Given the values of the derivative f′(x) in the table and that f(0)=150, find or estimate f(x) for x=0,2,4,6.

Answers

Answer 1
Final answer:

To find or estimate f(x) for x=0,2,4,6, integrate the given derivative f'(x) with respect to x to find the constant term. Then, add each value of f'(x) in the table to the constant term to obtain the values of f(x) for x=0,2,4,6.

Explanation:

To find or estimate f(x) for x=0,2,4,6, we need to use the values of the derivative f'(x) given in the table. Since f'(x) represents the rate of change of f(x) at different values of x, we can use the derivative to find or estimate the values of f(x). Given that f(0) = 150, we can start by finding the constant term of the function using this initial condition.

To find the constant term, we need to integrate the derivative f'(x) with respect to x. This will give us the original function f(x).Integrating f'(x) gives us f(x) = 150 + C, where C is the constant term we need to find.Next, we can use the given values of f'(x) in the table to find or estimate the corresponding values of f(x) for x=0,2,4,6.Let's assume that the third column in the table represents the values of f'(x) at different values of x. We can add each value to the constant term C to obtain the values of f(x) for x=0,2,4,6.

Therefore, by integrating f'(x) and adding the constant term, we can find or estimate the values of f(x) for x=0,2,4,6.

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Related Questions

This graph shows a portion of an even function. Use the graph to complete the table of values.

Answers

1
1
3
3

all you really have to look at is how the graph is set up and then you have the answers like up top

1, 1, 3, 3 - I just did it on e2020 and got it correct

convert y=2x-7 to slope intercept form

Answers

It is already in slope-intercept form: y = mx + b

So y = 2x - 7
It is already in that form lol

It is important to re-evaluate financial goals periodically. In which of the following situations would it be necessary to change an existing financial goal?
a. You fell sharply behind your expected schedule with regard to saving.

b. You recovered from an unexpected expense and are rattled that you did not see it coming.

c. You married, and your spouse has a similar financial goal.

d. You came across unexpected income.



Please select the best answer from the choices provided
A
B
C
D

Answers

The answer to the question is A
The answer is A. You fell sharply behind your expected schedule with regard to saving. 
You're financial goal and planning should be designed to fulfill a realistic expectation on your financial situation somewhere in the future.
When you're behind the schedule, you should either bring down the threshold for your financial goals to make it more realistic to achieve or find  another source of income so your target could still be fulfilled even though you have to make additional sacrifice

**I really need help on this! Please answer!*
The table shows the scoring system for quarterbacks in Jeremy's fantasy football league. In one game, Jeremy's quarterback had 2 touchdowns passes, 16 complete passes, 7 incomplete passes, and 2 interceptions. How many total points did Jeremy's quarterback score?

**QUARTERBACK SCORING**
Touchdown pass - 6
Complete pass - 0.5
Incomplete pass - -0.5
Interception - -1.5

Answers

The total number of points = 13.5 points

What is the total amount of points gained?

We are given the scoring method as:

Touchdown pass: 6

Complete pass : 0.5

Incomplete pass : -0.5

Interception : -1.5

Now, we are told that Jeremy's quarterback had the following:

2 touchdowns passes,

16 complete passes,

7 incomplete passes,

2 interceptions.

Thus:

Total points = (2 * 6) + (0.5 * 16) + (-0.5 * 7) + (-1.5 * 2)

Total points = 13.5 points

Brenda can deliver 644 newspapers in 7 hours. How many newspapers can Brenda deliver in 9 hours?

Answers

644/7= 92
92 per day
92x 9= 828

Answer is 828 newspapers
First, you divide 644 by 7 to find out how many she can deliver in 1 hour.
That gives you 92.
Times that by 2 and get 184, then add 644 to that.
That equals 828, and that is your answer.
Brenda can deliver 828 newspapers in 9 hours.
Hope this helps

describe how you would Use the distributive property to simplify 39 * 5

Answers

To use the distributive property in this equation, you would separate 39 into 30 and 9. Then you would multiply 5 by 30 and 5 by 9. Hope this helps! :D

~PutarPotato
Seperate 39 into 30 and 9. Than you would multiply 5 by 30 and 5 by 9.

Someone please help me!

Answers

now, if the outside diameter is 3.5, then its radius is half that, or 1.75, whilst if the inner diameter is 3.25, then its half for the radius is 1.625.

check the picture below.

The perimeter of a rectangle is 400 yards. What are the dimensions of the rectangle if the length is 80 yards more than the width?

Answers

2L+2w=400
L=80+w
2(80+w)+2w=400
160+2w+2w=400
160+4w=400
4w=240
w=60
L=80+60
L=140
So, the length is 140 and the width is 60

The width is 60 yards and the length, being 80 yards more, is 140 yards.

To find the dimensions of the rectangle when the perimeter is 400 yards and the length is 80 yards more than the width, we can set up two equations based on the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.

Let the width be w. Then the length is w + 80 yards.

Using the perimeter formula:

400 = 2(w + 80) + 2w

400 = 2w + 160 + 2w

400 = 4w + 160

Subtract 160 from both sides:

240 = 4w

Divide by 4:

w = 60 yards

Now, calculate the length:

l = w + 80 = 60 + 80

l = 140 yards

The width is 60 yards, and the length is 140 yards.

A child types the letters q, w, e, r, t, y, randomly producing 1000 letters in all. what is the expected number of times that the sequence qqqq appears, counting overlaps

Answers

1/6*1/6*1/6*1/6 = 1/1296 = 0.078% probability of ANY 4-letter sequence (including qqqq)
1000/1296 is less than 1.
Expected number of times qqqq (or any given 4-letter sequence) will appear in 1000 letters is 0.
Final answer:

The expected number of times the sequence 'qqqq' appears in 1000 random typings of 6 different letters is approximately 0.769 times.

Explanation:

This problem falls under the category of discrete probability in mathematics. The child randomly types one of 6 different letters.

Therefore, the probability of typing any one specific letter, such as 'q', is 1/6. The sequence 'qqqq' is a sequence of 4 specific letters. Thus, the probability of typing this sequence at any given point is (1/6)^4 or 1/1296.

To find the expected number of times the sequence 'qqqq' will appear in 1000 typed letters, we multiply the probability of the event by the number of attempts. However, because 'qqqq' is a sequence of 4 letters, our attempts are based on 4-letter sequences and not individual letters. So, instead of 1000 letters, we have 1000 - 4 + 1 = 997 possible 4-letter sequences in 1000 letters.The expected number of times the sequence 'qqqq' will appear is then 997 * (1/1296) which is approximately 0.769. In simple words, we would expect the sequence 'qqqq' to occur around 0.769 times or less than once in 1000 random typings of the 6 different letters.

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the product of two consecutive even positive integers is 10 more than seven times the larger . find the integers?

Answers

2 consecutive even numbers.....x and x + 2

x(x + 2) = 7(x + 2) + 10
x^2 + 2x = 7x + 14 + 10
x^2 + 2x = 7x + 24
x^2 + 2x - 7x - 24 = 0
x^2 - 5x - 24 = 0
(x - 8)(x + 3) = 0

x - 8 = 0
x = 8

x + 3 = 0
x = -3...not this one because it is negative

x = 8
x + 2 = 8 + 2 = 10

so ur 2 consecutive even numbers are 8 and 10

The current (I) in an electrical conductor varies inversely as the resistance (r) of the conductor. The current is 2 amperes when the resistance is 960 ohms. What is the current when the resistance is 480 ohms?

Answers

the current is 4 amperes
[tex]I=\frac{k}{r}[/tex], where [tex]k[/tex] is constant of variation.
[tex]\frac{2}{1} = \frac{k}{960} \\k=2\cdot960=1920[/tex].

Since we know the data to find the current when the resistance is 480 Ohms [tex]\Rightarrow[/tex] [tex]I=\frac{k}{r}=\frac{1920}{480}=4 \ amperes[/tex].

Suppose you are taking the bus home, and can take either the 51 or the 82. you know that the 82 will arrive in exactly 10 minutes, but because the 51 is unreliable, you suspect that the amount of time until it arrives is uniformly distributed between 0 and 30 minutes. you take the first bus that arrives. let t be the number of minutes you wait until you board a bus. find e[t].

Answers

Final answer:

The expected waiting time for a bus, E[t], is 8.33 minutes, which is calculated considering the possibility of either bus 51, which has a uniform arrival time between 0 to 30 minutes, or bus 82, which arrives in exactly 10 minutes.

Explanation:

The problem you are dealing with involves finding the expected waiting time, E[t], for either bus 51 or bus 82 to arrive. The expected value of a uniformly distributed random variable on an interval [a, b] is given by the formula (a + b)/2. However, we need to account for the fact that if bus 82 arrives in exactly 10 minutes, then if the 51 bus hasn't arrived by then, you will take the 82 bus.

To compute E[t], if the 51 bus arrives within the first 10 minutes, the expected waiting time is the average of 0 and 10 minutes, which is 5 minutes. If the 51 bus does not arrive within 10 minutes, you will take the 82 bus at exactly 10 minutes. Therefore, the expectation must only account for the time if the 51 bus arrives before the 82. This gives us:

The probability that the 51 bus arrives in the first 10 minutes is 10/30 = 1/3.

The expected waiting time if 51 arrives in the first 10 minutes is 5 minutes.

If the 51 bus does not arrive within 10 minutes, you'll wait exactly 10 minutes for the 82 bus.

So, E[t] = (1/3) * 5 minutes + (2/3) * 10 minutes = (5 + 20)/3 = 25/3 minutes.

Therefore, the expected waiting time E[t] is 8.33 minutes (rounded to two decimal places).

what is the basic ratio for 30:42

Answers

30:42 is represented as 30/42
The lowest form for that is 5/7. Hope that helped. Good luck
Final answer:

The basic ratio of 30:42 is 5:7. This was found by simplifying the ratio to its lowest terms, which is done by dividing both sides of the ratio by the largest number that can evenly divide both numbers, the greatest common factor (GCF).

Explanation:

The basic ratio of 30:42 is found by simplifying the ratio to its lowest terms. To do this, find the greatest common factor (GCF) of the two terms, which is the largest number that can evenly divide both numbers. In this case, the GCF of 30 and 42 is 6. Therefore, by dividing both sides of the ratio by 6, we get the simplified ratio: 5:7. So, the basic ratio for 30:42 is 5:7.

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Find the volume of the solid region. the solid between the planes z = 3x + 2y + 1 and z = x + y, and above the triangle with vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0) in the xy-plane.

Answers

The volume of the solid region. the solid between the planes z = 3x + 2y + 1 and z = x + y, and above the triangle with vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0) in the xy-plane is 6 cubic unit.

What is volume?

It is defined as a three-dimensional space enclosed by an object or thing.


It is given that

The solid between the planes z = 3x + 2y + 1 and z = x + y, and above the

triangle with vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0) in the xy-plane.

r(u) = (1, 2)

r(v) = (-2, -1)

|r(u)xr(v)| = 3

The volume of the solid:

∬S(3x + 2y + 1 − x − y)ds = ∫₀¹ ∫(u, 0)(2x + y +1)3 dv du

After solving:

= 3(4/3 - 5 /6 + 3/2)

= 6

Thus, the volume of the solid region. the solid between the planes z = 3x + 2y + 1 and z = x + y, and above the triangle with vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0) in the xy-plane is 6 cubic unit.

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Final answer:

The volume of the solid region between the planes z = 3x + 2y + 1 and z = x + y, above the triangular region in the xy-plane, can be found using a double integral over the triangular area defined by vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0).

Explanation:

To find the volume of the solid region between the planes z = 3x + 2y + 1 and z = x + y, and above the triangular region in the xy-plane, we can use a double integral over the triangular region. The volume is given by the difference between the two planes integrated over the area of the triangle formed by the vertices (1, 0, 0), (2, 2, 0), and (0, 1, 0).

First, define the vertices of the triangle in the xy-plane: A(1, 0), B(2, 2), and C(0, 1).

Second, find the equations of the lines forming the sides of the triangle, which helps in defining the limits of the integral.

Lastly, set up the double integral:

∫∫ (3x + 2y + 1) - (x + y) dA,

after solving, we get volume = 6

where dA is the differential area element in the xy-plane, and the limits of integration are determined by the triangular region.

The integration can be simplified by determining a suitable ordering for dx and dy, often choosing to integrate in x first and then y, or vice versa, based on the geometry of the triangle. The exact bounds for x and y need to be worked out from the equations of the lines defining the triangle's edges.

The result of this integral will give the volume of the solid region bounded by the two planes and above the triangle.

Using sum or difference formulas, find the exact value of sin(165∘)
Express your answer in the form
sin(165∘)=√a(√b−1)/4 for some numbers a and b

Answers

We have a = 2 and b = 3.

To find the exact value of sin(165°) using sum or difference formulas, we notice that 165° can be expressed as the sum of two angles whose sine and cosine values we know exactly, for example, 120° and 45°. The sum formula for sine is sin(A + B) = sin(A)cos(B) + cos(A)sin(B).

Therefore, sin(165°) = sin(120° + 45°) = sin(120°)cos(45°) + cos(120°)sin(45°).

From here, we use the known values:

sin(120°) = sin(180° - 60°) = sin(60°) = √3/2

cos(45°) = √2/2

cos(120°) = cos(180° - 60°) = -cos(60°) = -1/2

sin(45°) = √2/2

Plugging these values into our formula gives:
sin(165°) = ( √3/2)(√2/2) + (-1/2)(√2/2) = (√6 - √2)/4

This fraction can be rewritten to match the given form by factoring out √2 in the numerator:
sin(165°) = √2(√3 - 1)/4

Hence, in the form sin(165°) = √a(√b - 1)/4, we have a = 2 and b = 3.

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the extreme values of the function subject to the given constraint. f(x, y, z) = 8x + 8y + 4z; 4x2 + 4y2 + 4z2 = 36

Answers

[tex]L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)[/tex]

[tex]L_x=8+8\lambda x=0\implies 1+\lambda x=0[/tex]
[tex]L_y=8+8\lambda y=0\implies 1+\lambda y=0[/tex]
[tex]L_z=4+8\lambda z=0\implies 1+2\lambda z=0[/tex]
[tex]L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9[/tex]

[tex]yL_x=y+\lambda xy=0[/tex]
[tex]xL_y=x+\lambda xy=0[/tex]
[tex]\implies yL_x-xL_y=y-x=0\implies y=x[/tex]

[tex]2zL_x=2z+2\lambda xz=0[/tex]
[tex]xL_z=x+2\lambda xz=0[/tex]
[tex]\implies 2zL_x-xL_z=2z-x=0\implies x=2z[/tex]

[tex]2zL_y=2z+2\lambda yz=0[/tex]
[tex]yL_z=y+2\lambda yz=0[/tex]
[tex]\implies 2zL_y-yL_z=2z-y=0\implies y=2z[/tex]

[tex]x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1[/tex]

[tex]z=\pm1\implies y=x=\pm2[/tex]

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

The extreme max value is "[tex]f(x,y,z) = 36[/tex]" and min value is "[tex]f(x,y,z) = -36[/tex]".

According to the question,

[tex]f(x, y, z) = 8x + 8y + 4z[/tex]

let,

[tex]g(x,y,z) = 4x^2 + 4y^2 + 4z^2 - 36[/tex]

By using Lagrange multipliers,

→ [tex]\bigtriangledown f= \lambda \bigtriangledown g[/tex]...(equation 1)

[tex]\bigtriangledown f = <8,8,4>[/tex][tex]\bigtriangledown g = <8x, 8y,8z>[/tex]

∴ [tex]<8,8,4>=<8\lambda x, 8 \lambda y, 8 \lambda z >[/tex]

then,

[tex]8 \lambda x = 8[/tex]...(equation 2)[tex]8 \lambda y =8[/tex]...(equation 3)[tex]8 \lambda z = 4[/tex]...(equation 4)

→ [tex](x = \frac{1}{\lambda}, y=\frac{1}{\lambda}, z =\frac{1}{2 \lambda} )[/tex]

As we know,

→             [tex]4x^2 +4y^2+4z^2=36[/tex]

By substituting the values, we get

→ [tex]4(\frac{1}{\lambda} )^2+ 4(\frac{1}{\lambda} )^2+4(\frac{1}{2\lambda} )^2 =36[/tex]

→                 [tex]\frac{4}{\lambda^2} +\frac{4}{\lambda^2} +\frac{1}{\lambda^2} =36[/tex]

→                                  [tex]\frac{9}{\lambda^2}=36[/tex]

                                     [tex]\frac{1}{\lambda}= \pm \frac{6}{3}[/tex]

                                     [tex]\frac{1}{\lambda} = \pm 2[/tex]

x = 2, y = 2, z = 1

then,

→ [tex]f(x,y,z) = 36[/tex] (Extreme max value)

and,

x = -2, y = -2, z = -1

then,

→ [tex]f(x,y,z) = -36[/tex] (min value)

Thus the above answer is correct.

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A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. The northbound train travels 4 miles per hour faster than the southbound train. After 2.5 hours, they are 330 miles apart. At what speeds are the two trains traveling?

Answers

recall your d = rt, distance = rate * time.

if, the southbound train is going at a speed of say " r " mph, since we know that the northbound one is going faster by 4 miles, than is really going at " r + 4 " mph then.

now, we know in 2.5 hours, they're 330 miles from each other, thus the southbound train has been rolling for 2.5 hours, and the northbound train has also been rolling for 2.5 hours.

if the northbound train has covered on those 2.5 hours say " d " miles, then the southbound train has covered the slack, or " 330 - d ".

[tex]\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{t}\\ &------&------&------\\ Northbound&d&r+4&2.5\\ Southbound&330-d&r&2.5 \end{array} \\\\\\ \begin{cases} \boxed{d}=2.5(r+4)\\ 330-d=2.5r\\ ----------\\ 330-\boxed{2.5(r+4)}=2.5r \end{cases} \\\\\\ 330-2.5r-10=2.5r\implies 320=5r\implies \cfrac{320}{5}=r\implies 64=r[/tex]

how fast is the northbound going?  well, r + 4.

a diamond's density is 3.2 g/cm3

determine the volume of a diamond that has a mass of 1 g

Answers

The answer is:  "0.3125 cm³ "  ;  or; write as:  "13/40  cm³ " .
________________________________________________________ 

1 g * (1 cm³ / 3.2g) = __?___ cm³  ;

The units of "g" cancel ; 

and we have:  (1/3.2)  cm³ ;
 
 =  (1 ÷ 3.2) cm³ ;
 
 =  0.3125 cm³ ;  or; write as:  13/40  cm³
_____________________________________

Chris plans to mulch the Border surrounding a rectangular Garden in his backyard if the length of L of the garden (exculding its border) is 3 more than twice its width w and the width of the border is 1/4w which function repersents tje area A to be mulched in terms of w?

Answers

The answer by the sequence:

Width of the garden = w
Length of the garden  = 2w+3

Width of the entire plot = w + 0.5w = 1.5w
Length of the entire plot = (2w + 3) 0.5w = 2.5w + 3

Area of the garden = w (2w + 3) 
Area of the entire plot = 1.5w (2.5w + 3)

Area of the garden = 2w² + 3w
Area of the entire plot = 3.75w² + 4.5w

Area of border = area of the entire plot - area of the garden
                          = 3.75w² + 4.5w - (2w² + 3w)

Area of the border = 3.75w² + 4.5w - 2w² - 3w

Area of the border = 1.75w² + 1.5w

Consider the exponential function f(x) = 3 and its graph. Which statements are true for this function and graph? Check all that apply. The initial value of the function is . The growth value of the function is . The function shows exponential decay. The function is a stretch of the function f(x) = . The function is a shrink of the function f(x) = 3x. One point on the graph is (3, 0).

Answers

The function is a stretch of the function f(x) = (1/3)x .

The function shows exponential growth a stretch of the function f(x) = (1/3)^x .

What are exponential functions?

When the expression of a function is such that it involves the input to be present as the exponent (power) of some constant, then such a function is called an exponential function. Their usual form is specified below. They are written in several equivalent forms.

Given that the exponential function f(x) = 3

The initial value of the function is 2.

The base of the function is 3.

When the intial value is where x=0

where x=0, the value of f(0)=3

The growth is 1/3 but it is decay, that might be correct, or not because it is decay.

It is a stretch of the function f(x)=(1/3) power of x

when x=3, then f(3)=1/9

The function shows exponential growth a stretch of the function f(x) = [tex](1/3)^x[/tex].

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7/6 - 4/3n = -3/2n + 2(n + 3/2)

Answers

2n/3+25/6 I simplified the question if that is  what you wanted me to do.

How to solve -5 3/14 to the thousandths place?? Please help

Answers

first off, let's change the mixed fraction to "improper", and do the division then.

[tex]\bf \stackrel{mixed}{-5\frac{3}{14}}\implies -\cfrac{5\cdot 14+3}{14}\implies \stackrel{improper}{-\cfrac{73}{14}}\implies -73\div 14\approx -5.21428571 \\\\\\ -5.\stackrel{tenth}{2}~\stackrel{hundreth}{1}~\stackrel{thousandth}{4}[/tex]

baby sister took nap for 2 hours and 22 minutes and 1 hour and 35 minutes yesterday. how many more minutes did she sleep yesterday than today

Answers

Your baby sister slept 47 minutes longer today then yesterday

Write the fact family for the numbers 32,8,and 4

Answers

Assuming that you meant factor family to be a factor tree.

               32                                     8                                           4 
            16       2                             4   2                                       2 2
         4      4                                 2 2
       2 2  2  2

Evaluate the series 50 + 10 + 2 + . . .

Answers

It is a sum of geometric series, where first term [tex]a_1=50[/tex] and common ratio:

[tex]r=\dfrac{a_2}{a_1}=\dfrac{10}{50}=\dfrac{1}{5}[/tex]

so:

[tex]S=50+10+2+\ldots=\dfrac{a_1}{1-r}=\dfrac{50}{1-\frac{1}{5}}=\dfrac{50}{\frac{4}{5}}=\dfrac{50\cdot5}{4}=\dfrac{250}{4}=\boxed{62.5}[/tex]

A and B are vertical angles. If A = 4x - 10 and B = 6x - 30, find mA.

Answers

vertical angles
m<A = m<B
so
4x - 10 = 6x - 30
6x - 4x = -10 + 30
2x = 20
x = 10

m<A = 4x - 10
m<A = 4(10) - 10
m<A = 40 - 10
m<A = 30

If A and B are vertical angles, then A = B.  Thus, 4x - 10 = 6x - 30, and 10 = x.  Check:  Does 4(10) - 10 = 6(10) - 30?  Does 30 = 30?  YES.  So x = 10 is correct.  The measure of angle A is 30 degrees.

which function is an even function?

Answers

C. cos one because its the only one out of the answer choices that is even in the 12 basic funtions
A function f is an even function, if for all x we have  f(x)=f(-x).

All the functions in the problem are constant functions, because no x is involved.

For example, consider the first function: [tex]f(x)=sin(-3 \pi)[/tex], 

[tex]sin(-3 \pi )[/tex] is just a constant value.( it is actually equal to 0)

Thus for any x, f(x) = 0 and f(-x) =0


This can be said for all constant functions: all of them are even functions.


Answer: all

Consider the linear function that is represented by the equation y=-10x+6 and the linear function that is represented by the equation y-36=8(x-4). Which statement is correct regarding their slopes and y-intercepts?

a. The function that is represented by the equation y=-10x+6 has a steeper slope and a greater y-intercept.

b. The function that is represented by the equation y=-10x+6 has a steeper slope, and the function that is represented by the equation y-36=8(x-4) has a greater y-intercept.

c. The function that is represented by the equation y-36=8(x-4) has a steeper slope, and the function that is represented by the equation y=-10x+6 has a greater y-intercept.

d. The function that is represented by the equation y-36=8(x-4) has a steeper slope and a greater y-intercept.

Answers

This is about understanding slopes.

Option A is correct.

We are given two linear functions which are;

y = -10x + 6  - - - (eq 1)

y - 36 = 8(x - 4)  - - - (eq 2)

Formula for straight line equation is;

y = mx + c

Where m is slope and c is the y intercept.

Let's expand eq 2 to be in the form of y = mx + c

Thus;

>>y - 36 = 8(x - 4)

>> y - 36 = 8x - 32

>> y = 8x - 32 + 36

>> y = 8x + 4  - - - (eq 3)

Thus, slope of eq 1 is -10 and y-intercept is 6.

Similarly, slope of eq 3 is 8 and y-intercept is 4.

This means y = -10x + 6 has a greater y-intercept than y - 36 = 8(x - 4).

Also, the slope in y - 36 = 8(x - 4) which is 8 will slope to the right while the slope of y = -10x + 6  which is -10 will slope to the left. This means that line represented by y = -10x + 6  has a steeper slope.

This is because the higher the slope, the steeper the line.

Read more at; brainly.in/question/12866833

After rewriting both equations in slope-intercept form, we find that the function y = -10x + 6 has a steeper slope and the function y - 36 = 8(x - 4) has a greater y-intercept, making option (b) the correct answer.

The question involves comparing the slopes and y-intercepts of two linear functions, represented by the equations y = -10x + 6 and y - 36 = 8(x - 4). To compare them, we need to write both equations in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

The first equation, y = -10x + 6, is already in slope-intercept form, with a slope of -10 and a y-intercept of 6. For the second equation, y - 36 = 8(x - 4), we first distribute the 8 to get y - 36 = 8x - 32 and then add 36 to both sides to get the slope-intercept form, y = 8x + 4, which has a slope of 8 and a y-intercept of 4.

Comparing the slopes, -10 for the first equation and 8 for the second, we see that the first equation has a steeper slope because -10 has a greater magnitude than 8. Comparing the y-intercepts, 6 for the first equation and 4 for the second, the first equation has a greater y-intercept. Therefore, the correct statement regarding their slopes and y-intercepts is (b) The function that is represented by the equation y = -10x + 6 has a steeper slope and the function that is represented by the equation y - 36 = 8(x - 4) has a greater y-intercept.

Which triangle has 0 reflections of symmetry

Answers

Answer:

The answer would be option A the scalene triangle

Answer:

The first triangle, or, A !!

Step-by-step explanation:

Is y=7x+2 x+7y=8 parallel, perpendicular, or neither?

Answers

rearrange them to slope-intercept form

y = 7x + 2

y = -(1/7) x + 8

product of their slopes is  7 * -1/7  = -1  so they are perpendicular
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