Answer :
(a) Orange juice → Heterogeneous mixture
(b) Tap water → Homogeneous mixture
Explanation:
Homogeneous mixture:
It is a type of mixture in which the components of the mixture are distributed uniformly throughout the mixture.
It can not be separated by physically. It has only one phase.
Heterogeneous mixture:
It is a type of mixture in which all the components are completely mixed and the particles present in the mixture can be separated by physically.
They have two or more phase.
From the given options, tap water is a homogeneous mixture because it has only one phase.
While the other options, orange juice are heterogeneous mixture because it can be separated by physically and they have two or more phase.
Tap water is a homogeneous mixture because its composition is uniformly distributed and it appears as one substance. Orange juice, especially if it contains pulp, is a heterogeneous mixture since its components (pulp and liquid) are distinct and not uniformly mixed.
Explanation:The substances in question, orange juice and tap water, can be classified as either homogeneous or heterogeneous mixtures. In a homogeneous mixture, the components are evenly mixed throughout and you can't see the different parts. Tap water is an example of this because it usually contains many different substances dissolved inside it like minerals, and gasses, but it still retains the same properties throughout, meaning it looks like one substance.
On the other hand, a heterogeneous mixture contains components that aren't evenly mixed and you can see the different parts. Orange juice, especially if it's freshly squeezed and contains pulp, is an example of a heterogeneous mixture. The pulp and liquid are very different in terms of texture and appearance and they don't blend into a single, indistinguishable mixture.
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What is the osmotic pressure of a solution formed by dissolving 44.3 mg of aspirin (C9H8O4) in 0.358 L of water at 25 ∘C?
The osmotic pressure of a solution formed by dissolving 44.3 mg of aspirin in 0.358 L of water at 25 ∘C is 0.01633 atm. This is calculated using the formula for osmotic pressure 'Pi = n/V RT', inserting the required values including the mole of aspirin, the volume, the gas constant, and temperature.
Explanation:To calculate the osmotic pressure, we need to use the formula Pi = n/V RT, where 'n' is the number of moles of the solute, 'V' is the volume in liters, 'R' is the gas constant (0.08206 L atm/mol K), and 'T' is the temperature in Kelvin. Firstly, we need to find the molar mass of aspirin (C9H8O4) which is approximately 180.16 g/mol. Consequently, we can determine the mole of aspirin used as 44.3 mg / 180.16 g/mol = 0.000246 moles. Now knowing all values, plug them into the formula: Pi = 0.000246 moles /0.358L * 0.08206 atm mol^-1K^-1 * 298.15K which equals 0.01633 atm, the osmotic pressure of the solution.
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For the osmotic pressure of an aspirin solution, first convert the mass of aspirin to moles, find the molarity, convert the temperature to Kelvin, and then apply the osmotic pressure formula. The osmotic pressure is found to be approximately 0.0168 atm.
The question asks to determine the osmotic pressure of a solution containing aspirin at a certain temperature. The osmotic pressure can be calculated using the formula:
\(\Pi = MRT\)
Where:
\(\Pi\) is the osmotic pressure,
\(M\) is the molarity of the solution (moles of solute per liter of solution),
\(R\) is the gas constant (0.0821 L atm K^{-1} mol^{-1}), and
\(T\) is the temperature in Kelvin.
First, convert the mass of aspirin to moles using the molecular weight of aspirin (C9H8O4), which is 180.16 g/mol:
\(44.3 mg = 0.0443 g\)
\(0.0443 g \times \dfrac{1 mol}{180.16 g} \approx 2.46 \times 10^{-4} mol\)
Next, find the molarity \(M\) by dividing the number of moles by the volume in liters:
\(M = \dfrac{2.46 \times 10^{-4} mol}{0.358 L} \approx 6.87 \times 10^{-4} M\)
Now convert the temperature to Kelvin:
\(T = 25 \degree C + 273.15 = 298.15 K\)
Finally, calculate the osmotic pressure:
\(\Pi = (6.87 \times 10^{-4} M)(0.0821 L atm K^{-1} mol^{-1})(298.15 K)\)
\(\Pi \approx 0.0168 atm\)
Therefore, the osmotic pressure of the aspirin solution is approximately 0.0168 atm.
Which type of intermolecular attractive force operates between (part A) all molecules, (part B) polar molecules, (part C) the hydrogen atom of a polar bond and a nearby small electronegative atom
Answer:
PART A: The LDF occurs between all molecules. Dispersion forces result from shifting electron clouds, which cause weak, temporary dipole.
PART B: Dipole dipole operates only between polar molecules. This is when two polar molecules get near each other and the positively charged portion of the molecule is attracted to the negatively charged portion of another molecule.
PART C: Dipole dipole and in some cases hydrogen bonding operate between the hydrogen atom of a polar bond and a nearby small electronegative atom. Only if the atom bonded to it were F, O or N it would be hydrogen bonding. Otherwise it is dipole dipole.
All molecules - Dispersion force.
Polar molecules - Dipole–Dipole interaction.
The hydrogen atom of a polar bond and a nearby small electronegative atom - Dipole–Dipole and Hydrogen Bonding.
What are intermolecular attractive force?Intermolecular force is a force that connect molecules to each other.
There are four types of forces present
DispersionDipole–DipoleHydrogen Bonding Ion-DipoleThus, the bonds present are: All molecules - Dispersion force.
Polar molecules - Dipole–Dipole interaction.
The hydrogen atom of a polar bond and a nearby small electronegative atom - Dipole–Dipole and Hydrogen Bonding.
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A 50 W engine generates 50 J of energy. How long did it run for?
A. 10 s
B. 1 s
C. 5 s
D. 100 s
Answer: A Explanation:
the temperature of a sample of copper increased by 23.0 C when 265 J of heat was applied. What is the mass of the sample?
To find the mass of the copper sample, we use the formula for heat transfer Q = mcΔT. By substituting the given values of specific heat capacity of copper, the amount of heat applied and the change in temperature into the formula and solving for mass, we find the mass of the copper sample to be 29.54g.
Explanation:The subject of this question is physics, specifically dealing with the concept of heat transfer. To determine the mass of the copper sample, we'll use the formula for heat transfer: Q = mcΔT, where 'Q' is the amount of heat transferred, 'm' is the mass of the substance, 'c' is the specific heat capacity, and 'ΔT' is the change in temperature.
In this case, we know that the specific heat capacity of copper is 0.39 J/g °C, the amount of heat applied (Q) is 265 J and the change in temperature ΔT is 23.0 °C. By substituting these values into the formula, we can solve for 'm' (mass). Rearranging the formula gives us m = Q / (cΔT). Substituting the given values, we find m = 265 J / (0.39 J/g°C * 23.0°C) gives us the mass of the copper sample to be 29.54 g.
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A catalyst can increase the rate of a reaction ________. Select one: a. by increasing the overall activation energy (Ea) of the reaction b. by providing an alternative pathway with a lower activation energy c. by lowering the activation energy of the reverse reaction d. by changing the value of the frequency factor (A) e. All of these are ways that a catalyst might act to increase the rate of reaction.
Catalysts increase the reaction rate by providing an alternative pathway with lower activation energy. They don't alter other energy factors.
Explanation:In a chemical reaction, a catalyst increases the rate of the reaction by providing an alternative pathway with a lower activation energy. This option 'b' is correct. The activation energy is the minimum amount of energy required for a reaction to occur. By reducing this energy, catalysts speed up the reaction process without being consumed in the reaction itself. They don't alter the overall energy (option 'a'), they don't lower the energy of the reverse reaction (option 'c'), and they do not change the value of the frequency factor ('option 'd'). Hence, answer 'e' is also not correct.
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Calculate the concentrations of all species in a 1.15 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants for sulfurous acid are K a 1 = 1.4 × 10 − 2 and K a 2 = 6.3 × 10 − 8 .
Final answer:
The concentration of Na+ in a 1.15 M Na2SO3 solution is 2.30 M, and the concentration of SO32- is 1.15 M, as Na2SO3 dissociates entirely into these ions in solution.
Explanation:
To calculate the concentration of all species in a 1.15 M Na2SO3 (sodium sulfite) solution, we need to consider the ionization of sulfurous acid (H2SO3), which isn't explicitly present but relates to the anion derived from Na2SO3. The ionization constants given are Ka1 = 1.4 × 10−2 for the first dissociation (H2SO3 to HSO3−) and Ka2 = 6.3 × 10−8 for the second dissociation (HSO3− to SO32−). Although, given the context, we aren't going through the complete step-by-step equilibrium calculation for Ka1 and Ka2, we understand that Na2SO3 dissociates completely in solution to Na+ and SO32−. Therefore, initially, the concentration of Na+ is 2.30 M (since each Na2SO3 unit yields two Na+ ions), and the concentration of SO32− is 1.15 M.
The concentrations in the 1.15 M Na2SO3 solution are approximately:
- [tex][H2SO3] = [HSO3^-] = 1.15 M,[/tex]
- [tex][SO3^2-] = 2.10 \times 10^-5 M,[/tex]
- [tex][Na^+] =1.15 M, and[/tex]
- [tex][OH^-] = 8.70 \times 10^-14 M.[/tex]
Given:
- Initial concentration of [tex]\(Na_2SO_3\) = 1.15 M[/tex]
- [tex]\(K_a1\)[/tex] for sulfurous acid [tex]= \(1.4 \times 10^{-2}\)[/tex]
- [tex]\(K_a2\)[/tex]for sulfurous acid [tex]= \(6.3 \times 10^{-8}\)[/tex]
We can assume that the ionization of [tex]\(Na_2SO_3\)[/tex] into [tex]\(HSO_3^-\)[/tex] and [tex]\(Na^+\)[/tex] is small due to the weak acid nature of sulfurous acid. So, the initial concentration of [tex]\(H_2SO_3\)[/tex] is approximately equal to 1.15 M.
Now, we approximate the concentration of [tex]\(H^+\)[/tex] ions to be approximately equal to the concentration of [tex]\(H_2SO_3\)[/tex], which is 1.15 M.
Using [tex]\(K_a2\)[/tex], we calculate the concentration of [tex]\(SO_3^{2-}\)[/tex] ions:
[tex]\[ [SO_3^{2-}] = \frac{[H^+]^2}{K_a2} \approx \frac{(1.15)^2}{6.3 \times 10^{-8}} \approx 2.10 \times 10^{-5} \, \text{M} \][/tex]
Since [tex]\(HSO_3^-\)[/tex] ions concentration is approximately equal to [tex]\(H^+\)[/tex] ions concentration and [tex]\(Na^+\)[/tex] concentration is the same as [tex]\(Na_2SO_3\)[/tex], we have:
- [tex]\([H_2SO_3] = [HSO_3^-] \approx 1.15 \, \text{M}\)[/tex]
- [tex]\([SO_3^{2-}] \approx 2.10 \times 10^{-5} \, \text{M}\)[/tex]
- [tex]\([Na^+] \approx 1.15 \, \text{M}\)[/tex]
The concentration of [tex]\(OH^-\)[/tex] ions can be calculated using the [tex]\(K_w\)[/tex]expression:
[tex]\[ [OH^-] = \frac{K_w}{[H^+]} \approx \frac{1.0 \times 10^{-14}}{1.15} \approx 8.70 \times 10^{-14} \, \text{M} \][/tex]
What is the percentage composition of soap (C12H35COON)?
Answer:
Carbon percentage 65.8% Hydrogen percentage 14.9% Oxygen percentage 13.4% Nitrogen percentage 5.9%
Explanation:
The molar mass of C12H35COON is 237.41g/mol
Carbon percentage composition= (12.01*13)/237.41 *100= 65.8%
Hydrogen percentage composition= (1.008*35)/237.41 *100= 14.9%
Oxygen percentage composition= (15.99*2)/237.41 *100= 13.4%
Nitrogen percentage composition= (14.007)/237.41 *100= 5.9%
The percent composition of soap is as follows carbon-65.82 %, hydrogen-14.76%,oxygen-13.50%,nitrogen- 5.90%.
What is percent composition?The Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates mass of each type of an element present in a compound. It is useful in analysis of compounds providing elemental composition.It is useful in even analysis of ores giving metal content information.
The molar mass of soap C₁₂H₃₅COON=237 g/mole, thus for carbon=12×13/237×100=65.82%, for hydrogen=1×35/237×100=14.76%., for oxygen= 16×2/237×100=13.50%, for nitrogen=14/237×100=5.90%.
Thus, the percent composition of soap is as follows carbon-65.82 %, hydrogen-14.76%,oxygen-13.50%,nitrogen- 5.90%.
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What mass of strontium nitrate (Sr(NO3)2) would be required to prepare 2.000 L of a 0.0150 M aqueous solution of this salt?
Final answer:
To prepare a 0.0150 M solution of strontium nitrate in 2.000 L, you would need to use 4.49 grams of strontium nitrate.
Explanation:
To calculate the mass of strontium nitrate required to prepare the solution, we can use the formula:
moles = concentration x volume
First, convert the concentration to moles per liter:
moles/liter = concentration = 0.015 M
Next, multiply the moles per liter by the volume in liters to find the moles of strontium nitrate:
moles = (0.015 M) x (2.000 L) = 0.030 mol
Finally, calculate the mass of strontium nitrate using the molar mass:
mass = moles x molar mass = 0.030 mol x 149.6 g/mol = 4.49 g
Which of the following sites has volcanoes related to subduction? A is on an island arc, B is in the Andes, C is near Hawaii, D is along a mid-ocean ridge.
Answer:
A is on an island arc,
B is in the Andes
Explanation:
The subduction region is referred to as the subduction zone. When a plate slips underneath another, it forms a trench. Earthquakes resulting from the plate panelling often result in magma spilling across the underwater volcano trench. Island arcs are vast chains of active volcanoes with strong seismicity located along the converging tectonic plate borders. Much of the islands arcs emerge from the oceanic crust and also have originated from fall of the lithosphere into the mantle across the subduction zone. In the Andes mountain range, Under the South American plate the Nazca plate is subducting.
The sites has volcanoes related to subduction is on an island arc and is in the Andes.
A subduction zoneA subduction zone forms when continental crust and oceanic crust collide.
Subduction zones are located in the Pacific Ocean.
The subduction zone is at the western margin of South America (Andes).
Island arcs have active volcanoes found along convergent tectonic plate boundaries.
Thus option A and B are correct answer.
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The atomic mass of sulfur is 32.1 amu, and the atomic mass of oxygen is 16.0 amu. To the nearest tenth of a percent, what is the percent by mass of sulfur in sulfur trioxide (SO3)?
Answer:
[tex]\%\ Composition\ of\ sulfur=40.1\ \%[/tex]
Explanation:
Percent composition is percentage by the mass of element present in the compound.
Given , Mass of sulfur= 32.1 amu
Mass of oxygen = 16.0 amu
Mass of sulfur trioxide [tex]SO_3[/tex] = 32.1 amu + 3*16.0 amu = 80.1 amu
[tex]\%\ Composition\ of\ sulfur=\frac{Mass_{sulfur}}{Mass_{SO_3}}\times 100[/tex]
[tex]\%\ Composition\ of\ sulfur=\frac{32.1\ amu}{80.1\ amu}\times 100=40.1\ \%[/tex]
Final answer:
To determine the percent by mass of sulfur in sulfur trioxide (SO3), calculate the molar mass of the compound and divide the atomic mass of sulfur by the total molar mass. The percent by mass of sulfur in SO3 is found to be 40.0%.
Explanation:
To find the percent by mass of sulfur in sulfur trioxide (SO3), we first calculate the molar mass of the compound. We have one sulfur atom and three oxygen atoms in SO3.
Molar mass of S = 32.07 amuMolar mass of O = 16.00 amu (for one oxygen atom)Next, we calculate the molar mass of SO3:
Molar mass of SO3 = Molar mass of S + 3 × Molar mass of O
= 32.07 amu + 3 × 16.00 amu
= 32.07 amu + 48.00 amu
= 80.07 amu
To find the percent composition of sulfur, we divide the molar mass of sulfur by the total molar mass of the compound and multiply by 100:
Percent by mass of S in SO3 = (Molar mass of S / Molar mass of SO3) × 100%
= (32.07 amu / 80.07 amu) × 100%
= 40.0% (to the nearest tenth of a percent)
At Mountain X, you could boil water in less than 3 minutes. At Mountain Y, it takes you almost 7 minutes to boil the same amount of water. What can be said about the elevations of both mountains?
A. The elevation of both mountains is the same.
B. Mountain X has a higher elevation than Mountain Y.
C. Mountain X has a lower elevation than Mountain Y.
D. Cannot determine from the information given
Answer:
The answer to your question is letter B.
Explanation:
Water boils at sea level at 100°C at higher heights the boiling point diminishes. That means that at higher heights the time needed to boil water will be lower than at sea level.
In this problem at mountain B is only 3 minutes needed to boil water that means that the height is higher here.
Answer:
The correct answer is B. Mountain X has a higher elevation than Mountain Y
Explanation:
The boiling point of a liquid reduces as the altitude where the boling takes place increases. With every 500 ft increase in altitude the boiling point of water devreses by 0.5 °C as such the boiling point of water at 8000 ft is just 92 °C. To compenasate cooking at altidude require the use of a pressure cooker as it is hard to boil items such as potatoes at very high altitudes of thousands of feet
How does William Jennings Bryan respond to the criticism that the free and unlimited coinage of silver will disrupt ""business interests""?
Answer:
He responded by saying their business definition was far too narrow.
Explanation:
Williams Bryan relates the battle for free silver with the revolution in the United States.
His iconic "Cross of Gold" address ignited the Democratic National Convention in 1896 where he begged the american people not to be "crucified on the cross of gold." He was said this because of the Republicans plan to introduce a firm gold standard and abolish silver coinage.
What was the significance to India of the Persian conquest of the Indus Valley and Kashmir under Emperor Darius in the sixth century B.C.E.?
Answer:
India had a greater contact and net work with other areas or territory.
Explanation:
This lead to the introduction of new ideas and they also learnt new techniques.
When 2−bromo−3,3−dimethylbutane is treated with K⁺ −OC(CH₃)₃, a single product T having molecular formula C₆H₁₂. When 3,3−dimethyl−2−butanol is treated with H₂SO₄, the major product U has the same molecular formula. Given the following ¹H NMR data, what are the structures of T and U?
Answer:
T = 3,3-dimethylbut-1-ene
U = 2,3-dimethylbut-2-ene
Explanation:
The chemical reactions for the two reactions and the mechanisms of reaction are shown in the two attachments to this answer.
Hope it helps!
A 8.6 g rock sample is added to a graduated cylinder filled with water, causing the level to increase from 12.8 mL to 13.6 mL. What is the density of the rock sample?
The density of the rock sample is 10.75 g/cm³.
Explanation:The density of an object can be calculated using the formula:
Density = mass/volume
In this case, we have the mass of the rock sample (8.6 g) and the change in volume of the water in the graduated cylinder (13.6 mL - 12.8 mL = 0.8 mL). To calculate the density, we need to convert the volume from mL to cm³, since the mass is in grams.
1 mL = 1 cm³, so the volume of the rock sample in cm³ is 0.8 cm³.
Now, we can calculate the density:
Density = mass/volume
Density = 8.6 g / 0.8 cm³
Density = 10.75 g/cm³
Therefore, the density of the rock sample is 10.75 g/cm³.
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The density of the rock sample is found to be 10.75 g/mL by dividing its mass, 8.6 g, by the volume of water it displaced, which is 0.8 mL.
To determine the density of the rock sample, we use the formula density = mass/volume. The mass of the rock is given as 8.6 g. The volume displaced by the rock is the change in the water level in the graduated cylinder: 13.6 mL - 12.8 mL = 0.8 mL.
Now, we can calculate the rock's density:
Density = Mass / Volume
Density = 8.6 g / 0.8 mL
Density = 10.75 g/mL
Therefore, the density of the rock sample is 10.75 g/mL.
How many unhybridized p atomic orbitals are present when a central atom exhibits trigonal planar geometry?
Answer:
1
Explanation:
Trigonal planar geometry is shown by the compounds where hybridization of central atom is [tex]sp^2[/tex].
In [tex]sp^2[/tex] hybridization, three hybrid orbitals are equally spaced at an angle of 120°.
Some of the compounds having [tex]sp^2[/tex] hybridization are [tex]CO_3^{2-}[/tex], [tex]SO_3[/tex], etc
In [tex]sp^2[/tex] hybridizationm, one s-orbital and 2 p-orbitals are involved.
Total no. of orbitals present in p-subshell is 3.
As 2 is involved in [tex]sp^2[/tex] hybridization, therefore no. of unhybridized orbital in [tex]sp^2[/tex] hybridization is 1.
Which states of matter can flow?
1) gas and liquid
2) gas
3) gas, liquid, and solids
4) liquid
Answer:
1) Gas and Liquid
Explanation:
hope it helps
The physicals properties of a substance can be used to identify the substance, because_____. Select all that apply.
1. at any given location, the physical properties of a substance do not change
2. when the substances are chemically reacted the physical properties remain the same
3. each substance has a unique set of physical properties
4. no two substances have any of the same properties
Answer:
1. at any given location, the physical properties of a substance do not change.
2. Each substance has a unique set of physical properties
Explanation:
The physical property of a substance is a feature of a substance that can be noticed or measured without changing the key identity of the substance. Physical properties include density, hardness, melting point, colour etc...
Answer:
1. at any given location, the physical properties of a substance do not change
3. each substance has a unique set of physical properties
Explanation:
1. The physical properties of a substance do not change provided that the physical conditions in the niche environment remain same.
3. Every substance on Earth has a unique set and arrangement of atoms and molecules that give them their own unique properties.
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.
Answer:
The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ
Explanation:
From Arrhenius equation showing the temperature dependence of reaction rates.
[tex]K = Ae^{\frac{Ea}{RT} }[/tex] where
k = rate constant
A = Frequency or pre-exponential factor
Ea = energy of activation
R = The universal gas constant
T = Kelvin absolute temperature
we have
[tex]f = e^{\frac{Ea}{RT} }[/tex]
Where
f = fraction of collision with energy higher than the activation energy
Ea = activation energy = 10.0kJ = 10000J
R = universal gas constant = 8.31 J/mol.K
T = Absolute temperature in Kelvin = 400K
In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature
Plugging in the values into the equation relating f to activation energy we get
[tex]f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} }[/tex] or f = [tex]e^{3.01}[/tex] = 20.22 moles of argon have an energy of 10.0 kJ or greater
The question asks for the fraction of argon atoms at 400 K with an energy of 10.0 kJ or higher, which would require integrating the Maxwell-Boltzmann distribution, but key information is missing for a definitive answer.
Explanation:To calculate the fraction of argon atoms in a gas sample at 400 K with an energy of 10.0 kJ or greater, the principles of statistical mechanics and the Maxwell-Boltzmann distribution are applied. The Maxwell-Boltzmann distribution gives the fraction of particles at a certain energy level within a system at thermal equilibrium. However, we are missing some key information like the Maxwell-Boltzmann distribution function for the particular conditions set by the question, which is essential for performing such a calculation.
Typically, the calculation would require integrating the partition function over all energy states equal to or greater than 10.0 kJ. Without the exact form of the energy distribution, it is not possible to provide an accurate answer. The question pertains to a high level of physical chemistry or statistical mechanics typically studied at the college or university level.
Make a drawing of the particles in an NaCl solution to show why this solution conducts electricity. Make a drawing of the particles in an NaCl crystal to show why pure salt does not conduct.
Answer:
See the image attached. It is taken from an online chemistry textbook.See the explanation below.Explanation:
Sodium chloride consits of sodium cations (positive ions), Na⁺, and chloride anions (negative ions), CL⁻.
Pure sodium chloride is packed in crystals: sodium ions and chloride ions are packed together and the ions are in fixed positions. There are not free electrons that can move. Thus, sodium chloride doesn't conduct electricity, because there are no electrons or ions which are free to move.
In aqueous solution, sodium chloride units dissociates into their ions:
[tex]NaCl\rightarrow Na^++Cl^-[/tex]
Those ions are freely to move in the solution, and such they are charge carriers, which conduct the electricity.
As explained above, in solid sodium chloride, the ions cannot move and there is not flow of current.
That is why solid pure salt of NaCl does not conduct electricity and the solutions of NaCl do conduct electricity.
The image attached show both diagrams. In the diagram A, the ions are packed together, showing that they cannot move. In the diagram B, the ions are dissolved in water, showing that they can move and carry the charge, allowing the flow of current.
. The order of a chemical reaction with respect to one of its reactants is 0. If you double the concentration of that reactant, the reaction rate will _______. A. be cut in half B. double C. increase by an undetermined amount D. remain unchanged E. None of the Abov
Answer:
D. remain unchanged
Explanation:
A Zero-order reaction is defined as a chemical reaction wherein the rate doesn't vary with the increase or decrease in the concentration of the reactants.
Thus, If you double the concentration of that reactant, the reaction rate will:
D. remain unchanged
I hope it helps!
N2(g) + 3 H2(g) ⇌ 2 NH3(g) + Energy
For the reaction of nitrogen gas and hydrogen gas to make methane, what stresses would shift the equilibrium to the left toward the reactants?
Answer:
The answer to your question is below
Explanation:
Reaction
N₂ + 3H₂ ⇔ 2 NH₃ + energy
a) The concentration of NH₃, if the concentration of NH₃ increases, the reaction will move to the left.
b) Diminishing the temperature, no more energy will be released and the reaction will move to the reactants.
Nitrogen gas and hydrogen gas are combined in a reaction to produce ammonia. If 3.0 moles of N2 and 12.0 moles of H2 are present in the mixture, which is the limiting reactant?
Answer:
The limiting reactant is the N₂
Explanation:
The reaction for production of ammonia is:
N₂ + 3H₂ → 2NH₃
Ratio is 1:3. Let's make a rule of three to solve this:
1 mol of nitrogen is needed to react with 3 moles of hydrogen.
3 moles of nitrogen may react with (3 . 3) /1 = 9 moles of H₂
It is ok because I have 12 moles, so the limiting reactant is the N₂ but let's confirm it.
3 moles of H₂ react with 1 mol of N₂
12 moles of H₂ would react with (12. 1) / 3 = 4 moles of N₂
It's ok to say the N₂ is the limiting because I don't have enough moles to react. I need 4 and I only have 3
Final answer:
To determine the limiting reactant in the reaction to produce ammonia, we compare the stoichiometric amounts needed according to the balanced equation. Nitrogen is the limiting reactant in this reaction because it requires more hydrogen than what is available to completely react.
Explanation:
To determine the limiting reactant between nitrogen gas (N2) and hydrogen gas (H2) in the synthesis of ammonia (NH3), we use the balanced chemical equation:
N2 + 3 H2 ->2 NH3
According to the equation, each mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia. Given the reaction mixture of 3.0 moles of N2 and 12.0 moles of H2, we compare the stoichiometric amounts needed for the reaction. The nitrogen gas would require 9.0 moles of hydrogen gas to fully react (3 moles N2 imes 3 moles H2/1 mole N2 = 9 moles H2). Since there are 12.0 moles of hydrogen gas available, hydrogen is in excess, and nitrogen is the limiting reactant.
How much heat (in joules) is required to raise the temperature of 30.0 kg of water from 15o C to 95o C?
Answer : The amount of heat required is, [tex]1.004\times 10^6J[/tex]
Explanation :
Formula used :
[tex]q=m\times c\times (T_{final}-T_{initial})[/tex]
where,
q = heat required = ?
m = mass of water = 30.0 kg = 3000 g
c = specific heat of water = [tex]4.184J/g^oC[/tex]
[tex]T_{final}[/tex] = final temperature = [tex]95^oC[/tex]
[tex]T_{initial}[/tex] = initial temperature = [tex]15^oC[/tex]
Now put all the given values in the above formula, we get:
[tex]q=3000g\times 4.184J/g^oC\times (95-15)^oC[/tex]
[tex]q=1004160J=1.004\times 10^6J[/tex]
Thus, the amount of heat required is, [tex]1.004\times 10^6J[/tex]
Final answer:
To raise the temperature of 30.0 kg of water from 15°C to 95°C, 10,041,600 joules of heat energy are required. This is calculated using the product of the mass of the water, the specific heat capacity of water, and the change in temperature.
Explanation:
The amount of heat transfer required to change the temperature of a substance can be calculated using the formula Q = mcΔT, where Q is the heat energy in joules, m is the mass of the substance in kilograms, c is the specific heat capacity (for water it's 4,184 J/kg/°C), and ΔT is the change in temperature in degrees Celsius.
For the given problem of raising the temperature of 30.0 kg of water from 15°C to 95°C, the temperature change (ΔT) is 95°C - 15°C = 80°C. The calculation would be as follows: Q = (30.0 kg) × (4,184 J/kg/°C) ×(80°C).
Calculation:
Q = 30.0 kg × 4,184 J/kg/°C * 80°CQ = 125,520 kg·°C ×J/kg/°CQ = 10,041,600 JTherefore, the heat required is 10,041,600 joules.
100. mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.0766 atm at 25.0 degree C . Calculate the molar mass of the protein. Be sure your answer has the correct number of significant digits.
Answer:
molar mass is [tex]6.39\times10^3\ g/mol[/tex]
Explanation:
Osmotic pressure is related with concentration as follows:
[tex]\pi =CRT[/tex]
Where, C is concentration or molarity , R is gas constant and T is temperature.
Osmostic pressure given is 0.0766 atm
R is [tex]0.0821 L \ atm \ K^{1}mol^{-1}[/tex]
T = 25 + 273 = 298 K
Rearrange the above equation to calculate concetration of the solution as follows:
C = P/RT
[tex]C=\frac{0.0766}{0.0821 \times 298} \\=0.00313\ M[/tex]
molarity = moles/volume in L
moles = molarity × volume in L
volume = 5.00 mL = 0.005 L
moles = 0.00313 × 0.005
=[tex]1.565 \times 10^{-5}[/tex]
[tex]molar\ mass=\frac{mass\ in\ g}{moles} \\=\frac{0.1\ g}{1.565\times 10^{-5}mol} \\=6.389\times 10^3\ g/mol\\[/tex]
Therefore, molecular mass of protein is [tex]6.39\times10^3\ g/mol[/tex]
When a variable is determined by a factor outside of the function or model being evaluated, it is said to be A. statistically insignificant. B. exogenous. C. endogenous. D. unexplained.
Answer:
The correct answer is B. exogenous
Explanation:
Let us try to describe exogenous and endogenous variables an exogenous variable value is influenced only by factors outside a model or system and is forced onto the model, while a change in an exogenous variable is known as an exogenous change. Also an endogenous variable is one whose value is influenced only by the system or model under study.
You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several different temperatures. The sphere can expand or shrink to any volume without changing the pressure of the gas inside. As a result of your experiment, you find that the volume (V) of the gas divided by its temperature (T) is always equal to 1.75. What would the volume (V) of the gas be at a temperature of 300K? (assume the unit for volume is liters) Show your work and answer the question with a clear statement. Show each step of your calculations for full points. After showing your calculations, answer the question with a clear statement.
Volume of the gas at 300K will be 525l itres.
Explanation:According to Charles' law, the volume of a gas is inversely proportional to its absolute temperature when the pressure of the gas is constant.
Here the V/T is given to be constant and equal to 1.75.
The temperature of the gas = T = 300K.
Let the volume of the gas be V liters.
So according to the question,
V / T = 1.75.
So,V / 300 = 1.75.
So, V = 300 × 1.75.
Or, V = 525 litres.
So, the volume of the gas at 300K will be 525 litres.
The Volume of the gas at 300K will be 525l liters.
Charles law:As per Charles' law, the volume of gas should be inversely proportional to the absolute temperature at the time when the pressure of the gas is constant.
Calculation of the volume of the gas:Here the V/T should be constant and equivalent to 1.75.
The temperature of the gas = T = 300K.
Also, we assume that the volume of the gas is V liters.
So,
V / T = 1.75.
V / 300 = 1.75.
V = 300 × 1.75.
V = 525 litres.
Find out more information about the Temperature here:https://brainly.com/question/7510619?referrer=searchResults
State the number of solutions for Matrix B. a. No Solution b. One Solution c. Infinitely Many Solutions
Answer:
C. Infinitely Many Solutions
Explanation:
No solution case : This is the case when all given variables are not equal to any constant, for example: there is one row of zeros in matrix e.g 0=3. matrix B don't have any zero row. So, Not True.
One Solution case: This is the case when all variables are independent variables like if they are equal to some constant. e.g x=1,y=2,z=4 , Matrix B have more than one variable in first row due to which it made equation look like x+y=-5. so matrix B can't have only one solution. So, Not True.
Infinitely Many Solutions case: when there is one or more variables which is not equal to any constant and acting as linearly dependent variable, then that matrix have infinite solutions. Matrix B have that variable which is linearly dependent as show in the attachment solution. So, True.
What common household element can, over time, reduce airflow, insulate components, reduce heat exchange or even cause the system to hang or reboot?
Answer:
The correct answer is Dust
Explanation
Dust is a dry dirt in powder form usually found on surfaces of items in a building, it comprises of very small particles of soil, sand and sometimes includes toxic substances, skin cells,bacteria, soil particles, particles of clothing material, tiny pieces of dead insects and pollen
Answer: Dust
Explanation:
Dust is a solid matter with fine particles, it mostly hangs in the atmosphere and are produced from various sources such as pollutions, loose soil which are lifted through aeolian process. Continuous exposure to dust in house holds or work place can make someone sick and affect one's health. Apart from that, it also reduces comfort and can even affect the efficient functioning of home or office appliances and gadgets.
A sample may contain any or all of the following ions: Hg22+, Ba2+, and Mn2+.
(a) No precipitate formed when an aqueous solution of NaCl was added to the sample solution.
(b) No precipitate formed when an aqueous solution of Na2SO4 was added to the sample solution.
(c) A precipitate formed when the sample solution was made basic with NaOH.
Which ion or ions are present in the sample solution? (Select all that apply.)
Mn2+ ions
Ba2+ ions
Hg22+ ions
Answer:
The ion present in the sample solution is Mn2+
Explanation:
(a) No precipitate formed when an aqueous solution of NaCl was added to the sample solution.
Most chlorides are quite soluble in water except for he H g 2 C l 2, that is an insoluble salt. Since no precipitation formed upon addition of NaCl, H g 2 + was not present in the sample.
(b) No precipitate formed when an aqueous solution of Na2SO4 was added to the sample solution.
The B a S O 4 is an insoluble salt too. Since no precipitation formed upon addition of N a 2 S O 4 , the ion B a 2 + was not present in the sample.
(c) A precipitate formed when the sample solution was made basic with NaOH.
As the M n ( O H ) 2 is insoluble in this last solution, the precipitate formed corresponds to B a S O 4 and H g 2 C l 2 compounds , therefore it can be concluded that the present ion in the sample solution is Mn+2.