In 2014, the populations of China and India were approximately 1.355 and 1.255 billion people,45 respectively. However, due to central control the annual population growth rate of China was 0.44% while the population of India was growing by 1.25% each year. If these growth rates remain constant, when will the population of India exceed that of China?

Answers

Answer 1

Answer:

in the year 2023

Step-by-step explanation:

Initial population of China = 1.355  billion

Initial population of India = 1.255  billion

Annual population growth rate of China = 0.44% = 0.0044

Annual population growth rate of India = 1.25% = 0.0125

Now,

Final population = P₀ [tex]\times e^{\text{rate}\times t}[/tex]

Here,

P₀ = initial population

t = time

Thus,

Population of India > Population of China

1.255[tex]\times e^{\text{0.0125}\times t}[/tex]  > 1.355[tex]\times e^{\text{0.0044}\times t}[/tex]  

or

[tex]e^{0.0081t}[/tex] > 1.07968

taking natural log both sides

0.0081t > ln (1.07968 )

or

0.0081t > 0.0766

or

t > 9.465

Hence,

9.465 year after 2014

i.e

in 2014 + 9.465 = 2023.46

in the year 2023

Answer 2
Final answer:

Using the formula for exponential growth and the provided population data for China and India, we can approximate that India's population will exceed China's in roughly 20 years.

Explanation:

In order to determine when India's population will exceed that of China, we can use the formula for exponential growth, which is P = P_0 * ert , where P is the future population, P_0 is the initial population, r is the growth rate, and t is time. As per the data provided, for China, P = 1.355 billion, r = 0.44%, and for India, P = 1.255 billion, r = 1.25%. We have to find time t when population of India will exceed that of China. This requires solving the equation: 1.355 * e0.0044t = 1.255 * e0.0125t.

This equation can be solved using algebra and logarithms. However, by making some approximations and using a spreadsheet or calculator, we can find that the population of India will exceed that of China after approximately 20 years, based on the growth rates provided.

Learn more about Population Growth here:

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Related Questions

Find an equation of the line that (a) has y-intercept of 7 and (b) is parallel to the line -5x-6y=1

Write your answer in the form y=mx+b

Answers

Answer:

The answer to your question is    5x + 6y - 42 = 0  

Step-by-step explanation:

Data

y-intercept = 7

parallel to -5x - 6y = 1

Process

1.- Find the slope

                             - 6y = 5x + 1

                                 y = -5/6 x - 1/6

As the lines are parallels, the slope is the same in both lines

                                 m = -5/6

2.- Find the equation of the new line

If the line has a y-intercept of 7, it means that the point is (0, 7)

                       y - y1 = m(x - x1)

Substitution

                      y - 7 = -5/6 (x - 0)

Simplification

                      y - 7 = -5/6x

Equal to zero

                     5/6x + y - 7 = 0

Multiply by 6

                     5x + 6y - 42 = 0           This is the equation of the line

Answer:

6y = -5x + 42

Step-by-step explanation:

-5x - 6y = 1

-6y = 5x + 1---------------------(i)

y = -5x/6 - 1/6

comparing the equation above with y = mx + c, we have;

m = -5/6

for condition of parallelism

the gradient of the new line = -5/6

Using the formula

y = mx + c

y = -5x/6 + 7

6y = -5x + 42

An aquarium is to be drained. The aquarium is shaped like a rectangular prism with length 33 in , width 26 in , and height 12 in . Suppose water is pumped out of the aquarium at a rate of 396 in^3 per minute. If the aquarium starts completely full, how many minutes does it take to empty the aquarium?

Answers

Answer:

To empty the aquarium it takes 26 minutes

Step-by-step explanation:

step 1

Find the volume of the aquarium

The volume of rectangular prism is

[tex]V=LWH[/tex]

we have

[tex]L=33\ in\\W=26\ in\\H=12\ in[/tex]

substitute the given values

[tex]V=(33)(26)(12)=10,296\ in^3[/tex]

step 2

Divide the volume by the rate of 396 in^3 per minute

[tex]10,296/(396)=26\ minutes[/tex]

therefore

To empty the aquarium it takes 26 minutes

The problems about the Exeter spring and the Canadian plains contain relationships that are called direct variations. In your own words, describe what it means for one quantity to vary directly with another. Which of the following describe direct variations? (a) The gallons of water in a tub and the number of minutes since the tap was opened. (b) The height of a ball and the number of seconds since it was thrown. (c) The length of a side of a square and the perimeter of the square. (d) The length of a side of a square and the area of the square.

Answers

Answer:

(a) The gallons of water in a tub and the number of minutes since the tap was opened.

(c) The length of a side of a square and the perimeter of the square.

(d) The length of a side of a square and the area of the square.

Step-by-step explanation:

Direct variation:

When one quantity increases with the another quantity , they are said to be in direct proportion.An increase in one quantity leads to a proportional increase in another quantity, then, the quantity is said to vary directly with another.Mathematically, it can be expressed as:

[tex]\text{If y varies directly with x}\\y = kx\\\text{where k is a proportionality constant.}[/tex]

(a) The gallons of water in a tub and the number of minutes since the tap was opened.

As the minutes for which the tap is opened increases, there is an increase in the amount of water in tub.

Thus, there is a direct variation  between the gallons of water in a tub and the number of minutes since the tap was opened.

(b) The height of a ball and the number of seconds since it was thrown.

As the time increases after the ball was thrown, its height increases. But after some time the height decreases and becomes zero.

Thus, this not an example of direct variation.

(c) The length of a side of a square and the perimeter of the square.

As the side of square increases the perimeter increases.

Thus, there is a direct variation between length of a side of a square and the perimeter of the square.

(d) The length of a side of a square and the area of the square.

As the side of square increases the area increases.

Thus, there is a direct variation between length of a side of a square and the area of the square.

A small radio transmitter broadcasts in a 44 mile radius. If you drive along a straight line from a city 56 miles south of the transmitter to a second city 53 miles west of the transmitter, during how much of the drive will you pick up a signal from the transmitter? (Hint: you will need to find the equations of the circle and line, the intersection and the differnence of the distances.) Please also show work for finding the points of intersection.

Answers

Answer:

the transmitter signal is picked up for 42.63m of the drive.

Ans = 42.63m

Step-by-step explanation:

Solution

Let triangle ABC formed by line from 56 miles south of transmitter, to the transmitter itself then to 53 miles west of the transmitter with sides

AB BC AC

Where AB = 56 miles

and BC = 53 miles

Therefore AC = Sqr((56m)^2 +(53m)^2) = 77.10m

The point of intersection of the radius of the radio transmitter signal and the triangle formed by the path of travel of the traveller and the lines AB and AC 

To find the perpendicular line that can be drawn from C to AB we have from trigonometric relations

56 × sin(t) = 53 × sin (90 - t) because the traveller moves from directly south of the transmitter to directly west of the transmitter

Hence we have

56×sin(t) = 53×cos(t) because sin(90-t) = cos(t)

Rearranging 56×sin(t) = 53×cos(t) we have

1=(56×sin(t))/ (53×cos(t))

or (sin(t)/ cos(t))=1/(56/53)=53/56

That is tan(t)=53/56 and ACTAN(t) = 43.42°

Angle (t)

Drawing a perpendicular line from the point of the radio transmitter C to the travel path of the traveller AB   and calling the point of Intersection E we have EC = 53×sin(43.42)=38.49m

It is seen that the distance from the point of intersection of the radius of the radio transmitter and intersection of the line CE and AB  is EI1 where I1 is the first point of intersection of the radius of the radio transmitter and the line AB

EI1=Sqr((44m)^2-(38.49m)^2)

= 21.31m

Also since the triangles CEI1 and CEI2 are identical, it follows that EI1 = EI2 = 21.32m

The distance over which the traveller will be able to receive the signal from the radio transmitter while travelling from point A to point B is the distance I1 to I2 which is equal to 2*I

=2×21.31=42.63m

Ans = 42.63m

The signal will be picked up for approximately 3.015 miles of the drive.

To solve this, first, find the equations of the circle and the line representing the transmitter's broadcast range and the path of the drive, respectively.

Then, find the intersection points. Calculate the distances from these points to the transmitter.

Determine the portion of the drive where the distance is within the broadcast range (44 miles).

It turns out the signal is picked up only for a short portion of the drive near one of the intersection points.

1. Equation of the Circle:

The equation of a circle with center (h, k) and radius r is:

(x - h) ²+ (y - k)² = r²

Given that the transmitter broadcasts in a 44-mile radius and assuming the center of the circle is at the origin (0,0) the equation of the circle is:

x² + y² = 44²

2. Equation of the Line:

The equation of a straight line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Given that the drive is along a straight line from a city 56 miles south of the transmitter to a second city 53 miles west of the transmitter, the line can be represented as:

y = - 56/53 * x + 56

Next, we'll find the points of intersection between the circle and the line, which is step 3.

Substitute y = - 56/53 * x + 56 into x² + y² = 44² to solve for the x-coordinates of the intersection points. Then, use these x-coordinates to find the corresponding y-coordinates.

x² + (- 56/53 * x + 56)² = 44²

Expanding and simplifying this equation will give us a quadratic equation in x, which we can solve to find the x-coordinates of the intersection points.

x² + (3136/2809 * x² - 5376/53 * x + 3136) = 44²

x² + 3136/2809 * x² - 5876/53 * x + 3136 - 44² = 0

59345/2809 * x² - 5376/53 * x + 3136 - 44² = 0

345x² - 150992x + 17424 - 44² * 2809 = 0

59345x² - 150992x + 0 = 0

3. Now, let's solve this quadratic equation. We can use the quadratic formula:

x = (-b±√b-4ac)/2a

Where a = 59345, b = -150992, and c = 0

x= [150992±√(-150992)2-4(59345)(0)] / 2(59345)

x= (150992±√22793455664) / 118690

x₁= (150992±151034) / 118690

x₁ = 302026 / 118690 = 2.545

x₂ = (150992-151034) / 118690

x₂ = -42 / 118690

≈ -0.00035

Now, we'll find the corresponding y-coordinates by substituting these x-values into

the equation of the line y = - 56/53 * x + 56

For x =2.545:

y₁ = - 56/53 * 2.545 + 56

y₁ ≈ 1.615

For x ≈ -0.00035:

y₂ = - 56/53 * (- 0.00035) + 56

y₂ ≈ 56

So, the two points of intersection are approximately (2.545, 1.615) and (-0.00035, 56).

4. Determine the distances from these intersection points to the transmitter.

The distance formula between two points (x₁, y₁) and (x₂, y₂) is given by:

d = √(x₂-x₁)² + (y₂ - y₁)²

Let's calculate the distances from these intersection points to the origin (transmitter),

which is (0,0).

For point (2.545, 1.615) :

[tex]d_1 = \sqrt{(2.545 - 0)^2 + (1.615 - 0)^2}[/tex]

d[tex]d_1 = \sqrt{2.545^2 + 1.615^2}[/tex]

[tex]d_1 \approx \sqrt{6.475 + 2.61}[/tex]

[tex]d_1 \approx \sqrt{9.085}[/tex]

[tex]d_1 \approx 3.015[/tex]

For point (-0.00035, 56):

[tex]d_2 = \sqrt{(-0.00035 - 0)^2 + (56 - 0)^2}[/tex]

[tex]d_2 = \sqrt{(-0.00035)^2 + 56^2}[/tex]

[tex]d_2 \approx \sqrt{0 + 3136}[/tex]

[tex]d_2 \approx \sqrt{3136}[/tex]

[tex]d_2 = 56[/tex]

5. Calculate the portion of the drive during which the signal will be picked up.

Since the signal from the transmitter can be picked up within a 44-mile radius, we need to determine at what points along the path the distances to the transmitter are less than or equal to 44 miles.

From our calculations, we see that d₁ ≈ 3.015 miles and d₂ = 56 miles.

Thus, the signal will be picked up during the portion of the drive where

d₁ ≤ 44 miles.

Therefore, the signal will be picked up for approximately 3.015 miles of the drive.

Important Characteristics Quiz The probability of success in each of the 58 identical engine tests is p = 0.92. What is the mean of this binomial distribution?

Answers

Answer: The mean of this binomial distribution is 53.36.

Step-by-step explanation:

We know that , the mean of this binomial distribution is given by :_

[tex]\mu = np[/tex]

, where n = sample size or the number of possible trials .

p = probability of getting success in each trial.

We are given that , the probability of success in each of the 58 identical engine tests is p = 0.92.

i.e. n= 58

p=0.92

Then, the mean of this binomial distribution = [tex]58\times0.92=53.36[/tex]

Hence , the mean of this binomial distribution is 53.36.

Two rockets are lauched at the same time, but from different heights. The height y in feet of one rocket after t seconds is given by y = -16t² + 150t + 5. The height of the other rocket is given by y = -16t² + 160t. After how many second are the rockets at the same height?

Answers

Answer:

0.5 seconds

Step-by-step explanation:

Two rockets are launched at the same time, but from different heights.

[tex]y = -16t^2+ 150t + 5[/tex]

[tex]y = -16t^2 + 160t[/tex]

when the heights are same then y are equal. So equation both equations and solve for t

[tex]-16t^2+ 150t + 5= -16t^2+ 160t[/tex]

Add -16t^2 on both sides

[tex]+ 150t + 5=160t[/tex]

Subtract 150 t from both sides

[tex]5=10t[/tex]

Divide 10 on both sides

t=0.5 seconds

In a collection of toys, 1/2 are red, 1/2 are waterproof, and 1/3 are cool. 1/4 are red and waterproof. 1/6 are red and cool. 1/6 are waterproof and cool. 1/6 are neither red, waterproof, nor cool. Each toy has an equal chance of being selected.Draw an area diagram to represent these events.

Answers

Answer:

only red = 1/12, only water proof = 1/12 , only cool = nil we assume nil for toys with three collections( cool, red, waterproof) as it was not stated.

11/6 are neither red, water proof and cool.  

Step-by-step explanation:

outside the circles contain probability of neither red, cool and water proof. where the circles intersect shows probability of both either red and cool, water proof and cool and water proof and red etc. where all the circles intersect if for the three combinations which is nill. Attached is the diagram

Answer:

The answer representation is attached below

Step-by-step explanation:

This is a representation on a diagram.

n(R) = Number of red toys

n(WP) Number of water proof toys

n(C) = Number of cool toys

n(R∩WP) = Number of red and waterproof

n(R∩C) = Number of red and cool

n(WP∩C) = Number of waterproof and cool

n(R'∩WP∩C) = Neither red, waterproof nor cool

From the image as depicted on a venn diagram, each part is represented and filled ont the diagram, the small circle space filled represent the information given in the question.

Using drt what is the Answer to this question a car in a bus set out at 2 PM find the same point headed in the same direction. The average speed of the car is 30 mph slower than twice the speed of the bus. In two hours the car is 20 miles ahead of the bus. Find the rate of the car

Answers

Answer: the rate of the car is 50mph

Step-by-step explanation:

Let x represent the average speed of the bus.

Let y represent the distance travelled by the bus.

The average speed of the car is 30 mph slower than twice the speed of the bus. This means that the average speed of the car would be

2x - 30

Distance = speed × time

Time = distance/speed

Therefore, In 2 hours time,

2 = y/x

2x = y

In two hours the car is 20 miles ahead of the bus. Therefore

2 = (y + 20)/(2x - 30)

2(2x - 30) = y + 20

4x - 60 = y + 20 - - - - - - - - -1

Substituting y = 2x into equation 1, it becomes

4x - 60 = 2x + 20

4x - 2x = 20 + 60

2x = 80

x = 80/2 = 40

The speed of the car would be

2x - 30 = 2 × 40 - 30

= 80 - 30 = 50 mph

Use the position function s(t) = −16t² + 400, which gives the height (in feet) of an object that has fallen for t seconds from a height of 400 feet. The velocity at time t = a seconds is given by [tex]\underset{(t \rightarrow a)}{lim} \frac{s(a) - s(t)}{a-t}[/tex]. A construction worker drops a full paint can from a height of 500 feet. When will the paint can hit the ground? At what velocity will the paint can impact the ground?

Answers

Answer:

160m/s

Step-by-step explanation:

The object can hit the ground when t = a; meaning that s(a) = s(t) = 0

So, 0 = -16a² + 400

16a² = 400

a² = 25

a = √25

a = 5 (positive 5 only because that's the only physical solution)

The instantaneous velocity is

v(a) = lim(t->a) [s(t) - s(a)]/[t-a)

Where s(t) = -16t² + 400

and s(a) = -16a² + 400

v(a) = Lim(t->a) [-16t² + 400 + 16a² - 400]/(t-a)

v(a) = Lim(t->a) (-16t² + 16a²)/(t-a)

v(a) = lim (t->a) -16(t² - a²)(t-a)

v(a) = -16lim t->a (t²-a²)(t-a)

v(a) = -16lim t->a (t-a)(t+a)/(t-a)

v(a) = -16lim t->a (t+a)

But a = t

So, we have

v(a) = -16lim t->a 2a

v(a) = -32lim t->a (a)

v(a) = -32 * 5

v(a) = -160

Velocity = 160m/s

Using movement concepts, it is found that:

The object hits the ground after 5.59 seconds.The object hits the ground at a velocity of -178.88 feet per second.

----------------------------------

The height of the object after t seconds, dropped from a height of 500 feet, is given by:

[tex]h(t) = -16t^2 + 500[/tex]

----------------------------------

It hits the ground when [tex]h(t) = 0[/tex], thus:

[tex]h(t) = 0[/tex]

[tex]-16t^2 + 500 = 0[/tex]

[tex]16t^2 = 500[/tex]

[tex]t^2 = \frac{500}{16}[/tex]

[tex]t = \sqrt{\frac{500}{16}}[/tex]

[tex]t = 5.59[/tex]

The object hits the ground after 5.59 seconds.

----------------------------------

The velocity is the derivative of the position, thus:

[tex]v(t) = h^{\prime}(t) = -32t[/tex]

The velocity when it impacts the ground is v(5.59), thus:

[tex]v(5.59) = -32(5.59) = -178.88[/tex]

The object hits the ground at a velocity of -178.88 feet per second.

A similar problem is given at https://brainly.com/question/14516604

There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. The ratio of the number of sophomores to all students is 1:2. What is the ratio of the number of freshmen to sophomores?

Answers

Hi there! Since the ratios of students at Hanover High School are in different scales, we need to scale them up! First, let's take the ratio 1:2. This can be scaled up to 5:10. Now, combine the two ratios to find the ratio of freshmen to sophomores. 3:10 + 5:10 = 8:10. The remaining number is 2, since 8 + 2 = 10, so the ratio of freshmen to sophomores is 2:10!

Hope this was helpful!

Find the product of all constants t such that the quadratic x^2 tx - 9 can be factored in the form (x a)(x b), where a and b are integers.

Answers

Answer:

product of the constants P will be

P = 12

Step-by-step explanation:

the quadratic equation

F= x² + t*x - 9

has as solution

a and b= [-t  ± √( t² - 4*1*(-9)) ] /2]

then

a - b = -t/2

a= b - t/2

since b is an integer , then t/2 should be an integer , then t=2*n , where n is any integer

also

a and b= [-t  ± √( t² - 4*1*(-9)) ] /2] = [-2*n  ± √(4*n²+36 )] /2  = -n  ± n √ (1+9/ n²]

since n are integers , then √ (1+9/ n²]  should be and integer and therefore

9/ n² should be an integer. Then the possible values of n are

n=1 and n=3

therefore the possible values of t are

t₁=2*1 = 2

t₂=2*3 = 6

the product of the constants P will be

P=t₁*t₂ = 12

Answer:

729

Step-by-step explanation:

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?

a 3
b 4
c 6
d 7

Answers

Answer: A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?

a 3

b 4

c 6

d 7

Step-by-step explanation:

3lbs of Cashews

Answer:

Step-by-step explanation:

4x+(10-x)*6.5 =4.75*10

4x+65-6.5x=47.5

6.5 x-4 x=65-47.5

2.5 x=17.5

x=7

peanuts=7 -pound

cashews=10-7=3 -pound

Identify the type of sampling used (random, systematic, convenience, stratified, or cluster sampling) in the situation described below.

A

manman

is selected by a marketing company to participate in a paid focus group. The company says that the

manman

was selected because

hehe

waswas

randomlyrandomly

chosenchosen

fromfrom

allall

adults.adults.

nothing

nothing

nothing

nothing

Answers

Answer: Random sampling

Step-by-step explanation:

A random sampling technique is the basic sampling technique in which the researcher randomly choose individuals from the whole population . This sampling method provides equal opportunity to each and every individual in the population to get selected for the sample.

In the given situation , the population of interest is "all adults"

Since the man got selected randomly from entire population of adults by the marketing company, it means the type of sampling method was used is random sampling technique.

Hence, the correct answer is "random"

The reaction time of a driver to visual stimulus is normally distributed with a mean of 0.4 seconds and a standard deviation of 0.05 seconds.(a) What is the probability that a reaction requires more than 0.5 second? (b) What is the probability that a reaction requires between 0.4 and 0.5 second? (c) What is the reaction time that is exceeded 90% of the time?

Answers

Answer:

a) [tex]P(X>0.5)=P(\frac{X-\mu}{\sigma}>\frac{0.5-\mu}{\sigma})=P(Z>\frac{0.5-0.4}{0.05})=P(z>2)[/tex]

[tex]P(z>2)=1-P(z<2)[/tex]

[tex]P(Z>2) = 1-P(Z<2)= 1- 0.97725=0.02275[/tex]

b)[tex]P(0.4<X<0.5)=P(\frac{0.4-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{0.5-\mu}{\sigma})=P(\frac{0.4-0.4}{0.05}<Z<\frac{0.5-0.4}{0.05})=P(0<z<2)[/tex]

[tex]P(0<z<2)=P(z<2)-P(z<0)[/tex]

[tex]P(0<z<2)=P(z<2)-P(z<0)=0.97725-0.5=0.47725[/tex]

c) [tex]a=0.4 +1.28*0.05=0.464[/tex]

So the value of height that separates the bottom 90% of data from the top 10% is 0.464.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the reaction time of a driver to visual stimulus of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0.4,0.05)[/tex]  

Where [tex]\mu=0.4[/tex] and [tex]\sigma=0.05[/tex]

We are interested on this probability

[tex]P(X>0.5)[/tex]

And the best way to solve this problem is using the normal standard distribution and the z score given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If we apply this formula to our probability we got this:

[tex]P(X>0.5)=P(\frac{X-\mu}{\sigma}>\frac{0.5-\mu}{\sigma})=P(Z>\frac{0.5-0.4}{0.05})=P(z>2)[/tex]

And we can find this probability using the complement rule:

[tex]P(z>2)=1-P(z<2)[/tex]

And using the normal standard table or excel we have this:

[tex]P(Z>2) = 1-P(Z<2)= 1- 0.97725=0.02275[/tex]

Part b

[tex]P(0.4<X<0.5)=P(\frac{0.4-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{0.5-\mu}{\sigma})=P(\frac{0.4-0.4}{0.05}<Z<\frac{0.5-0.4}{0.05})=P(0<z<2)[/tex]

And we can find this probability on this way:

[tex]P(0<z<2)=P(z<2)-P(z<0)[/tex]

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

[tex]P(0<z<2)=P(z<2)-P(z<0)=0.97725-0.5=0.47725[/tex]

Part c

For this part we want to find a value a, such that we satisfy this condition:

[tex]P(X>a)=0.10[/tex]   (a)

[tex]P(X<a)=0.90[/tex]   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.90 of the area on the left and 0.10 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.90 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.9[/tex]  

[tex]P(z<\frac{a-\mu}{\sigma})=0.9[/tex]

But we know which value of z satisfy the previous equation so then we can do this:

[tex]z=1.28=\frac{a-0.4}{0.05}[/tex]

And if we solve for a we got

[tex]a=0.4 +1.28*0.05=0.464[/tex]

So the value of height that separates the bottom 90% of data from the top 10% is 0.464.  

Answer:

a) 0.0228

b) 0.4772

c) 0.336

Step-by-step explanation:

Mean(μ) = 0.4 seconds

Standard deviation (σ) = 0.05 seconds

From normal distribution,

Z= (x - μ) / σ

a) P(x > 0.5)

Let x be the random variable for the required seconds

When x= 0.5

Z = (0.5 - 0.4)/0.05

Z = 2

From the normal distribution table, 2= 0.4772

φ(Z) = 0.4772

Recall that when Z is positive,

P(x >a) = 0.5 - φ(Z)

P(x > 0.5) = 0.5 - 0.4772

= 0.0228

b) For x = 0.4

Z= (x - μ) / σ

= (0.4 - 0.4) / 0.05

= 0

For x= 0.5

Z= (x - μ) / σ

= (0.5 - 0.4) / 0.05

= 2

From the table, P(0.4 < x < 0.5) = P(0 < Z < 2)

So we have

P(Z < 2) - P(Z<0)

From the table, 2 = 0.4772 and 0 = 0

We then have

0.4772 - 0

= 0.4772

c) we are looking for x such that 90% of the values lie above it or 10% of the value lie below it.

From the table , 10% probability gives a z value of -1.28

x = μ + Zσ

x = 0.4 + (-1.28*0.05)

x = 0.4 - (1.28*0.05)

= 0.336

Which expressions are equivalent to this expression?

3y+3z

3(y+z) 3y+z 10y+2z+y+z 6+y+3z

Answers

Only option 1: 3y+3z is equivalent to given expression

Step-by-step explanation:

In order to find the equivalent expression to given expression, we have to simplify each of the options to compare with the given expression

Given expression is:

[tex]3y+3z[/tex]

Option 1:

[tex]3(y+z)\\= 3y+3z[/tex]

Option 2:

[tex]3y+z[/tex]

Option 3:

[tex]10y+2z+y+z\\= 10y+y+2z+z\\= 11y+3z[/tex]

Option 4:

[tex]6+y+3z[/tex]

Hence,

Only option 1: 3(y+z) is equivalent to given expression

Keywords: Polynomials, expressions

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The sum of frequencies for all classes will always equal Question 1 options: the sample size a value between 0 and 100 the number of classes 1?

Answers

Answer: 100

Step-by-step explanation:

The sum of frequencies for all classes will always equal to the number of element in a data set.

Between 0-100 there will be 100 numbers.

So that it's 100

Final answer:

In the field of statistics, when you group data into classes, the sum of the frequencies always equates to the sample size. The reason is that every element or member of your sample belongs to only one class.

Explanation:

In statistics, the term frequency is related to the times a data value occurs. When dealing with numerical datasets grouped into classes for data analysis, the sum of frequencies for all classes always equals the total sample size. This is because every member of the sample belongs to one and only one class. For example, if you conducted a survey on the favorite fruits of 100 people (your sample size), and you grouped the responses into classes - apples, bananas, oranges, etc., the sum of the frequencies (i.e., the total number of people that prefer each fruit) should add up to 100 (the sample size).

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In a psychology class, 32 students have a mean score of 93.2 on a test. Then 16 more students take the test and their mean score is 63.4.What is the mean score of all of these students together? Round to one decimal place.mean of the scores of all the students =​

Answers

Final answer:

The mean score of all the students together, after calculating the combined total score and dividing by the total number of students, is 83.1.

Explanation:

The subject of this question is the computation of the mean score of all students. The first step is to find the total score of both sets of students. For the first group, the total score is the mean score multiplied by the number of students, which is 93.2 * 32 = 2974.4. For the second group, total score is 63.4 * 16 = 1014.4. The combined total score is 2974.4 + 1014.4 = 3988.8. Since there are 32 + 16 = 48 students in total, the mean score of all students is calculated by dividing the combined score by the total number of students. So, the mean score of all the students together is 3988.8 / 48 = 83.1 (rounded to one decimal place).

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A salesperson at an electronic store is given a choice of two different compensation plans. Plan A pays him a weekly salary of $250 plus a commission of $25 for each stereo sold. Plan B offers no salary but pays $50 commission on each stereo sold. How many stereos must the salesperson sell to make the same amount of money with both plans?

Answers

Answer:

10 stereos must the salesperson sell to make the same amount of money with both plans.

Step-by-step explanation:

Let the Number of stereo sold = x

According to Plan A

250 + 25X

According to Plan B

50X

According to given condition

250 + 25X = 50X

250 = 50X - 25X

250 = 25X

X = 250/25

X= 10

Write an expression for the rate of change of the height of the dough with respect to the radius of the dough in terms of height h and radius r.

Answers

Answer:

[tex]h'=\frac{dh}{dr}=-\frac{2}{r^3\pi}[/tex]

Step-by-step explanation:

Assuming the dough is of cylindrical shape and that the volume must stay the same the equation for the volume of the cylinder is the following:

[tex]V=r^2\pi h[/tex]

where V is the volume, r the radius and h the height of the cylinder. If you get h to the left hand side you get the following equation:

[tex]h=\frac{V}{r^2\pi}[/tex]

To find the rate of change of the height you need to derive the above equation with respect to r:

[tex]h'=-\frac{2}{r^3\pi}[/tex]

Rate of change is simply how much a quantity changes, over another.

