Lightning is an example of matter in a liquid state.
True
False
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Answer:

A magnetic field

Explanation:

Answer:

synapses

The chemical that helps them to communicate is neurotransmitters

Explanation: synapses have a receiving end and a sending end that helps them receive signal transmitted through the neurotransmitters

B. Valence Electrons

_________________

Reason:

The valence electrons are the number of electrons in an outer shell of an atom that can participate in forming chemical bonds with other atoms. Atoms with a relatively empty outer shell will want to give up electrons.

The officer conclude that the driver exceeded the speed limit as the speed was 69mph.

speed = distance /time

speed  = 30 miles / 26 minute

speed = 30 miles /26 minute x 60 minutes/1 hour

speed = 900 miles/13 hours

speed = 69 mph.

the prevailing maximum pace limit for cars on expressways is a hundred and twenty km and on national highways, the maximum velocity restriction is 100 mph.

Velocity limits in India vary by way of nation and car type. In April 2018, the Union Ministry of street shipping and Highways constant the most velocity limit on expressways at a hundred and twenty km/h, for national highways at one hundred km/h, and for urban roads at 70 km/h for the M1 class of vehicles.

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Telescopes assist astronomers by detecting and analyzing light from celestial objects in great detail, enabling scientists to view distant objects and investigate their properties, including the chemistry of their atmospheres. They provide insight into the deep time and space of the universe.

Telescopes play an integral role in astronomical discoveries as they allow us to detect and analyze light and other forms of electromagnetic radiation from celestial objects. The key components in telescopes that make this possible are their light-gathering power and high-resolution imaging capabilities.

Telescopes gather more light than the human eye, allowing them to observe dim and distant objects in more detail. They can detect images and spectra of planets and galaxies, some of which are so distant that their light has traveled for billions of years to reach us. This provides profound insight into the structure of the universe and the life cycles of celestial bodies.

Moreover, by observing the chemistry of these planets' atmospheres, telescopes enable astronomers to search for signs of extraterrestrial life. Advanced telescopes such as the Hubble Space Telescope and the Very Large Telescope in Chile provide views of deep space and deep time – periods of time deep in the past – at an unrivaled resolution.

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Answers

1)Light is a kind of electromagnetic radiation.

3)Electromagnetic radiation has no mass.

4)Electromagnetic radiation can travel through a vacuum.

Explanations

Electromagnetic waves are waves that can travel through vacuum. that is they do not require material medium for propagation.

Light is in the electromagnetic spectrum.

Electromagnetic waves can travel through a long distance. For instance, radio waves are electromagnetic radiations that travel long distances.

Electromagnetic radiations carry energy with it but no mass.

Some of the electromagnetic radiations are visible such as visible light.

Final answer:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. The rectangular equation for the plane curve is x^2 + y^2 = 36.

Explanation:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. This will eliminate the parameter t and give us a rectangular equation. Let's do the calculations:

x^2 = (6 cos t)^2 = 36 cos^2 t

y^2 = (6 sin t)^2 = 36 sin^2 t

Adding the two equations together: x^2 + y^2 = 36 (cos^2 t + sin^2 t) = 36

So, the rectangular equation for the plane curve is x^2 + y^2 = 36. This means that option C is the correct answer.

Final answer:

To find the length of a pendulum with 1.0 seconds on the Moon, we use the formula for a pendulum's period, adjust the acceleration due to gravity to the Moon's 1.63 m/s², and solve for the pendulum's length.

Explanation:

The subject question inquires about the length of a pendulum on the Moon that has a period of 1.0 seconds, taking into consideration that the Moon's gravity is 1/6th that of Earth's. The formula for the period of a simple pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

On Earth, assuming the acceleration due to gravity (g) is approximately 9.81 m/s², the length (L) for a pendulum with a period (T) of 1.0 seconds can be calculated using this formula. However, since we are interested in the situation on the Moon where g is 1/6th that of Earth's, we would have to adjust the acceleration due to gravity in our formula to be 1.63 m/s² (since 9.81 m/s² divided by 6 equals approximately 1.63 m/s²).

Accordingly, by rearranging the formula to L = T²g/(4π²), and substituting T with 1.0 second, and g with 1.63 m/s², one can compute the appropriate length of the pendulum on the Moon that would have a period of 1.0 second.

