When your car breaks down, it is recommended to park where the vehicle can be seen for at least 200 feet in each direction. This is important for safety reasons, as it allows other drivers to see your parked car and avoid any potential collisions or accidents. By parking your car where it can be seen from a distance, you are also ensuring that emergency services or roadside assistance can easily locate and help you.
Explanation:When your car breaks down, it is recommended to park where the vehicle can be seen for at least 200 feet in each direction.
This is important for safety reasons, as it allows other drivers to see your parked car and avoid any potential collisions or accidents.
By parking your car where it can be seen from a distance, you are also ensuring that emergency services or roadside assistance can easily locate and help you.
Two people are rowing a boat at a speed of 9 m/s. in 3 seconds, they dock the boat at a pier. what is the boatâs acceleration?
When jump starting a vehicle, once the stalled vehicle is successfully started, remove the cables in the same order in which they were connected?
The statement “When you jump start a vehicle, if the stalled vehicle started, then you remove the cables in the same order in which they were connected”, is false.
Go through these steps before you even connect the cables:
1. Both batteries should have the same polarity and same voltage.
2. Never let the vehicles touch each other and your cars should be near enough to connect the cables.
3. Turn off the lights, accessories, and ignition switch in both cars. Put the vehicles in neutral mode and make sure the parking brake is set. Also wear safety glasses.
4. Never smoke. An explosion is possible if sparks and ear a battery.
5. Don’t try to it the battery if the weak battery is frozen because it can explode.
6. Be sure to be able to identify the positive and negative terminals of both batteries. You need to have enough room to clamp to the cable terminals.
Baseball player swings and hits a pop fly straight up in the air to the catcher. the height of the baseball in meters t seconds after it is hit is given by the quadratic function h left parenthesis t right parenthesis equals negative 4.9 t squared plus 34.3 t plus 1h(t)=â4.9t2+34.3t+1. how long does it take for the baseball to reach its maximumâ height? what is the maximum height obtained by theâ baseball?
Explain why the mean and standard deviation are not appropriate for particle size distributions
The mean and standard deviation are not appropriate for particle size distributions due to non-normal distributions, irregular particle shapes, discrete measurement methods, and differences in weighting methods that aren't captured by standard parametric statistics like mean and deviation.
The mean and standard deviation are not always appropriate for describing particle size distributions because particle sizes are often not normally distributed. In the case of particle size distribution, there can be significant skewness or a high level of kurtosis, leading to a distribution that significantly deviates from normality. Additionally, particles may be irregularly shaped, which affects how their size is represented and measured. When particle size is based on sieves, the analysis becomes discrete rather than continuous, which can limit the utility of standard deviation. Furthermore, different weighting methods, like number weighted distribution or intensity weighted distribution, significantly affect the representation of particle size, which the mean and standard deviation do not properly account for.
Moreover, in dynamic light scattering (DLS) methods, the assumption is made that particles are spherical and the distribution is monomodal, which might not hold true for all particle systems. Since the mass of a particle is proportional to the cube of its radius, if particles are crushed to become smaller, a sample with the same number of particles represents a significantly different mass, affecting the representativeness of mean and standard deviation.
Particle shape also influences the determination of size as particles often deviate from sphericity. The equivalent spherical diameter (ESD) used in dynamic measurements may vary, reflecting a limitation for standard mean and deviation metrics. Due to these complexities, particle size distributions are often better described using median particle sizes (such as D50) and span, a dimensionless number that provides insight into the width of size distribution.
A steel cylinder with a moveable piston on top is filled with helium (He) gas. The force that the piston exerts on the gas is constant, but the volume inside the cylinder doubles, pushing the piston up. Which of the following answers correctly states the cause for the change described in the scenario? The temperature increased. The density of the helium atoms decreased. The pressure decreased. The helium atoms increased in size.
A ball rolling down an incline has its maximum kinetic energy at
A ball rolling down an incline has its maximum kinetic energy at the bottom of the incline because the potential energy is converted into kinetic energy as it descends down the slope.
Explanation:In the context of Physics, a ball rolling down an incline has its maximum kinetic energy at the bottom of the slope. As the ball rolls downhill, potential energy (stored energy due to its position) is gradually converted into kinetic energy (the energy of motion). This is essentially the principle of conservation of energy. So, at the top of the incline, the ball's energy is primarily potential energy, but as it descends, it gains speed and thus kinetic energy. At the bottom of the slope, all the potential energy has been converted to kinetic energy, hence it is at its maximum. Friction and air resistance could decrease the kinetic energy slightly, but when neglecting these factors, the ball's kinetic energy is greatest at the lowest point.
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It is desired that 7.7 mc of charge be stored on each plate of a 5.3 mf capacitor. what potential difference is required between the plates?
Mikes car can accelerate from 0 mph to 40mph in 5 seconds what is the acceeration of his car in miles per hour per second
A ray diagram shows that an object is placed between the focal point and the vertex of a convex mirror. What are the characteristics of the image produced by the object? inverted, smaller than object, real upright, smaller than object, virtual inverted, larger than object, real upright, larger than object, virtual
Answer:
B on EDGE2k21
Explanation:
trust me bih
A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be overcome to keep the object moving at a constant velocity?
We must remember that the total net force equation at constant velocity is:
F – Ff = 0
of
F - µN = 0
Using Newton's 2nd Law of Motion:The drawing (not to scale) shows one alignment of the sun, earth, and moon. the gravitational force vector f sm that the sun exerts on the moon is perpendicular to the force vector f em that the earth exerts on the moon. the masses are: mass of sun = 1.99 1030 kg, mass of earth = 5.98 1024 kg, mass of moon = 7.35 1022 kg. the distances shown in the drawing are rsm = 1.5 1011 m and rem = 3.85 108 m. determine the magnitude of the net gravitational force on the moon.
Solution:
Ms = 1.99 × 1030 kg− mass of Sun;
Me = 5.98 × 1024kg− mass of Earth;
Mm = 7.35 × 1022kg − mass of Moon;
rSM = 1.50 × 1011m − distance to the Moon from the Sun;
rEM = 3.85 × 108m − distance to the Moon from the Earth;
The gravitational force that acts on the Moon by the Earth (Law of Gravity):
[tex]F_{e} = G \frac {M_{e} * M_{m} } {r^{2}_{EM}} = 6.67 x 10^{-11} N * (\frac {m} {kg})^{2}*\frac {5.98 * 10^{24} kg * 7.35 * 10^{22} kg} {(3.85 x 10^{8}m)^{2}} = 1.98 * 10^{20} N[/tex]
The gravitational force that acts on the Moon by the Sun (Law of Gravity):
[tex]F_{S} = G \frac {M_{s} * M_{m} } {r^{2}_{EM}} = 6.67 x 10^{-11} N * (\frac {m} {kg})^{2}*\frac {1.99 * 10^{30} kg * 7.35 * 10^{22} kg} {(1.50 x 10^{11}m)^{2}} = 4.34 * 10^{20} N[/tex]
Net gravitational force on the moon:
[tex]F = F_{e} + F_{s} [/tex]
Pythagorean theorem for a right triangle ABC:
[tex]F = \sqrt {F^{2}_{S} + F^{2}_{e}} = \sqrt {(1.98 *
10^{20}N)^{2} + (4.34 * 10^{20} N)^{2}} = 4.77 * 10^{20}N[/tex]
Answer: Answer: magnitude of the net gravitational force on the moon is
4.77 × [tex]10^{20} [/tex]N.
The net gravitational force on the moon due to the earth and sun can be calculated using Newton's Law of Universal Gravitation. We apply this law to both the earth-moon and sun-moon systems, and the net force is the vector sum of these two forces.
Explanation:The net gravitational force exerted on the moon by the sun and the earth can be calculated using Newton's law of gravitation, which states that the force between two objects is proportional to the product of their masses divided by the square of the distance between them. We use this law twice: once for the earth-moon system and once for the sun-moon system.
For the Earth-Moon system: F_EM = (G * mass of earth * mass of moon) / (distance from earth to moon)². Given the values in the problem, this amounts to F_EM = (6.67 * 10⁻¹¹ N.m²/kg² * 5.98 * 10²⁴ kg * 7.35 * 10²² kg) / (3.85 * 10⁸ m)².
For the Sun-Moon system: F_SM = (G * mass of sun * mass of moon) / (distance from sun to moon)². Again, substituting the given values we have F_SM = (6.67 * 10⁻¹¹ N.m²/kg² * 1.99 * 10³⁰ kg * 7.35 * 10²² kg) / (1.5 * 10¹¹ m)².
The net gravitational force on the moon is given by the vector sum of these two forces, which form a right angle, due to the geometry of the situation. Hence, the net force is the hypotenuse of a right triangle with sides F_EM and F_SM, and can be calculated using Pythagoras' Theorem: Net Force = √(F_EM² + F_SM²).
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Give an example in which a small force exerts a large torque. give another example in which a large force exerts a small torque.
Answer:
Explanation:
Torque is defined as the product of force and the perpendicular distance.
If we take a screw driver of small length then we need to apply a large force to open or tighten the screw.
If a screw driver of long arm, then we need to apply small force to open or tighten the screw.
Which of the answer choices correctly describes covalent bonds?
A) An attraction between oppositely charged ions
B) A force that holds atoms or ions together in a fixed structure or unit
C) A sharing of four pairs (eight valence electrons) between two atoms
D) A sharing of an electrons pair between two atoms
Two spaceships that have different masses but rocket engines of identical force are at rest in space. if they fire their rockets at the same time, which ship will speed up faster
The ship that will speed up faster if they fire their rockets at the same time is; The one with the lower mass
Rocket PropulsionWe are told that;
There are two spaceships
Each spaceship has different masses
Each spaceship has rocket engines of identical force.
We know that formula for force is;
F = ma
Thus, if force is constant, the higher the mass, the lesser the acceleration and also the lesser the speed. Thus, the lower the mass the faster the speed.
This means the spaceship that will speed up faster will be the one with lesser mass.
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where do the three rays in a ray diagram start
In a ray diagram, the three rays usually originate from the same point on the object. Following predefined ray-tracing rules, these rays pass through or reflect off a lens or mirror, converging or diverging to form an image. The point where these rays intersect represents the location of the image.
Explanation:In a ray diagram, the three rays typically start from the same point on the object. This point on the object is the source from which the rays emanate. As the rays travel towards the lens or mirror involved, they will follow particular paths based on a set of simple ray-tracing rules. For example, one ray might pass through the focal point on its way to the lens and exit the lens parallel to the optical axis. These rays will then converge or diverge to form an image, depending on the lens or mirror set-up.
It is important to note that although three rays are often drawn for clarity and verification, only two are necessary to locate a point in the image. The point at which these rays intersect on the other side of the lens or mirror is where the image of the point from which they originated is located. Following these ray-tracing rules correctly will provide an accurate representation of how light behaves in the given optical system, illustrating the fundamental principles of geometric optics.
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A child has legs that are each 0.500 m long. What is her maximum walking speed?
A. 2.21 m/s
B. 2.19 m/s
C. 2.6 m/s
D. 5.58 m/s
Is grass abiotic or biotic
A squirrel has x-and y-coordinates (1.1 m, 3.4 m) at time t1= 0 and coordinates (5.3 m, -0.5 m) at time t2= 3.0 s. for this time interval, find (a)the components of the average velocity
Final answer:
The x-and y-components of the squirrel's average velocity for the given time interval are 1.4 m/s and -1.3 m/s, respectively. These are found by dividing the changes in position by the time interval.
Explanation:
The student is asking for the calculation of the components of the average velocity of a squirrel over a time interval. To find these components, we use the formula for average velocity, which is given by the change in position (Δx and Δy) divided by the change in time (Δt). The changes in the x- and y-coordinates are found by subtracting the initial coordinates from the final coordinates.
The change in the x-coordinate (Δx) is
5.3 m - 1.1 m = 4.2 m
The change in the y-coordinate (Δy) is
-0.5 m - 3.4 m = -3.9 m
The change in time (Δt) is
t2 - t1 = 3.0 s - 0 = 3.0 s
Thus, the x-component of the average velocity is
Δx/Δt = 4.2 m/3.0 s = 1.4 m/s
and the y-component of the average velocity is
Δy/Δt = -3.9 m/3.0 s = -1.3 m/s.
A mass oscillates on the end of a spring, both on earth and on the moon. where is the period the greatest?
Final answer:
The period of oscillation of a mass on a spring is the same on both Earth and the Moon, as it is independent of gravity.
Explanation:
The question asks where the period of oscillation of a mass on a spring is the greatest, either on Earth or on the Moon. The period of a spring-mass system, according to the formula T = 2π√(m/k), where T is the period, m is the mass, k is the spring constant, and π (pi) is approximately 3.14159, is independent of gravity. Hence, the gravitational differences between the Earth and the Moon do not affect the period directly. However, external forces like gravity can influence the amplitude of the oscillation, not the period itself. Therefore, the period of oscillation will be the same on both the Earth and the Moon, assuming no other factors are changed.
A carnot engine rejects 80 mj of energy every hour by transferring heat to areservoir at 10°c. determine the temperature of the high-temperature reservoir and the power produced if the rate of energy addition is 40 kw.
The temperature of the high-temperature reservoir of a Carnot engine releasing 80 MJ/hour to a 10°C reservoir and receiving energy at the rate of 40 kW is approximately 510.72 K. The power produced by this engine is approximately 17.78 kW.
Explanation:The temperature of the high-temperature reservoir of the Carnot Engine can be determined using Carnot's theorem, which states that Qc/Qh=Tc/Th or its simplified version, efficiency (Eff) = 1 - (Tc/Th) for a Carnot engine. Given the energy released by the engine (Qc) as 80 MJ/hour or 22.22 kW, and the rate of energy addition (Qh) as 40 kW, we can determine the temperature of the high-temperature reservoir (Th) from the ratio of these values and the known temperature of the cold reservoir (Tc) of 10°C or 283.15 Kelvin (K).
To achieve this, we first determine the engine's efficiency. Given Qc and Qh, we have Eff = 1 - (Qc/Qh) = 1 - (22.22 kW / 40 kW) = 0.445 (or 44.5%). Applying this to the efficiency formula, 'Eff = 1 - (Tc/Th)', we can rearrange this to find 'Th = Tc / (1 - Eff) = 283.15 K / (1 - 0.445) = 510.72 K'. Hence, the temperature of the high-temperature reservoir is approximately 510.72 K.
The power produced is the difference between the energy added and the energy rejected, so Power = Qh - Qc = 40 kW - 22.22 kW = 17.78 kW.
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The main purpose of a service panel in a house is to A. keep the meter working correctly. B. connect the service drop to the house. C. provide automatic circuit protection and prevent fires. D. keep electrical hazards localized.
keep electrical hazards localized
The number of hours of daylight at any place on earth depends on
describe an electromagnet and how it is used
An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. The magnetic field disappears when the current is turned off. Electromagnets usually consist of insulated wire wound into a coil. A current through the wire creates a magnetic field which is concentrated in the hole in the center of the coil. The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.
The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.
Electromagnets are widely used as components of other electrical devices, such as motors, generators, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment. Electromagnets are also employed in industry for picking up and moving heavy iron objects such as scrap iron and steel.[2]
Electromagnets are temporary magnets powered by electric current with versatile applications in different fields.
**An electromagnet** is a piece of wire that generates a magnetic field when an electric current passes through it. Unlike permanent magnets, **electromagnets** can be turned on and off by controlling the flow of electricity. They are widely used in various applications such as electric motors, generators, MRI machines, and even in scrapyard cranes.
A gasoline engine operates at a temperature of 270°c and exhausts at 180°c. calculate the maximum efficiency of this engine. (note that the celsius scale is used.)
16.6 is the answer. Not 17.0 do not round.
An object floats on water with 80% of its volume below the surface. the same object when placed in another liquid floats on that liquid with 72% of its volume below the surface. determine the density of the unknown fluid.
A jet plane is flying at a constant altitude. at time t1=0 it has components of velocity vx= 94 m/s , vy= 110 m/s . at time t2= 33.5 s the components are vx= 175 m/s , vy= 45 m/s . part a for this time interval calculate the average acceleration. give your answer as a pair of components separated by a comma. for example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. express your answer using two significant figures.
The average acceleration components of the jet plane for the given time interval are approximately 2.4, -1.9 m/s², calculated using the change in velocity components divided by the time interval.
To calculate the average acceleration of a jet plane flying at a constant altitude with given velocity components at two different times, we use the formula for average acceleration: a = (v_f - v_i) / Δt, where a is the average acceleration, v_f is the final velocity, v_i is the initial velocity, and Δt is the change in time.
Given the initial velocity components at t1=0 are v_x1 = 94 m/s and v_y1 = 110 m/s, and the final velocity components at t2=33.5 s are v_x2 = 175 m/s and v_y2 = 45 m/s, we can calculate the average acceleration components as follows:
Average acceleration in the x-direction: a_x = (v_x2 - v_x1) / Δt = (175 m/s - 94 m/s) / 33.5 s = 2.42 m/s²Average acceleration in the y-direction: a_y = (v_y2 - v_y1) / Δt = (45 m/s - 110 m/s) / 33.5 s = -1.94 m/s²Therefore, the average acceleration components for the time interval are approximately 2.4, -1.9 m/s².
A scientific _______ is a unifying explanation for a set of observations that has been verified by multiple testing. hypothesis belief law theory
The elements required for a fire to start are
A force of 110 N is applied horizontally to the handles of a lawnmower to move it at a speed of 0.80 m/s across a lawn. Find the power used to mow the lawn.
The power used to mow the lawn, with a force of 110 N applied to move the lawnmower at 0.80 m/s, is calculated using the formula P = F × v and results in 88 Watts.
Explanation:To calculate the power used to mow the lawn, we use the formula for power, which is the rate of doing work. Power (P) is equal to the work done (W) divided by the time taken (t), or P = W/t. In this case, work done can also be described as the force applied (F) times the distance moved (d) in the direction of the force, but since the problem doesn't provide the distance and only provides the speed at which the lawnmower is moving, we can use another formula for power: P = F × v where v is velocity.
Given that the force (F) is 110 N and the velocity (v) is 0.80 m/s, we can find the power with P = 110 N × 0.80 m/s giving us:
P = 88 Watts.
This is the power used by the person to mow the lawn while applying a constant horizontal force to move the lawnmower at a constant speed.
How much would you have to raise the temperature of a copper wire (originally at 20 ?c) to increase its resistance by 18 % ? the temperature coefficient of resistivity of copper is 0.0068 (?c)?1?
To increase the resistance of the copper wire by 18%, the temperature will be increase to 46.47 °C
Data obtained from the question Original temperature (T₁) = 20 °C Original resistance (R₁) = RNew resistance (R₂) = 18% increase = 1.18RCoefficient of resistivity (α) = 0.0068 °C¯¹New temperature (T₂) =? How to determine the new temperatureα = R₂ – R₁ / R₁(T₂ – T₁)
0.0068 = 1.18R – R / R(T₂ – 20)
0.0068 = 0.18R / R(T₂ – 20)
0.0068 = 0.18 / (T₂ – 20)
Cross multiply
0.0068 (T₂ – 20) = 0.18
Divide both side by 0.0068
T₂ – 20 = 0.18 / 0.0068
T₂ – 20 = 26.47
Collect like terms
T₂ = 26.47 + 20
T₂ = 46.47 °C
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