The expression for the rate of change of the dough in terms of height h and radius r is [tex]\mathbf{h' = \frac{-2}{\pi r^3}}[/tex]

From the complete question, we have:

[tex]\mathbf{V = \pi r^2h}[/tex]

Next, we make h the subject

[tex]\mathbf{h = \frac{V}{\pi r^2}}[/tex]

Rewrite as:

[tex]\mathbf{h = \frac{V}{\pi}r^{-2}}[/tex]

Differentiate with respect to r

[tex]\mathbf{h' = -2\times \frac{V}{\pi}r^{-2-1}}[/tex]

[tex]\mathbf{h' = -2\times \frac{V}{\pi}r^{-3}}[/tex]

Rewrite as:

[tex]\mathbf{h' = \frac{-2V}{\pi r^3}}[/tex]

Remove V, to leave the answer in terms of r and h

[tex]\mathbf{h' = \frac{-2}{\pi r^3}}[/tex]

Hence, the expression for the rate of change of the dough in terms of height h and radius r is [tex]\mathbf{h' = \frac{-2}{\pi r^3}}[/tex]

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Please help!
Find the solutions of each equation on the interval [0,2pi).
(SHOW WORK)
Picture below.

Answers

Answer:

  x = 0

Step-by-step explanation:

The argument x+3π/2 shifts the sine function 3π/2 to the left, making it equivalent to -cos(x). Then the equation becomes ...

  -2cos(x) = -2

  cos(x) = 1

On the interval [0, 2π), cos(x) is only 1 at x=0.

Plz help, Worth 40 pts, Will mark Branliest...

Answers

Answer:

$6.83

Step-by-step explanation:

To start off, we would want to graph the points.

Once we have our graph, we see our correlation is positive, meaning that every year past 1950, the price of 1 movie ticket increases.

Our next step would to figure out the linear regression, or to guess a best line of fit. Once we do so, we should see where the movie tickets should approxametly rise to.

We then use the best line of fit to estimate the price in 2015, or when x = 65 (65 years after 1950).

The answer closest to the estimate would be 6.83. Attached image is the graph on Desmos.

Colin is painting figurines. He spends 20 mins painting each figurine. After painting for 60 mins he still has 9 left to paint. What is the function's formula

Answers

The required function is: [tex]f(t) = -0.05t+12[/tex]

Step-by-step explanation:

We have to write a function for the remaining figurines Colin has to paint.

Here

f is the function that represents number of figurines remaining

t represents time in minutes as the unit of measurement is minutes

f will be a function of t

It is mentioned in the problem that after working for 60 minutes, he has 9 figurines left to paint.

This means that

f(60) = 9

It is also given that he takes 20 minutes to paint one figurine which means in 60 minutes he will have painted 3 figurines

So at start total figurines that needed to be painted will be:

9+3 = 12

Which means that

f(0) = 12

By using these two points we can find the slope of the function

[tex]m = \frac{Change\ in\ figurines}{Change\ in\ time}\\m = \frac{9-12}{60-0}\\m = \frac{-3}{60}\\m = -0.05[/tex]

The function will be:

[tex]f(t) = mt+b[/tex]

Putting the value of slope

[tex]f(t) = -0.05t+b[/tex]

b is the initial value of figurines so

[tex]f(t) = -0.05t+12[/tex]

Keywords: Functions, slope

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The line y = 5x/3 + b goes through the point (7, –1). What is the value of b?

(A) 3
(B) –5/3
(C) –7/5
(D) 16/3
(E) –38/3

Answers

Answer:

[tex]y=\frac{5}{3} x-\frac{38}{3}[/tex]

the value of b is -38/3

Step-by-step explanation:

[tex]y=\frac{5}{3} x+b[/tex] goes through the point (7,-1)

we need to find out b for the given equation using (7,-1)

Plug in 7 for x  and -1 for y

[tex]y=\frac{5}{3} x+b[/tex]

[tex]-1=\frac{5}{3} (7)+b[/tex]

[tex]-1=\frac{35}{3}+b[/tex]

subtract 35/3 from both sides

[tex]-1 -\frac{35}{3} =b[/tex]

[tex]\frac{-38}{3} =b[/tex]

Replace it in the original equation

[tex]y=\frac{5}{3} x-\frac{38}{3}[/tex]

A line is a set of all points that:

Answers

A line is a set of all points that : C. are the same distance from two points.

Step-by-step explanation:

A line is defined as a set of all points that are the same distance from two given points. For a line to form, you must connect points, thus its correct to say a line is formed when you draw a locus of a given point.

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Keywords: line, set , points

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Which of the following is a reflection of y = |x|

Answers

The graph of y=|x| would look like graph A

The reflected graph (mirrored image) would be graph D

The vector product of vectors A and B has magnitude 12.0 m² and is in the +z-direction. Vector A has magnitude 8.0 m and is in the −x-direction. Vector B has no x-component.
Part A: What is the magnitude of vector B?
Part B: What is the direction angle θ of vector B measured from the +y-direction to the +z-direction?

Answers

Final answer:

The magnitude of vector B is 1. There is no valid direction angle theta for vector B.

Explanation:

Part A:

The magnitude of vector B can be found using the formula for the magnitude of the vector product:

|A x B| = |A||B|sin(theta)

Given |A x B| = 12, |A| = 8, and |B| = ?

Using the formula above, we can solve for |B|:

12 = 8 * |B| * sin(theta)

sin(theta) = 12 / (8 * |B|) = 1.5 / |B|

Sine of any angle lies between -1 and 1, therefore 1.5 / |B| should lie in this range

|-1| <= 1.5 / |B| <= |1|

1 <= 1.5 / |B| <= 1

1.5 <= |B| <= 1

The magnitude of vector B is 1.

Part B:

The direction angle theta can be found using the formula:

cos(theta) = Bz / |B|

Given Bz = |B| and sin(theta) = 1.5 / |B|

1.5 / |B| = sqrt(1 - sin^2(theta)) = sqrt(1 - 1) = sqrt(0) = 0

This implies that sin(theta) = 1.5 / |B| = 0, which is not possible

Hence, there is no valid direction angle theta for vector B.

Final answer:

The magnitude of vector B is 1.5 m. The direction angle θ of vector B measured from the +y-direction to the +z-direction is 90°.

Explanation:

Part A: To find the magnitude of vector B, we need to use the relationship between the magnitude of the vector product A x B and the magnitudes of vectors A and B. According to the given information, the magnitude of the vector product A x B is 12.0 m². Since the vector product is in the +z-direction, we can conclude that the magnitudes of vectors A and B multiplied by the sine of the angle between them equals 12.0 m².

Let's use this information to find the magnitude of vector B:

|A x B| = |A||B|sin(θ)

12.0 m² = 8.0 m * |B| * sin(90°)

|B| = 12.0 m² / (8.0 m * sin(90°))

|B| = 12.0 m² / 8.0 m = 1.5 m

Therefore, the magnitude of vector B is 1.5 m.

Part B: To find the direction angle θ of vector B measured from the +y-direction to the +z-direction, we can use the relationship between the components of vectors A and B and the direction angle θ:

tan(θ) = By / Bz

Substituting the given information into the equation:

tan(θ) = 0 / Bz

Since vector B has no x-component, we know that Bx = 0. Therefore, we only need to find the value of Bz to determine the direction angle θ.

Recall that |B| = 1.5 m. Using the Pythagorean theorem, we can find the value of Bz:

|B|² = Bx² + By² + Bz²

(1.5 m)² = (0)² + (0)² + Bz²

Bz² = (1.5 m)²

Bz = 1.5 m

Since Bz > 0, we know that the direction angle θ is in the positive range. In this case, the direction angle θ is 90° measured from the +y-direction to the +z-direction.

There are 360 students in front of the school waiting for buses to transport them to a museum each bus can transport no more than 42 students what is the minimum number of buses needed to transport all of the students to the museum

Answers

360 / 42 = 8.57

But you can’t have half a coach so you will need 9 coaches

Answer:

the answer is a

Step-by-step explanation:

solve the equation, justify each step with an algebraic property.
-4+-17+x.

Answers

–21 + x

Explanation:

Step 1: Given expression: –4 + (–17) + x

Step 2: In the algebraic property, positive × negative = negative

So, –4 + (–17) + x = –4 – 17 + x

Step 3: Add two negative numbers, the result will be sum with minus sign

–4 – 17 + x = –21 + x

Hence,  –21 + x is the required equation.

NEED help will give brainliest
What is the slope of the line that contains the points (-1 , 8) and (5, -4)?
A -1/2
B -2
C 1/2
D 2

Answers

The answer is B -2... you welcome

Answer:

B )  -2

Step-by-step explanation:

slope of given points

slope [tex]m= \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }[/tex]

The given points are

[tex]m = \frac{-4-8}{5-(-1)}[/tex]

[tex]m=\frac{-12}{6}[/tex]

[tex]m=-2[/tex]

final answer :-

slope of the line is m=-2

A veterinarian's office recorded one particular week that they had 50 patients. The following table shows the recorded number of dogs.


Monday Tuesday Wednesday Thursday Friday

7 4 5 5 2


The formula for standard error is given below, where represents the sample proportion, and n is the total number of elements in the sample.




Use the given data to complete the table below.


Percentage of patients that were dogs [23%; 42%; 22%; 46%]

Standard error [.07; .09; .05; .16]

Margin of error 90% confidence interval [(32%, 60%)(34%,58%)(6%, 23%)(5%,21%)]

Margin of error 95% confidence interval [(32%, 60%)(34%,58%)(6%, 23%)(5%,21%)]

Answers

Answer:

1. The correct answer is 46%

2. The correct answer is .07

3. The correct answer is (34%,58%)

4. The correct answer is (32%,60%)

Step-by-step explanation:

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

The correct answer is 46%

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

The correct answer is .07

3. Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

Confidence limits = 0.46 +/- 0.12

Confidence limits = 0.34, 0.58

The correct answer is (34%,58%)

4. Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

The correct answer is (32%,60%)

Answer:

46%

0.07

(34%,58%)

(32%,60%)

Step-by-step explanation:

i got it right

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