Final answer:

The length of a pendulum with a period of 1.0 second on the Moon can be calculated by rearranging the period formula for a simple pendulum, T = 2π√(L/g), and substituting in the Moon's gravity of 1.63 m/s².

Explanation:

The length of a pendulum that has a period of 1.0 second on the Moon, where gravity is 1/6th of Earth's gravity, can be found using the formula for the period of a simple pendulum, T = 2π√(L/g). On Earth, where the standard acceleration due to gravity, g, is approximately 9.81 m/s², a 1.0-second period requires a certain pendulum length. However, on the Moon, the acceleration due to gravity is only 1.63 m/s².

We can rearrange this formula to solve for the length (L) of the pendulum on the Moon: L = (T² * g) / (4π²). By substituting T for 1.0 second and g for 1.63 m/s², the length of the pendulum on the Moon can be calculated.

Using the provided formula, we get L = (1.0² seconds² * 1.63 m/s²) / (4π²) which gives us the length of the pendulum on the Moon. You would then perform the calculation to find the exact value for L.

The 10 kg cart and 5 kg cart under different net forces will move to the left but with different accelerations. Despite the larger force acting on the 10 kg cart, the lighter 5 kg cart will actually accelerate at a greater rate.

Comparing the motion of a 10 kg cart experiencing a net force of 12 N to the left and a 5 kg cart experiencing a net force of 8 N to the left involves the principles of Newton's second law of motion, F=ma. For the 10 kg cart, the acceleration is found by dividing the force by mass(12 N / 10 kg), which equals 1.2 m/s² to the left. For the 5 kg cart, the acceleration is (8 N / 5 kg), which equals 1.6 m/s² to the left.

Therefore, despite the 10 kg cart experiencing a larger force, the 5 kg cart actually accelerates at a greater rate due to its lighter mass. This illustrates the principle that net force not only depends on the magnitude of the force but also on the mass of the object it is acting on.

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The kinetic energy of the wolf is 2500J.

The kinetic energy of the wolf can be calculated using the formula: Kinetic Energy = 0.5 x mass x velocity^2. Plugging in the given values, we have: Kinetic Energy = 0.5 x 50.0 kg x (10.0 m/sec)^2. Solving this equation will give us the wolf's kinetic energy.

Given values:

- Mass (m) = 50.0 kg

- Velocity (v) = 10.0 m/s

Using the formula for kinetic energy:

Kinetic Energy (KE) = 0.5 x mass x velocity^2

Plugging in the values:

KE = 0.5 x 50.0 kg x (10.0 m/s)^2

Calculating the square of the velocity:

KE = 0.5 x 50.0 kg x 100.0 m^2/s^2

Now, calculate the product:

KE = 2500.0 kg m^2/s^2

The unit of kinetic energy is joules (J), so we can rewrite it as:

KE = 2500.0 J

Therefore, the wolf's kinetic energy is 2500.0 joules (J).

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The answer is 1350 N

The answer is option a.

During a washing machine's spin cycle, the force that acts on the clothes is directed outward, which is a result of the centrifugal force.

In the context of a washing machine's spin cycle, the force that acts on the clothes is directed outward. This is due to the principle of centrifugal force, a type of inertial force that acts on an object moving in a circular path. The centrifugal force pushes the clothes against the wall of the washing machine drum when it rotates, effectively helping to draw water out of the clothes.

This centrifugal force pushes the clothes away from the center of rotation, causing them to stick to the drum's inner surface during the spin cycle.

Therefore, the answer is option a.

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As the time to run up the stairs increases, the power developed decreases..

When analyzing the relationship between time and power, it's essential to consider the fundamental definition of power as the rate at which work is done.

This can also be understood using the formula for power -

Power (P) = Work (W) / Time (t)

When the time (t) increases and the work (W) remains constant, the power output (P) decreases.

Thus, as the time required to run up the stairs increases, the power developed by that person decreases.

A) Tension in the cord A ≈ 570 Newton

B) Tension in the cord B ≈ 700 Newton

[tex]\texttt{ }[/tex]

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

weight of the suspended object = w = 210 N

Asked:

tension in the cord A = T_A = ?

tension in the cord B = T_B = ?

Solution:

Let:

γ = 360° - 60° - 45° - 90° = 165°

α = 90° + 45° = 135°

β = 60°

[tex]\texttt{ }[/tex]

We will use Lami's Theorem in this question.

