At what time the sum Rs. 5000 will be doubled at the interest
of 10% per annum?​

Answer:

As addition property of equality clearly states that if we add the same number to both sides of an equation, the sides remain equal.

Step-by-step explanation:

[tex]2x + 2y = 14[/tex]

[tex]-x + y = 5[/tex]    Add x in both sides (Addition Property of Equality)

[tex]2x + 2y = 14[/tex]

[tex]y = x + 5[/tex]    Multiply both sides by 2

[tex]2x + 2y = 14[/tex]

[tex]2y = 2x + 10[/tex]    Subtract 2x in both sides

[tex]+\left \{ {{2x + 2y=14} \atop {-2x + 2y=10}} \right.[/tex]       ∵adding both equation

[tex]4y = 24[/tex] divide both sides by 4

[tex]y = 6[/tex]

Put the value of y = 6 to the equation [tex]-x + y = 5[/tex]

[tex]-x + 6 = 5[/tex]  Subtract 6 from both sides

[tex]-x = -1[/tex]    Change the sign

[tex]x = 1[/tex]     

Keywords: Addition property of equality, reason, proof

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Answer:

Marked price is Rs. 53333.33 and the cost price is Rs. 42333.33.

Step-by-step explanation:

Let Rs. x and Rs. y are the cost price and marked price of the mobile set respectively.

Now, the man has a loss of Rs. 8000 after giving a 15% discount on the marked price.

Therefore, 15% of y is 8000 i.e. [tex]8000 = \frac{y\times 15}{100}[/tex]

⇒ y = Rs. 53333.33

Now, the man gained Rs. 3000 by selling the mobile set allowing 15% discount on the marked price.

Therefore, the mobile set has the cost price = x = Rs. [(53333.33 - 8000) - 3000] = Rs. 42333.33 (Answer)

Answer:

Step-by-step explanation:

percentage  spent on books = (325/2200) * 100

= 325/22 = 14.77%

Answer:

18 feet

Step-by-step explanation:

Given:

A cat is running away from a dog.

After 5 seconds it is 16 feet away from the dog

After 11 seconds  it is 28 feet away from the dog.

Let x represent the time in seconds that have passed and y represent the

distance in feet, so there are two points are formed such as (5, 16) and (11,28).

We will find the distance between dog and cat. by using distance formula of the two points.

[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex]

Now we substitute the given value in above equation.

[tex]d=\sqrt{(11-5)^{2}+(28-11)^{2} }[/tex]

[tex]d=\sqrt{(6)^{2}+(17)^{2} }[/tex]

[tex]d=\sqrt{36+289}[/tex]

[tex]d=\sqrt{325}[/tex]

[tex]d=18.08\ feet[/tex]

18.08 ≅ 18

So [tex]d=18\ feet[/tex]

Therefore the distance between dog and cat is 18 feet.

To find the linear equation for the distance between the cat and the dog, we calculate the slope with the given points and use it with one of the points to establish the equation y = 2x + 6. A graph can be drawn with the points (5, 16) and (11, 28) to visualize the cat's path.

The linear equation describing the distance the cat is from the dog in relation to time can be determined using the two given points: (5, 16) and (11, 28), where 'x' is the time in seconds and 'y' is the distance in feet.

We first find the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in the values we get:

m = (28 - 16) / (11 - 5) = 12 / 6 = 2

This means for each second that passes, the cat is 2 feet further away from the dog. Next, we use one of the points and the slope to write the equation in point-slope form. Using the point (5, 16) we have:

y - 16 = 2(x - 5)

Expanding and simplifying this equation gives us:

y = 2x + 6

This is the linear equation that describes the distance of the cat from the dog over time. To draw a graph, we plot the two points given and draw the line that passes through them, which will represent the cat's path. The slope of 2 indicates that for every 1 second, the distance increases by 2 feet.

Answer:

-24

Step-by-step explanation:

This is a simple multiplication problem. 8 times 3 is 24, and since one of the numbers is negative, the product (answer in multiplication) will be negative.

In multiplication and division of integers (positive and negative numbers), if the numbers have the same signs, the answer is ALWAYS positive, and if the numbers have different signs, the answer is ALWAYS negative.

Answer: -24

Step-by-step explanation: To multiply (-3)(8), it is important to understand that a negative times a positive is a negative so (-3)(8) is -24.

Answer:

most likely isosceles

Step-by-step explanation:

due to the fact that two angles are congruent and the other angle is probably not it would make it all isosceles triangle

A triangle with two 45-degree angles is a special type of triangle known as an isosceles triangle.

In a triangle, if two angles are congruent, then the opposite sides of those angles are also congruent. In an isosceles triangle, two sides are equal in length, and the angles opposite those sides are congruent. Since two angles of the triangle are 45 degrees each, their opposite sides are also equal in length, making it an isosceles triangle.

Answer:

48000

Step-by-step explanation:

12000 students

4%

1 =annually

12×4×1= 48000

Answer:12,000

Step-by-step explanation:can’t give you one cuz I’m doing this in mathxl :p

1 year = 12 months.

2 years = 12 x 2 = 24 months.

Multiply the number of times it sells out per month by the number of months:

7 x 24 months = 168 times.

Step-by-step explanation:

equation-

(x-3) (x-4) =

[tex] {x }^{2} - 3x - 4x + 12 = {x}^{2} - 7x + 12[/tex]

Given the roots 3 and 4 of a quadratic equation, and the leading coefficient 2, the quadratic equation can be derived as 2x^2 - 14x + 24.

To find a quadratic equation given its roots and leading coefficient, you use the factored form of a quadratic equation, x = (x - root1)(x - root2).  

Given that the roots are 3 and 4, the equation takes the form of x = (x - 3)(x - 4). When you multiply this out, you get x^2 - 7x + 12.

The problem also states that the leading coefficient is 2, so we multiply our obtained equation by 2 to get: 2x^2 - 14x + 24.

So, the requested quadratic equation is 2x^2 - 14x + 24.

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Answer:

My answer what I came up with is B And B

Answer:

≈ 12.5 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, - 11) and (x₂, y₂ ) = (- 1, - 5)

d = [tex]\sqrt{(-1-10)^2+(-5+11)^2}[/tex]

   = [tex]\sqrt{(-11)^2+6^2}[/tex]

   = [tex]\sqrt{121+36}[/tex]

   = [tex]\sqrt{157}[/tex] ≈ 12.5 ( to the nearest tenth )

To find a number that is 10 times greater than 7962, we can multiply.

7,962 * 10 = 79,620

79,620 is 10 times greater than 7,962.

Best of Luck!

Answer:

79,620

Step-by-step explanation:

7,962 (10) = 79,620

Answer: OC = πx4

Step-by-step explanation:

This question is incomplete, the correct question is

The diameter of a circle is 4 cm. Which equation can be used to find its circumference?

OC = πx2

OC= πx4

4

Answer,

Since the diameter is given as 4cm

Also,

The circumference of a circle OC = π x diameter

Therefore, OC = πx4

Here's how I'm assigning a different variable to the value of each digit:

10x + y, where x is the first digit, and y is the second digit (you can test if this equation works)

The sum of the digits is 1/5 the value of the number. Using the information, we can form the equation:

x + y = (1/5)(10x + y)

Simplify

x + y = 2x + (1/5)y

The tens digit is one less than the ones digit. Using this information, we can form the equation:

x = y - 1

Adding both sides by 1 gives

x + 1 = y

Substituting this into the y's the first equation gives:

x + x + 1 = 2x + (1/5)(x + 1)

Distribute and simplify

2x + 1 = 2x + (1/5)x + 1/5

Subtract both sides by 2x

1 = (1/5)x + 1/5

Subtract 1/5 from both sides

4/5 = (1/5)x

Multiply both sides by 5

4 = x

x = 4

Use this to solve for y

x + 1 = y

4 + 1 = y

y = 5

Thus, x = 4 and y = 5. The 2 digit number is XY, which is 45.

Let me know if you need any clarifications; this was a very interesting math problem to solve!

Answer:   The correct answer is:   [C]:  "  [tex]15^{(7/4)}[/tex] " .

____________________________________

Step-by-step explanation:

____________________________________

Note the property for square roots in exponential form:

_____________________________________

     →    [tex]\sqrt[a]{(b)^ c}[/tex]  ;  ↔  b[tex]b^{(c/a)}[/tex] ;

    { [tex]a\neq 0[/tex] ; [tex][a^{(b/c)}]\neq 0[/tex] ; [tex]c\neq 0[/tex]  .}.

_____________________________________

As such, given:

     →    [tex]\sqrt[4]{(15^7)}[/tex] ;  

  a = 15,  b = 7,  c = 4 .

     →    [tex]\sqrt[4]{(15^7)}[/tex] ;   ↔  [tex]15^{(7/4)}[/tex] ;

     →  which corresponds to:

_____________________________________

Answer choice:  [C]:  "  [tex]15^{(7/4)}[/tex] " .

_____________________________________

Hope this helps!

  Wishing you well in your academic endeavors!

_____________________________________

Answer:

[tex]m\angle BOC=30^o[/tex]

Step-by-step explanation:

step 1

Find the measure of angle COD

we know that

[tex]m\angle COF=m\angle COD+m\angle DOF[/tex] ---> by addition angle postulate

we have

[tex]m\angle COF=150^o[/tex] ----> given problem

[tex]m\angle DOF=90^o[/tex] ----> because AD is perpendicular to BF

substitute the given values

[tex]150^o=m\angle COD+90^o[/tex]

[tex]m\angle COD=150^o-90^o[/tex]

[tex]m\angle COD=60^o[/tex]

step 2

Find the measure of angle BOC

we know that

[tex]m\angle BOC+m\angle COD=90^o[/tex] ---> by complementary angles

we have

[tex]m\angle COD=60^o[/tex]

substitute

[tex]m\angle BOC+60^o=90^o[/tex]

[tex]m\angle BOC=90^o-60^o[/tex]

[tex]m\angle BOC=30^o[/tex]

short answer: 30 degrees :)

Answer:

C. [tex]y^2=9[/tex]

Step-by-step explanation:

1. [tex]y^2 = 9[/tex]

2. [tex]y = \frac{+}{}\sqrt{9}[/tex]

3. Equation solutions:

[tex]y_{1} = 3\\y_{2} = -3[/tex]

The number of adult tickets sold is 165 and number of students tickets sold were 35

Solution:

Let "a" be the number of adult tickets sold

Let "s" be the number of student tickets sold

Cost of 1 adult ticket = $ 50.00

Student tickets are 50% less than adult tickets

Cost of 1 student ticket = Cost of 1 adult ticket - 50 % of Cost of 1 adult ticket

[tex]\rightarrow 50.00 - 50 \% \text{ of } 50.00\\\\\rightarrow 50 - \frac{50}{100} \times 50\\\\\rightarrow 50 - 25 = 25[/tex]

Thus Cost of 1 student ticket = $ 25

Given that a concert venue can hold 200 people

So we get,

number of adult tickets sold + number of student tickets sold = 200

a + s = 200 ----- eqn 1

The venue was sold out and made a revenue of $9125 for one event

So we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of student tickets sold x Cost of 1 student ticket = $ 9125

[tex]a \times 50.00 + s \times 25 = 9125[/tex]

50a + 25s = 9125 ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "s"

From eqn 1,

a = 200 - s --- eqn 3

Substitute eqn 3 in eqn 2

50(200 - s) + 25s = 9125

10000 - 50s + 25s = 9125

-25s = 9125 - 10000

-25s = -875

Substitute s = 35 in eqn 3

a = 200 - 35

Thus the number of adult tickets sold is 165 and number of students tickets sold were 35

Answer:

The length of the total 8 pieces in 0.8 meters = 6.4 meters

How many pieces there are in the remaining 0.4 meter = 6.5

Step-by-step explanation:

0.8 x 8 = 6.4

9 meters - 6.4 meters = the remaining 2.6 meters

2.6 x 0.4 = 6 1/2 pieces of ribbon in 0.4 meters.

Answer:

Step-by-step explanation:

Final answer:

To simplify the given expression involving fractions and variables, multiply, divide, and subtract accordingly to obtain the simplified form. Therefore, the simplified expression is   [tex](9/4)x^2 - (1/25)y^2.[/tex]

Explanation:

The given expression is:

[tex]81/36 * x^2 - y^2/25[/tex]

To simplify this expression:

Multiply 81/36 which equals 9/4.

Then, divide [tex]x^2[/tex] by 4, and subtract [tex]y^2[/tex] divided by 25.

Therefore, the simplified expression is  [tex](9/4)x^2 - (1/25)y^2.[/tex]

Answer:

[tex]\large\boxed{y=-\dfrac{3}{4}x+\dfrac{29}{4}}[/tex]

Step-by-step explanation:

[tex]\text{Let}\\\\k:y=m_1x+b_1,\ l:y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\=================================[/tex]

[tex]\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\text{Calculate the slops:}\\\\(5,\ -1),\ (2,\ -5)\\\\m_1=\dfrac{-5-(-1)}{2-5}=\dfrac{-5+1}{-3}=\dfrac{-4}{-3}=\dfrac{4}{3}\\\\\text{Therefore}\\\\m_2=-\dfrac{1}{\frac{4}{3}}=-1\left(\dfrac{3}{4}\right)=-\dfrac{3}{4}\\\\\text{Put the value of slope and coordinates of the given point (-1, 8) }\\\text{to the equation of a line:}\\\\8=-\dfrac{3}{4}(-1)+b\\\\8=\dfrac{3}{4}+b\qquad\text{subtract}\ \dfrac{3}{4}\ \text{from both sides}\\\\7\dfrac{1}{4}=b\to b=\dfrac{29}{4}\\\\\text{Finally:}\\\\y=-\dfrac{3}{4}x+\dfrac{29}{4}[/tex]

Answer: The required probability is 0.004.

Step-by-step explanation:

Since we have given that

Number of pieces = 50

Number of defective pieces = 5

So, we need to draw 2 defective pieces.

So, the probability of drawing 2 defective pieces one after the other on the first and second samples would be

[tex]\dfrac{5}{50}\times \dfrac{4}{49}\\\\=\dfrac{20}{2450}\\\\=0.004[/tex]

Hence, the required probability is 0.004.

Final answer:

Calculating the probability of drawing two defective pieces sequentially from a set of 50 pieces with 5 defectives.

Explanation:

The probability of drawing 2 defective pieces one after the other without replacement:

Find the probability of drawing the first defective piece: 5/50 = 1/10.

Since the pieces are drawn without replacement, the probability of drawing the second defective piece after the first is: 4/49.

Multiply the probabilities: (1/10) * (4/49) = 4/245.

[tex]AB=BC=CD=AD = \sqrt{10}[/tex]

As all the sides have same length, ABCD is a square

Step-by-step explanation:

To prove ABCD a square we have to find the lengths of each side

So,

the distance formula will be used to find the lengths

The distance formula is:

[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Now,

[tex]AB = \sqrt{(2-1)^2+(0-3)^2}\\= \sqrt{(1)^2+(-3)^2}\\=\sqrt{1+9}\\=\sqrt{10}[/tex]

[tex]BC = \sqrt{(5-2)^2+(1-0)^2}\\= \sqrt{(3)^2+(1)^2}\\=\sqrt{9+1}\\=\sqrt{10}[/tex]

[tex]CD = \sqrt{(4-5)^2+(4-1)^2}\\= \sqrt{(-1)^2+(3)^2}\\=\sqrt{1+9}\\=\sqrt{10}[/tex]

[tex]AD = \sqrt{(4-1)^2+(4-3)^2}\\= \sqrt{(3)^2+(1)^2}\\=\sqrt{9+1}\\=\sqrt{10}[/tex]

we can see that

[tex]AB=BC=CD=AD = \sqrt{10}[/tex]

As all the sides have same length, ABCD is a square

Keywords: Distance formula, square

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Answer:

option D. 20 cm

Step-by-step explanation:

step 1

Find the volume of the water

The volume of the water is equal to

[tex]V=LWH[/tex]

we have

[tex]L=60\ cm\\W=40\ cm\\H=50\ cm[/tex]

substitute

[tex]V=(60)(40)(50)[/tex]

[tex]V=120,000\ cm^3[/tex] ---> volume of water

step 2

Find the deep of the water, if the tank is returned to its horizontal position

we have

[tex]V=120,000\ cm^3[/tex]

[tex]L=100\ cm\\W=60\ cm\\H=?\ cm[/tex]

where

H is the deep of the water

substitute in the formula of volume

[tex]120,000=(100)(60)(H)[/tex]

solve for H

[tex]120,000=6,000)(H)[/tex]

[tex]H=20\ cm[/tex]

Answer:

31

Step-by-step explanation:

[tex]\bf \displaystyle\sum\limits_{j=1}^{10}~2j+7\implies \displaystyle\sum\limits_{j=1}^{10}~2j+\displaystyle\sum\limits_{j=1}^{10}~7\implies 2\displaystyle\sum\limits_{j=1}^{10}~j+\displaystyle\sum\limits_{j=1}^{10}~7 \\\\\\ 2\cdot \cfrac{10(10+1)}{2}~~+~~(10)(7)\implies 2\cdot 55+70\implies 110+70\implies 180[/tex]

Answer:ioj;i;

Step-by-step explanation:

fkuyhjgyhkuyh

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Substitute 1 in everywhere you see 'x'

2(1)^3 - 3(1)^2 - 18(1) + 8

Solve:

f(1) = -11

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Final answer:

To evaluate the function f [tex](x) = 2x^3 - 3x^2 - 18x + 8[/tex] at x=1, substitute 1 for every instance of x in the function and simplify to get f(1) = -11.

Explanation:

The question appears to be a math problem where the student is asked to evaluate a function at a specific input. Specifically, the function given is  [tex]f(x) = 2x^3 - 3x^2 - 18x + 8[/tex] and the student has been asked to evaluate this function when x is equal to 1. To find f(1), we replace every instance of x in the function with 1.

So, f(1) = [tex]2(1)^3 - 3(1)^2 - 18(1) + 8[/tex]= 2(1) - 3(1) - 18 + 8 = 2 - 3 - 18 + 8 = -11.

Thus, f(1) evaluates to -11.

Hope it helps u..........

Answer:

Step-by-step explanation: