The spanish song Decima has ten lines
Final answer:
A decima is a Spanish form of poetry that consists of ten lines per stanza, with a fixed rhyme pattern of ABBAACCDDC, representing a distinct structure from other forms like sonnets or haikus.
Explanation:
The decima is a form of Spanish poetry. Unlike a sonnet, which typically comprises fourteen lines and may follow various rhyme schemes such as the Shakespearian or Petrarchan forms, the decima is characterized by its ten-line stanzas. These stanzas adhere to a specific rhyme pattern and are traditionally written in eight-syllable lines. Each line in a decima ends with a rhyme following the pattern ABBAACCDDC. The form is quite popular in Spanish literature and folk music, and it is distinct in its total line count from other forms like the sonnet, sestina, and haiku.
Adrianna has fabric that is 34 yard long. She needs to cut the fabric into pieces that are 18 yard long. How many 18 -yard-long pieces will she have?
Question 4 options:
6
7
8
9
(Will give brainliest- please explain)
Answer:
2
Step-by-step explanation:
Dividing 18 yds into 34 yds yields 2; Adrianna will have 2 pieces 18 yds long, with 8 yds left over.
PLEASE Explain how to prove one of the following: In an isosceles trapezoid, how do you prove the base angles are congruent or in a kite the long diagonal of a kite is a perpendicular bisector to the short diagonal, how can you prove that adjacent sides are congruent in a kite?
Final answer:
Adjacent sides in a kite are congruent, which can be proven using the definition of a kite, the Reflexive Property of Equality, and the SAS Postulate to show that the two triangles formed by the diagonal are congruent.
Explanation:
To prove that adjacent sides are congruent in a kite, recall the definition of a kite: a quadrilateral with two distinct pairs of adjacent sides that are congruent. Let's name the kite ABCD where AB and AD are one pair of congruent sides, and BC and DC are the other pair. The longer diagonal, which we'll call AC, bisects the kite into two congruent triangles, ∆ABC and ∆ADC. By the definition of a kite, we know that AB = AD and BC = DC.
Now, since AC is the common side in both ∆ABC and ∆ADC, by the Reflexive Property of Equality, AC = AC. With two sides and the included angle (BAC and DAC are congruent as they are both angles cut by diagonal AC) congruent in both triangles, we apply the SAS Postulate (Side-Angle-Side) to prove that the triangles are congruent. Once the triangles are proven congruent, all their corresponding parts are congruent. Therefore, AB = AD and BC = CD, which means the adjacent sides in the kite are indeed congruent.
Amy has 3 children, and she is expecting another baby soon. Her first three children are girls. Is the sex of the fourth baby dependent or independent of the first three?
A) Independent. With every child, there is a 50% chance of having a boy or girl.
Eliminate
B) Dependent. Amy has not had a boy yet, so her chance of having a boy is greater.
C) Dependent. Every time Amy has a baby, the chances of having another girl increase.
D) Independent. Only the mom and dad determine the sex of that baby, not the siblings.
Answer:
I would say D.) is the best choice in this situation, The amount of female children you have does not determine the Gender that your child will be, The kids have nothing to do with the situation, The Father and Mother are what determine the Gender.
Answer:
Option A is right
Step-by-step explanation:
Given that Amy has 3 children, and she is expecting another baby soon. Her first three children are girls.
The fourth baby is independent of first three babies
As regards child birth, each trial is independent of the other with probability for a girl or boy equally likely with p = 0.5 = q
Hence option A is right answer.
Option B is wrong because the previous 3 girls have nothing to affect the sex of 4th child
Option C is wrong, since each trial is independent
D) is wrong since even mom and dad cannot determine the sex of that baby, it is nature and pure chance.
HELP PLEASE IM GIVING 50 BRAINLY POINTS!!!
According to Cavalieri’s Principle, which two solids would have congruent volumes?
A .a cone and a cylinder with equal base areas and heights
B. a cone and pyramid with equal base areas and heights
C. a cone and a rectangular prism with equal base areas and heights
D. a cylinder and a sphere with equal radii
The correct options for the Cavalieri's Principle are A and B, where the cone is paired with either a cylinder or a pyramid, both having equal base areas and heights.
Given Cavalieri's Principle which states that if two solids have the same height and cross-sectional area at every level (parallel cross-sections), then they have equal volumes.
To determine two solids would have congruent volumes,
A. A cone and a cylinder with equal base areas and heights would satisfy Cavalieri's Principle because they would have equal cross-sectional areas at every level.
B. A cone and a pyramid with equal base areas and heights would also satisfy Cavalieri's Principle.
A cone and a rectangular prism with equal base areas and heights would NOT satisfy Cavalieri's Principle because their cross-sectional areas would be different at different levels.
Also, cylinder and a sphere with equal radii would NOT satisfy Cavalieri's Principle because their cross-sectional areas would be different at different levels.
So, the correct answer is either A (cone and cylinder) or B (cone and pyramid).
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles.
B = 49°, a = 16, b = 14
The answer is:
The first triangle is:
[tex]A=59.6\°\\C=71.4\°\\c=17.6units[/tex]
The second triangle is:
[tex]A=120.4\°\\C=10.6\°\\c=3.41units[/tex]
Why?To solve the triangles, we must remember the Law of Sines form.
Law of Sines can be expressed by the following relationship:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}[/tex]
Where,
a, b, and c are sides of the triangle
A, B, and C are angles of the triangle.
We are given,
[tex]B=49\°\\a=16\\b=14[/tex]
So, solving the triangles, we have:
- First Triangle:Finding A, we have:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}\\\\Sin(A)=a*\frac{Sin(B)}{b}=16*\frac{Sin(49\°)}{14}\\\\Sin^{-1}(Sin(A)=Sin^{-1}(16*\frac{Sin(49\°)}{14})\\\\A=59.6\°[/tex]
Finding C, we have:
Now, if the sum of all the interior angles of a triangle is equal to 180°, we have:
[tex]A+B+C=180\°\\\\C=180-A-B\\\\C=180\°-59.6\°-49\°=71.4\°[/tex]
Finding c, we have:
Then, now that we know C, we need to look for "c":
[tex]\frac{14}{Sin(49\°)}=\frac{c}{Sin(71.4\°)}\\\\c=\frac{14}{Sin(49\°)}*Sin(71.4\°)=17.58=17.6units[/tex]
So, the first triangle is:
[tex]A=59.6\°\\C=71.4\°\\c=17.6units[/tex]
- Second Triangle:Finding A, we have:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}\\\\Sin(A)=a*\frac{Sin(B)}{b}=16*\frac{Sin(49\°)}{14}\\\\Sin^{-1}(Sin(A)=Sin^{-1}(16*\frac{Sin(49\°)}{14})\\\\A=59.6\°[/tex]
Now, since that there are two triangles that can be formed, (angle and its suplementary angle) there are two possible values for A, and we have:
[tex]A=180\°-59.6\°=120.4\°[/tex]
Finding C, we have:
Then, if the sum of all the interior angles of a triangle is equal to 180°, we have:
[tex]A+B+C=180\°\\\\C=180\°-A-B\\\\C=180\°-120.4\°-49\°=10.6\°[/tex]
Then, now that we know C, we need to look for "c".
Finding c, we have:
[tex]\frac{14}{Sin(49\°)}=\frac{c}{Sin(10.6)}\\\\c=\frac{14}{Sin(49)\°}*Sin(10.6\°)=3.41units[/tex]
so, The second triangle is:
[tex]A=120.4\°\\C=10.6\°\\c=3.41units[/tex]
Have a nice day!
At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the numbers 1, 2, and 3.
What is the sample space of spinning the two wheels?
Answer:
12 possible outcomes.
Sample space:
[tex]\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}[/tex]
Step-by-step explanation:
The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.
1. There are four possible outcomes for the first wheel: F, A, I and R
2. There are three possible outcomes for the second wheel: 1, 2 and 3
So, the sample space is
[tex]\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}[/tex]
A trough is filled with water. The trough holds 315 gallons. Each cubic foot of water contains about 7.5 gallons. The trough is 7 feet long and 4 feet wide. What is the height of the trough?
Answer:
The height of the trough is about 1.5 ft
Step-by-step explanation:
If each cubic foot of water contains about 7.5 gallons.
Then; 315 gallons is about [tex]\frac{315}{7.5}=42ft^3[/tex]
Let h be the height of the trough, then
[tex]7\times 4\times h=42[/tex]
This implies that;
[tex]28h=42[/tex]
Divide both sides by 28 to get:
[tex]h=\frac{42}{28}[/tex]
[tex]\therefore h=1.5[/tex]
The height of the trough is about 1.5 ft
the height of the trough is 1.5 feet.
To solve for the height of the trough that holds 315 gallons, we need to use the information that 1 cubic foot of water contains about 7.5 gallons. Since the trough is 7 feet long and 4 feet wide, we can first calculate the volume in cubic feet by dividing the volume in gallons by the gallon-to-cubic-feet conversion factor (315 gallons \/ 7.5 gallons/cubic foot). Then, we use this volume to find the height by dividing the volume by the product of the length and the width of the trough.
Here is a step-by-step approach:
Convert the volume from gallons to cubic feet: Volume (cubic feet) = Volume (gallons) ÷ 7.5 gallons/cubic footCalculate the height of the trough: Height (feet) = Volume (cubic feet) ÷ (Length (feet) x Width (feet))Now, let's calculate:
Volume (cubic feet) = 315 gallons ÷ 7.5 gallons/cubic foot = 42 cubic feetHeight (feet) = 42 cubic feet ÷ (7 feet x 4 feet) = 42 cubic feet ÷ 28 square feet = 1.5 feetTherefore, the height of the trough is 1.5 feet.
HELP ASAP PLEASE!!!
If f(x)=5x-1, What is f^-1 (f(2))?
A. 44
B. -2
C. -44
D. 2
Answer:
(D) 2
Step-by-step explanation:
f(x) = 5x - 1
y = 5x - 1
5x = y + 1
x = (y + 1)/5
f⁻¹ (x) = (x + 1)/5
f(x) = 5x - 1
f(2) = 5(2) - 1
f(2) = 9
f⁻¹ (x) = (x + 1)/5
f⁻¹ (f(2)) = (9 + 1)/5
f⁻¹ (f(2)) = 2
Given the value of cos 50° ? 0.6428, enter the sine of a complementary angle. Use an expression relating trigonometric ratios of complementary angles.
ANSWER
[tex]\sin(40) \degree = 0.6428[/tex]
EXPLANATION
The sine and cosine ratios are complementary.
This means that:
[tex] \cos(x \degree) = \sin(90 - x) \degree[/tex]
We were given that,
cos(50°)=0.6428
We want to find the sine of the complement of this angle.
[tex] \cos(50\degree) = \sin(90 -5 0) \degree[/tex]
[tex]\cos(50\degree) = \sin(40) \degree[/tex]
This implies that,
[tex] \sin(40) \degree = 0.6428[/tex]
Can someone please help with this question it’s confusing me
The answer might be 2.66
Answer:
0.5
Step-by-step explanation:
12 is the total amount of bags
(2*1/6+ 2*1/3 + 3*1/2 + 4*2/3 + 1*5/6 ) / 12 =
[1/3 + 2/3 + 3/2 + 8/3 + 5/6]/12 = [(1+2+8)/3 + (3*3+5)/6 ]/12 =
(11/3+14/6)/5 = [(22+14)/6 ]/12 = (36/6) /5 = 6/12=0.5
The function, f(t)= 1.2 cos 0.5t, does not have an amplitude and has a period of 4π.