If the system is in equilibrium , then:

[tex]\large {\boxed{\frac{T_A}{\sin \alpha} = \frac{w}{\sin \gamma}}}[/tex]

[tex]T_A = w \times \frac{\sin \alpha}{sin \gamma}[/tex]

[tex]T_A = 210 \times \frac{\sin 135^o}{sin 165^o}[/tex]

[tex]T_A = 210 \times ( 1 + \sqrt{3} )[/tex]

[tex]T_A \approx 570 \texttt{ Newton}[/tex]

[tex]\texttt{ }[/tex]

[tex]\large {\boxed {\frac{T_B}{\sin \beta} = \frac{w}{\sin \gamma}}}[/tex]

[tex]T_B = w \times \frac{\sin \beta}{sin \gamma}[/tex]

[tex]T_B = 210 \times \frac{\sin 60^o}{sin 165^o}[/tex]

[tex]T_B = 210 \times \frac{1}{2}( 6 + 3\sqrt{2} )[/tex]

[tex]T_B \approx 700 \texttt{ Newton}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

[tex]\texttt{ }[/tex]

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Final answer:

To find the position of the particle when t=7, integrate the velocity function to obtain the position function. Substitute a given position value to determine the constant of integration. Finally, plug in t=7 into the position function and evaluate to find the position of the particle.

Explanation:

To find the position of the particle when t=7, we need to integrate the velocity function from t=6 to t=7. The velocity function v(t) = 5sin(t^2) represents the rate of change of position with respect to time. Integrating this function gives us the position function x(t) = -5cos(t^2) + C, where C is a constant of integration.

We can find the value of C by substituting the given position x(6) = 4.0 into the position function. Plugging in t=6 and x=4.0, we get 4.0 = -5cos(6^2) + C. Solving for C, we find C = 4.0 + 5cos(6^2).

Now we can find the position of the particle when t=7 by plugging in t=7 into the position function x(t) = -5cos(t^2) + C, where C is the value we obtained earlier. Evaluating the expression, we find x(7) = -5cos(7^2) + (4.0 + 5cos(6^2)). Therefore, the position of the particle when t=7 is approximately (0.609, 0).

Final answer:

The position of the particle at t=7 can be determined by integrating the given velocity function v(t) = 5sin(t^2) from t=6 to t=7 and adding the result to the known position at t=6. The integral does not have an elementary antiderivative, so numerical methods are needed for evaluation.

Explanation:

The position of the particle, while it moves along the x-axis, can be found by integrating the velocity function. Since the velocity is given by v(t) = 5sin([tex]t^2[/tex]), we will integrate this with respect to time to find the position function x(t). Given that the particle's position at time t=6 is (4,0), we can use this information to find the constant of integration after integrating the velocity function.

To find the position x(t) at any time t after t=6, we would calculate the integral of the velocity function from 6 to t, and add this to the initial position at t=6:

∫6t 5sin(τ2)dτ + 4

To find the position at t=7, we would evaluate this integral from 6 to 7, which requires a numerical method since the integral of sin(t2) is not an elementary function. Once the integral is evaluated, this value is added to 4 (the position at t=6) to determine the final position of the particle at t=7.

Answer:

Explanation:

I agree with what the first person said

Final answer:

The correct answer is that the melting point and freezing point of a substance are always the same, illustrating the equilibrium between the solid and liquid states of that substance at a specific temperature, such as 0°C for water.

Explanation:

The correct answer to which of the following is true about melting and freezing points is: The melting point is always the same as the freezing point. This principle is crucial in understanding the thermal properties of substances. The temperature at which a substance changes from solid to liquid (melting point) is the same temperature at which it changes from liquid to solid (freezing point) when the process is reversible and under the same pressure conditions. For instance, with water (H₂O), this equilibrium occurs at 0°C, illustrating that at this temperature, the solid and liquid states of H₂O are in equilibrium (H₂O (s) = H₂O (l)).

It's essential to refute common misconceptions like the melting point being higher than the freezing point or that these concepts apply differently to liquids and gases. All materials, whether solid, liquid, or gas at room temperature, have characteristic melting/freezing points that do not depend on their state at room temperature but rather on their inherent thermal properties.

Answer:

the average kinetic energy of water particles

Explanation: