Calculate 1/4+(-5/12)+(-2/3)

The width of the rectangle is 9 cm, and the length is 14 cm.

To find the width and length of the rectangle:

Let's assume that the width of the rectangle is x cm. According to the problem, the length of the rectangle is 5 cm more than its width, so the length would be x + 5 cm.

The perimeter of the rectangle is 46 cm. The formula for the perimeter of a rectangle is P = 2(w + l), where P is the perimeter, w is the width, and l is the length.

So, we can set up the equation: 46 = 2(x + (x + 5)).

Simplifying the equation gives us: 46 = 2(2x + 5).

Expanding the equation further gives us: 46 = 4x + 10.

Subtracting 10 from both sides of the equation gives us: 36 = 4x.

Dividing both sides of the equation by 4 gives us: x = 9.

Therefore, the width of the rectangle is 9 cm, and the length is 9 + 5 = 14 cm.

To find the width and length of the rectangle, set up an equation using the given information and solve for x. The width is 9 cm and the length is 14 cm.

To solve this problem, we can set up an equation using the information given. Let's assume the width of the rectangle is x cm. Since the length is 5cm more than the width, it will be x + 5 cm. The perimeter of a rectangle is found by adding all its sides, so we have:

2(x + x + 5) = 46

Simplifying this equation gives us:

4x + 10 = 46

Subtracting 10 from both sides:

4x = 36

Dividing both sides by 4:

x = 9

Therefore, the width of the rectangle is 9 cm and the length is 9 + 5 = 14 cm.

The solution set for the system of equations is (3, 2).

In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought

Given is the system of equations -

5x - 2y = 11

3x + 5y = 19

Multiply Eq.{1} by 3 and Eq.{2} by 5, we get -

15x - 6y = 33

15x + 25y = 95

Now, performing Eq(2) - Eq(1), we get -

15x + 25y - 15x + 6y = 95 - 33

31y = 62

y = 2

x = 11 + 2y/5

x = 15/5

x = 3

Therefore, the solution set for the system of equations is (3, 2).

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The required area of the regular quadrilateral is 9 square inches.

Given that,
The perimeter of a regular quadrilateral is 12 inches. What is its area is to be determined.

A quadrilateral is a four-sided shape, regular or nonregular.
Examples:- square, rectangle parallelogram etc.

Here,
A regular quadrilateral is a square.
the perimeter of the rectangle = 4 × side
12 = 4 × side
side = 12 / 4
Side = 3 inch
Area of the square = side²
Area of the square = 3²
Area of the square = 9 square inches

Thus, the required area of the regular quadrilateral is 9 square inches.

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To write a number in scientific notation, first, write a decimal point in the number so that there's only one digit to the left of the decimal point.

Next, count the number of places the decimal point would need to move to get back to the original number.

The number of spaces to get back to the original number is the exponent.

I think the answer would be -1 + 2

The repeating decimal as a fraction can be represented as [tex]\mathbf{\dfrac{1}{3}}[/tex]

A repeating decimal is known to be a continuous decimal expressing a number with an indefinite reoccurring part after the decimal point that is not zero.

From Farrah's math grade average score of 93.3%;

[tex]\mathbf{= \dfrac{3}{9}} \\ \\ = \mathbf{\dfrac{1}{3}}[/tex]

Check:

[tex]\mathbf{\dfrac{1}{3}}}[/tex]   in decimal results into a repeating decimal 0.33333333

Therefore, we can conclude that repeating decimal as a fraction is represented as  [tex]\mathbf{\dfrac{1}{3}}[/tex]

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Final answer:

The multiplicative inverse or reciprocal of the fraction 5/9 is 9/5, which is the result of flipping the numerator and denominator.

Explanation:

The multiplicative inverse, or reciprocal, of a fraction is another fraction in which the numerator and denominator are flipped. For the fraction 5 over 9, the multiplicative inverse is found simply by reversing the numerator and the denominator, turning it into 9 over 5.

To illustrate this with an example, let's consider the fraction ½. The reciprocal of ½ is 2, as their product equals 1 (1/2 x 2 = 1). Similarly, the reciprocal of 5/9 will be such that (5/9) x (9/5) = 1.

Hence, the reciprocal of 5/9 is 9/5.

E goes from (4,8) to (1,2) which equals a 1/4 scale factor ( put lower number over higher number so X = 1/4 and Y = 2/8 which reduces to 1/4)

 so H needs to be reduced by 1/4

8/4 = 2

 so new coordinate is (2,2)

 Answer is C

2/3 + 1/4 + 4/8 =

find least common denominator and rewrite the fractions

lets use 24: 24/3 = 8, 24/4 = 6, 24/8 = 3

 so 2/3 = 16/24

1/4 = 6/24

4/8 = 12/24

now add them together:

16/24 + 6/24 + 12/24 = 34/24 which becomes 1 and 10/24 reducing to  1 and 5/12