Answer:
False
Step-by-step explanation:
Given in the question a function,
f(t)=1.2cos0.5t
Standard form of cosine function is
f(t)=acos(bt)
Amplitude is given by = |a|
Period of function is given by = 2π/b
So the amplitude is |1.2| = 1.2
the period is 2π/0.5 = 4π
Answer:
False
Step-by-step explanation:
The given function is
[tex]f(t)=1.2\cos 0.5t[/tex]
This function is of the form:
[tex]f(t)=A\cos(Bt)[/tex]
where A=1.2 and B=0.5
The amplitude of this function is given by;
|A|=|1.2|=1.2
The period of this function is given by;
[tex]T=\frac{2\pi}{|B|}[/tex]
[tex]T=\frac{2\pi}{|0.5|}[/tex]
[tex]T=\frac{2\pi}{0.5}=4\pi[/tex]
The correct answer is False
Pls answer this question
x^2 -4x +2=0
There are two options of x. You have both of them in picture 1.
Answer:
Step-by-step explanation:
x² - 4x +2=0
(x² - 4x +4) - 4+2=0
(x - 2)²= 2
x - 2 = √2 or x- 2 = -√2
x=2+√2 or x=2-√2
note : same solution :Magdaloskotova Beginner
(4+2√2)/2 = 2(2+√2)/2 = 2+√2
(4-2√2)/2 = 2(2-√2)/2 = 2-√2
Andrew drove from his house to his sister's house in 8 hours at an average of 60 miles per hour. On the way home he drove at an average rate of 64 miles per hour. How long did it take him to drive home?
Answer:
288
Step -by-step explanation:I'm not explaining :D
Answer:
It took him 7.5 hrs to drive home.
Step-by-step explanation:
The distance is the same, going or returning.
Recall that distance = rate times time.
Here, distance from Andrew's to his sister's is (60 mph)(8 hr) = 480 mi
If distance = rate times time, then time = distance / rate.
Here we have time = 480 mi / 64 mph = 7.5 hrs
It took him 7.5 hrs to drive home.
By graphing both sides of the equation, determine whether the following is an identity:
1+sec^2x= tan^2 x
Graphing is overkill... Let [tex]x=0[/tex]. Then [tex]\sec0=1[/tex], while [tex]\tan0=0[/tex]. But [tex]1+1=2\neq0[/tex], so this is not an identity.
Answer:
It is not an identity
Step-by-step explanation:
If you graphic the two equations (left and right) separately, if they are an identity, they will be the same graphic, which is not true in this case.
Another way in order to know if an equation is an identity, you can replace some values at x, for example 2 values:
X=30
X=60
And now we substitute in the equation, like this:
[tex]1+sec^2(30)=tan^2(30)[/tex]
2,33=0,33 this is not equal on both sides
[tex]1+sec^2(60)=tan^2(60)[/tex]
5=3 this is not equal on both sides
And if the results for each number x are the same on both sides of the equation, it is an identity. In this case they are different.
Write the standard equation of the circle shown.
Answer:
b
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ← r is the radius
The circle shown is centred at the origin and has a radius of 5, thus
x² + y² = 5² ⇒ x² + y² = 25 → b
Rewrite the following parametric equations in rectangular form.
x=e^3t and y= e^-t
a. y=3/x, x>0
b.x= 1/y^3, y>0
c. x= -y^3,y<0
d. y= 1/x^3, x>0
Answer:
Answer choice B
Step-by-step explanation:
This is the graph of f(x)=4(1/2)^x. What is the horizontal asymptote of f(x)?
ANSWER
The correct choice is D.
EXPLANATION
See the attachment for explanation;
during the first years of growth the height of a tree can be modeled with the function h=-t^2 +12t+10 where t is the time in years since being planted and h is the height in inches. Enter the average rate cof change, in inches per year, from year 1 to year 5.
ANSWER
6 inches
EXPLANATION
The given function is
[tex]h(t) = - {t}^{2} + 12t + 10[/tex]
The average rate of change from t=1 to t=5 is given by:
[tex] = \frac{h(5) - h(1)}{5 - 1} [/tex]
[tex]h(5) = - {(5)}^{2} + 12(5) + 10[/tex]
[tex]h(5) = - 25 + 60+ 10[/tex]
[tex]h(5) = 45[/tex]
Also,
[tex]h(1) = - {(1)}^{2} + 12(1) + 10[/tex]
[tex]h(1) = - 1+ 12+ 10[/tex]
[tex]h(1) = 21[/tex]
The average rate of change is now
[tex] = \frac{45 - 21}{4} [/tex]
[tex] = \frac{24}{4} [/tex]
[tex] = 6[/tex]
Convert 17π/8 to degrees.
Answer:
382.5°
Step-by-step explanation:
Multiply
17π 180°
------ by the conversion factor ------------
8 π
obtaining:
(17)(180)°
------------- = 382.5°
8
A rectangle measures 3 inches by 4 inches. If the lengths of each side double,what will its area be
6x8= 48 inches
3 doubled=6
4 doubled=8
help plsssssssssssssssssssssssssssssss
Answer:
[tex]t\le 4[/tex]
Step-by-step explanation:
Let t hours be the number of hours needed to rent the room. If one hour costs $8.30, then t hours cost $8.30t. The reservation fee is $34, so the total cost is
[tex]\$(34+8.30t).[/tex]
The history club wants to spend $67.20, thus
[tex]34+8.30t\le67.20\\ \\8.30t\le 67.20-34\\ \\8.30t\le 33.20\\ \\t\le \dfrac{33.20}{8.30}=\dfrac{332}{83}=4[/tex]
The maximum possible whole number of hours is 4 hours.
What is this equal to?
ANSWER
[tex] \sum_{n=1} ^{32} (4n + 1) = 2144[/tex]
EXPLANATION
The given series is
[tex] \sum_{n=1} ^{32} (4n + 1) [/tex]
The first term in this series is
[tex]a_1=4(1) + 1 = 5[/tex]
The last term is
[tex]l = 4(32) + 1 = 129[/tex]
The sum of the first n terms is
[tex]S_n= \frac{n}{2} (a + l)[/tex]
The sum of the first 32 terms is
[tex]S_ {32} = \frac{32}{2} (5 + 129)[/tex]
[tex]S_ {32} =16 \times 134[/tex]
[tex]S_ {32} =2144[/tex]
Therefore,
[tex] \sum_{n=1} ^{32} (4n + 1) = 2144[/tex]
Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1 squared divided by 64 equals 1.
Vertices: (-1, 3), (-1, -13); Foci: (-1, -13), (-1, 3)
Vertices: (3, -1), (-13, -1); Foci: (-13, -1), (3, -1)
Vertices: (-1, 1), (-1, -11); Foci: (-1, -15), (-1, 5)
Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
Answer:
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
Step-by-step explanation:
Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.
a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
Answer:
Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
Step-by-step explanation:
Ok so we have 5x[tex]\frac{5x^{2} }{36}-\frac{y^{2} }{64}=1[/tex]
As you know we have the equation of the hyperbola as (x-h)^2/a^2-(y-k)^2/b^2, so the formula of the foci is [tex](h+-c,k) and for vertices (h+-a,k)[/tex]
then we have to calculate c using pythagoras theorem we have that
a=6 because is the root of 36
b=8 beacause is the root of 64
And then we have that [tex]c^{2}=a^{2}+b^{2}[/tex]
[tex]c=\sqrt{36+64}[/tex]
So the root of 100 is equal to 10
Hence c=10
Using the formula given before and the equation we know that
h=-5
k=-1
And replacing those values on the equation we have that the foci are
(-5-10, -1)=(-15,-1)(-5+10,1)=(5,-1)And the vertices are:
(-5-6, -1)=(-11,-1)(-5+6, 1)= (1,-1)So the correct answer is D
simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
Answer:
The simplest form is x/(x + 3)
Step-by-step explanation:
* To simplify the rational Expression lets revise the factorization
of the quadratic expression
* To factor a quadratic in the form x² ± bx ± c:
- First look at the c term
# If the c term is a positive number, and its factors are r and s they
will have the same sign and their sum is b.
# If the c term is a negative number, then either r or s will be negative
but not both and their difference is b.
- Second look at the b term.
# If the c term is positive and the b term is positive, then both r and
s are positive.
Ex: x² + 5x + 6 = (x + 3)(x + 2)
# If the c term is positive and the b term is negative, then both r and s
are negative.
Ex: x² - 5x + 6 = (x -3)(x - 2)
# If the c term is negative and the b term is positive, then the factor
that is positive will have the greater absolute value. That is, if
|r| > |s|, then r is positive and s is negative.
Ex: x² + 5x - 6 = (x + 6)(x - 1)
# If the c term is negative and the b term is negative, then the factor
that is negative will have the greater absolute value. That is, if
|r| > |s|, then r is negative and s is positive.
Ex: x² - 5x - 6 = (x - 6)(x + 1)
* Now lets solve the problem
- We have two fractions over each other
- Lets simplify the numerator
∵ The numerator is [tex]\frac{x+2}{x^{2}+2x-3}[/tex]
- Factorize its denominator
∵ The denominator = x² + 2x - 3
- The last term is negative then the two brackets have different signs
∵ 3 = 3 × 1
∵ 3 - 1 = 2
∵ The middle term is +ve
∴ -3 = 3 × -1 ⇒ the greatest is +ve
∴ x² + 2x - 3 = (x + 3)(x - 1)
∴ The numerator = [tex]\frac{(x+2)}{(x+3)(x-2)}[/tex]
- Lets simplify the denominator
∵ The denominator is [tex]\frac{x+2}{x^{2}-x}[/tex]
- Factorize its denominator
∵ The denominator = x² - 2x
- Take x as a common factor and divide each term by x
∵ x² ÷ x = x
∵ -x ÷ x = -1
∴ x² - 2x = x(x - 1)
∴ The denominator = [tex]\frac{(x+2)}{x(x-1)}[/tex]
* Now lets write the fraction as a division
∴ The fraction = [tex]\frac{x+2}{(x+3)(x-1)}[/tex] ÷ [tex]\frac{x+2}{x(x-1)}[/tex]
- Change the sign of division and reverse the fraction after it
∴ The fraction = [tex]\frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}[/tex]
* Now we can cancel the bracket (x + 2) up with same bracket down
and cancel bracket (x - 1) up with same bracket down
∴ The simplest form = [tex]\frac{x}{x+3}[/tex]
ANSWER
[tex]\frac{x}{x + 3}[/tex]
EXPLANATION
We want to simplify:
[tex] \frac{x +2 }{ {x}^{2} + 2x - 3} \div \frac{x + 2}{ {x}^{2}- x} [/tex]
Multiply by the reciprocal of the second fraction:
[tex] \frac{x +2 }{ {x}^{2} + 2x - 3} \times \frac{{x}^{2}- x}{ x + 2} [/tex]
Factor;
[tex] \frac{x +2 }{ (x + 3)(x - 1)} \times \frac{x(x - 1)}{ x + 2} [/tex]
We cancel out the common factors to get:
[tex] \frac{x}{x + 3} [/tex]
The graph shows the number of paintballs a machine launches, y, in x seconds:
A graph titled Rate of Launch is shown. The x axis label is Time in seconds, and the x axis values are from 0 to 10 in increments of 2 for each grid line. The y axis label is Number of Balls, and the y axis values from 0 to 60 in increments of 12 for each grid line. A line is shown connecting points on ordered pair 2, 12 and 4, 24 and 6, 36 and 8, 48.
Which expression can be used to calculate the rate per second at which the machine launches the balls?
A.) 2/12
B.) 12/2
C.) 2/48
D.) 48/2
Answer:
Option B.) 12/2
Step-by-step explanation:
we know that
The rate of a linear equation is equal to the slope m
The slope is equal to
points (2,12) and (4,24)
m=(24-12)/(4-2)
m=12/2
m=6 balls/sec
Please help me out....
Answer:
x = 6
Step-by-step explanation:
Given that the line segment is an angle bisector then the following ratios are equal
[tex]\frac{42}{78}[/tex] = [tex]\frac{6x-1}{10x+5}[/tex], that is
[tex]\frac{7}{13}[/tex] = [tex]\frac{6x-1}{10x+5}[/tex] ( cross- multiply )
13(6x - 1) = 7(10x +5) ← distribute parenthesis on both sides
78x - 13 = 70x + 35 ( subtract 70x from both sides )
8x - 13 = 35 ( add 13 to both sides )
8x = 48 ( divide both sides by 8 )
x = 6
1) Find f(x) if it is known that f(5a)=5a−2.
2) Find g(x) if it is known that g(2t)=8t−1.
Answer:
Step-by-step explanation:
One
f(5a) means that wherever you see an x, you put in 5a
x = 5a
f(x) = x/5t * 5t - 2
f(x) = x - 2
===============
Two
g(2t) = 8t - 1
x = 2t
g(x) = 8t/2t*x - 1
g(x) = 4x - 1
1)for the first one you can put a=(1/5)a in the function and it will be:
[tex]f(a) = a - 2[/tex]
so in a function , alphabet is not important and you can rewrite it to this:
[tex]f(x) = x - 2[/tex]
2)the same as the first , we can put t=(1/2)t and conclusion is :
[tex]g(t) = 4t - 1[/tex]
and then change the t to x:
[tex]g(x) = 4x - 1[/tex]
Suppose a sample mean is distributed normally. if the sample size increases, what happens to the shape of the sampling distribution of the sample mean?
a. distribution becomes wider and flatter.
b. distribution becomes narrower and taller.
c. distribution remains the same.
d. distribution turns upside down and inside ou
Answer:
(b)
Step-by-step explanation:
(b) is correct: the distribution becomes narrower and taller.
Use the partial information given in this electronic W-2 form to calculate the amount in Box 3.
The Box 3 on an electronic W-2 form represents the total wages subject to Social Security tax. To calculate it, look for the 'Social Security wages' value on the form and determine if it exceeds the annual limit set by the Social Security tax.
Explanation:The Box 3 on an electronic W-2 form represents the total wages that are subject to the Social Security tax. To calculate the amount in Box 3, you can look for the value labeled 'Social Security wages' or 'SS wages' on the form. This value includes all taxable wages and tips that are subject to Social Security taxes, up to a certain limit.
For the year 2020, the Social Security tax is only applied to the first $137,700 of wages. If the 'Social Security wages' value provided on the form is higher than this limit, you should use the limit as the amount in Box 3. If the value is lower than the limit, then the 'Social Security wages' value itself should be used as the amount in Box 3.
Learn more about box 3 on electronic W-2 form here:https://brainly.com/question/31891188
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Please help me with this!!
Thank u
Answer:
Step-by-step explanation:
Left
When a square = a linear, always expand the squared expression.
x^2 - 2x + 1 = 3x - 5 Subtract 3x from both sides
x^2 - 2x - 3x + 1 = -5
x^2 - 5x +1 = - 5 Add 5 to both sides
x^2 - 5x + 1 + 5 = -5 + 5
x^2 - 5x + 6 = 0
This factors
(x - 2)(x - 3)
So one solution is x = 2 and the other is x = 3
Second from the Left
i = sqrt(-1)
i^2 = - 1
i^4 = (i^2)(i^2)
i^4 = - 1 * -1
i^4 = 1
16(i^4) - 8(i^2) + 4
16(1) - 8(-1) + 4
16 + 8 + 4
28
Second from the Right
This one is rather long. I'll get you the equations, you can solve for a and b. Maybe not as long as I think.
12 = 8a + b
17 = 12a + b Subtract
-5 = - 4a
a = - 5/-4 = 1.25
12 = 8*1.25 + b
12 = 10 + b
b = 12 - 10
b = 2
Now they want a + b
a + b = 1.25 + 2 = 3.25
Right
One of the ways to do this is to take out the common factor. You could also expand the square and remove the brackets of (2x - 2). Both will give you the same answer. I think expansion might be easier for you to understand, but the common factor method is shorter.
(2x - 2)^2 = 4x^2 - 8x + 4
4x^2 - 8x + 4 - 2x + 2
4x^2 - 10x + 6 The problem is factoring since neither of the first two equations work.
(2x - 2)(2x - 3) This is correct.
So the answer is D