let The Area of land = A meters²
Now, According to question
∵ Land is in rectangular shape
And we know, Area of rectangle = length × width
∴ Area of land = Area of rectangle = length × width
Or, A = L × w
Or, A = 5 × [tex]10^{4}[/tex] meter × 6 × [tex]10^{3}[/tex] meter
Or , A = 30 × [tex]10^{4+3}[/tex]
i.e A = 30 × [tex]10^{7}[/tex] meters²
So, The Area of land = A = 30 × [tex]10^{7}[/tex] meters²
Hence,The Area of land is 30 × [tex]10^{7}[/tex] meters² . Answer
Whats the Answer y=10 4x-5y=3
A high school drama club is putting on their annual theater production there is a maximum of 800 tickets for the show the cost of the tickets are six dollars before the day of the show and nine dollars on the day of the show to meet the expenses of the shelf book club must sell at least $5000 worth of tickets
Answer:
Step-by-step explanation:
a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.
HOPE THIS HELPED ;3
Garrett brown bought $200,000 of term life insurance at the rate of $5.40 per thousand dollar unit how much is the annul premium
Answer:
The annual premium will be = $1080
Step-by-step explanation:
Total life insurance term amount = $200,000
The term life insurance rate per $1000 = $5.40
Let’s divide total term amount i.e. $200,000 by $1000 unit to get the total number of $1000 units in $200,000
So, $200,000 ÷ $1000 = 200
So, it is clear that 200 would be the total number of $1000 units in total term life insurance amount of $200,000.
Therefore, if rate per unit $1000 is $5.40, then we must have to multiply $5.40 by 200 to find the annual premium as the total number of $1000 units in total term life insurance amount
of $200,000 is 200.
So, $5.40 × 200 = $1080
Hence, the annual premium will be = $1080
Keywords: insurance, premium, annual premium
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How many solutions does the system of equations have Y = 4x+3 and 2Y-8x = 3
Answer:
The system has no solution.
Step-by-step explanation:
Write the system as
y - 4x =3
2y - 8x = 3
The 2nd equation can be written as
2(y - 4x)
and the system would be
y - 4x =3
2(y - 4x) = 3
Now, call y -4x = z. Then we would have the system
z = 3
2z = 3
But if z =3 then 2z = 6 and we have a contradiction.
We conclude that the system has no solution.
Ruby was paid $24 to sweep 4 walks which of the following can be represented by an equivalent ratio ?
•$6 to sweep 1 walk
•$12 to sweep 3 walks
•$30 to sweep 5 walks
Answer:
$6 to sweep 1 walk
Step-by-step explanation:
$24 : 4 walks can be simplified by dividing both sides by 4.
24/4:4/4=6:1
Ava and Addison are saving for a new cell phone. Ava is starting at 100$ and adding 5$ each week.Addison is starting with 200$ and is adding 4$ each week. Write and solve a problem that can be used to find out after how many weeks Ava and Addison will have the same amount of money saved?
Answer:
The numbers of weeks for which both Ava and Addison have same amount of money saved is 100 weeks .
Step-by-step explanation:
Given as :
The amount of money having with Ava at starting = $100
The money that Ava is saving each week = $5
The amount of money having with Addison at starting = $200
The money that Addison is saving each week = $4
Now, Let The numbers of weeks for which both Ava and Addison have same amount of money saved = n weeks
Now, According to question
The amount of money having with Ava at starting + (The money that Ava is saving each week × numbers of weeks) = The amount of money having with Addison at starting + (The money that Addison is saving each week × numbers of weeks)
Or, $100 + $5 × n = $200 + $4 × n
Or, $5 × n - $4 × n = $200 - $100
Or, n = 100
So, The numbers of weeks for which both Ava and Addison have same amount of money saved = n = 100 weeks
Hence,The numbers of weeks for which both Ava and Addison have same amount of money saved is 100 weeks . Answer
please help
Simplify.
(4a5b6)4
16a9b10
256a9b10
16a20b24
256a20b24
Answer:
256a^20b^24
Step-by-step explanation:
Two cars start from the same place driving at the same rate, one heading north and the other heading east. After two hours the car heading north has traveled 150 miles and the car heading east has traveled 100 miles. How far apart are the cars at this time?
A) 111.8 miles
B) 180.3 miles
C) 250 miles
D) 350 miles
Answer:
B: 180.3
Step-by-step explanation:
A^2 + B^2 = C^2
150^2 + 100 ^2 = 32500
square root of 32500
180.3
7x(x+1.8)=0 I have tried -1.8 and 0, they did not work.
Answer:
x= -12.6/7. you may try this
Good evening ,
Answer:
The solutions of the equation 7x(x+1.8)=0 are -1.8 and 0.
Step-by-step explanation:
7×(0)×[(0)+1.8] = 0×[1.8] = 0×1.8 = 0
7×(-1.8)×[(-1.8)+1.8] = 7×(-1.8)×[0] = 7×(-1.8)×0 = 0.
:)
Last Wednesday, students could choose ham or turkey sandwiches for lunch. The cafeteria made 60 sandwiches in all, 90% of which were turkey. How many turkey sandwiches did the cafeteria make?
Answer:
3
Step-by-step explanation:
Give me brainliest
Answer:
54 sandwiches were Turkey.
60 x .94 = 54
Step-by-step explanation:
Find the smaller of two consecutive integers,x, if the sum of the smaller and two times larger is 14. Write an equation and solve
Answer:
4
Step-by-step explanation:
Consecutive integers are e.g. 1, 2, 3, 4, ...
So they are 1 units apart.
If we let one of the integers be "x", then the next consecutive one would be "x + 1".
x is the smaller
x + 1 is the larger
of the two...
Now,
The sum of smaller (x) and 2 TIMES larger (x + 1) is 14, so we can write:
[tex]x+2(x+1)=14[/tex]
We use algebra and solve for x:
[tex]x+2(x+1)=14\\x+2x+2=14\\3x=14-2\\3x=12\\x=4[/tex]
So, the two numbers is 4 & 5
smaller of the two numbers is "4"
To find the smaller of two consecutive integers where the sum of the smaller and two times the larger is 14, set up the equation x + 2(x + 1) = 14 and solve for x to find that the smaller integer is 4.
Explanation:To find the smaller of two consecutive integers x, when the sum of the smaller and two times the larger is 14, we can set up a simple algebraic equation. Let x be the smaller integer; then the larger integer is x+1. The equation based on the given information is:
x + 2(x + 1) = 14
Now, let's solve for x:
x + 2x + 2 = 143x + 2 = 143x = 14 - 23x = 12x = 12 / 3x = 4Therefore, the smaller consecutive integer is 4.
SOMEONE SEND HELPPP
+ 10 is the missing step in the given chart.
Step-by-step explanation:
Given data from the Flow chart,
Start = 20,
End = 6,
Second Step is ÷ 5.
Let us form the given information into two equations,
Consider the missing value as X.
20+X=Y ⇒1
Y÷5=6 ⇒2
where Y is the value of middle box.
From equation 1,
Y=6×5
Y=30.
From equation 2,
20+X=30.
X=30-20.
X= 10.
Thus + 10 is the missing step.
−
1
⋅
f
(
−
8
)
−
4
⋅
g
(
4
)
=
−1⋅f(−8)−4⋅g(4)=
Answer:
-7
Step-by-step explanation:
The question is a mathematics problem related to evaluating functions, but it cannot be answered without additional information about the functions f and g.
Explanation:The question asks for the result when evaluating two functions f and g at given arguments and then combining these evaluated results with given coefficients. Specifically, it asks to compute the value of − 1 ⋅ f(− 8) minus 4 ⋅ g(4). However, without additional information about the functions f and g, it's not possible to calculate the exact numeric answer. Students usually encounter this type of problem while learning about functions and their evaluations in algebra.